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Published byJulian McKnight Modified over 3 years ago

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Houston, We Have a Problem! By Leena Bakshi and my group members

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Task 1: Varying Variables! FInitial Velocity: v, the initial velocity of each rocket. These values are given. Rocket #1: has an initial velocity of 250 m/s, but must be launched at ground zero. Rocket #2 has an initial velocity of 90 m/s, but can be launched at an initial height on 300 meters. FAcceleration: a, -9.8 m/s 2 : the force of gravity acting on the rocket. FTime: t, the time it takes to reach the final height. FInitial Height: h 0, These values are given. Rocket #1 = 0, Rocket #2 = 300 meters FFinal Height: h, the final height of each rocket. This value is given, since the two rockets need to reach a final height of 63,198 meters. FInitial Velocity: v, the initial velocity of each rocket. These values are given. Rocket #1: has an initial velocity of 250 m/s, but must be launched at ground zero. Rocket #2 has an initial velocity of 90 m/s, but can be launched at an initial height on 300 meters. FAcceleration: a, -9.8 m/s 2 : the force of gravity acting on the rocket. FTime: t, the time it takes to reach the final height. FInitial Height: h 0, These values are given. Rocket #1 = 0, Rocket #2 = 300 meters FFinal Height: h, the final height of each rocket. This value is given, since the two rockets need to reach a final height of 63,198 meters.

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Task 2: Algebraic Evidence FRocket #1: 0.5at 2 + vt + h 0 0.5(-9.8)( t 2 ) + (250)(t) + (0) = 63,198 meters (simplified): 63,198 = 250t-4.9 t 2 This is false: The maximum for this equation is seconds and can only reach a maximum height of meters. FRocket #1: 0.5at 2 + vt + h 0 0.5(-9.8)( t 2 ) + (250)(t) + (0) = 63,198 meters (simplified): 63,198 = 250t-4.9 t 2 This is false: The maximum for this equation is seconds and can only reach a maximum height of meters.

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FRocket #2: 0.5at 2 + vt + h 0 0.5(-9.8)( t 2 ) + (90)(t) + (300) = 63,198 meters This rocket only reaches a maximum of meters. Again, this will reach a false result and will not reach the moon. FRocket #2: 0.5at 2 + vt + h 0 0.5(-9.8)( t 2 ) + (90)(t) + (300) = 63,198 meters This rocket only reaches a maximum of meters. Again, this will reach a false result and will not reach the moon. Task 2: Algebraic Evidence

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Task 3: After 5 seconds… FRocket #1: F0.5at 2 + vt + h 0 F0.5(-9.8)( 5 2 ) + (250)(5) + (0) = final height F meters FRocket #1: F0.5at 2 + vt + h 0 F0.5(-9.8)( 5 2 ) + (250)(5) + (0) = final height F meters

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FRocket #2: F0.5at 2 + vt + h 0 F0.5(-9.8)( 5 2 ) + (90)(5) + (300) = final height F627.5 meters FRocket #2: F0.5at 2 + vt + h 0 F0.5(-9.8)( 5 2 ) + (90)(5) + (300) = final height F627.5 meters Task 3: After 5 seconds…

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Conclusions FThese amateur rockets will not make it to the moon. FIf the initial velocity on rocket one is modified, it can be a viable rocket. FInitial velocity affects the final height more than the initial height. FThese amateur rockets will not make it to the moon. FIf the initial velocity on rocket one is modified, it can be a viable rocket. FInitial velocity affects the final height more than the initial height.

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Video: Rocket Launch to Mars

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