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Learner-Centered Learning Environment Science and Technology 5 (Physics) Name:__________________________ Year and Section: ______

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A very strong typhoon landed on Pangasinan and destroyed most parts of the province causing flood and other serious damages. The whole province has been put under state of calamity and the Armed Forces of the Philippines requested volunteers to help them in distributing relief goods to the typhoon victims. Mark, being a Lasallian who contributes to the society, volunteered to join the military in distributing supplies to the residents of the affected areas. He is tasked to drop the relief goods to the rooftops of the victims. When is the perfect timing Mark must release the relief goods, so that they arrive precisely at the survivors location if the helicopter is moving at a constant speed?

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When is the perfect timing Mark must release the relief goods so that they arrive precisely at the survivors location? Put a check mark on your choice/s. Be ready to explain your choice/s. Release the goods in advance whatever the helicopters speed. Release the goods right above the location. I have another idea:_______ ___________ ___________ Release the goods in advance depending on helicopters speed. Worksheet #1: Mind Map

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Worksheet #2: Thinking About Your Choice Why did you choose that option? ________________ ________________ ________________ What factors should Mark consider in dropping the relief goods? Why? ________________ ________________ ________________ ________________ ________________ Draw the helicopter (according to your answer) when the goods are to be dropped off. And using broken lines, draw how you visualize the path of the goods going to the flood victims

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Worksheet #3: Word Search Before we clarify our ideas, let us define first some terms related to projectile motion. Look for a partner, and together, find the meaning of the terms listed below using this dictionary.this dictionary Projectile Trajectory Range Altitude

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After defining terms related to Projectile Motion, let us discover the three types of projectiles by viewing this Glenbrook page. This website will help us understand the nature of a projectile.this Glenbrook page Based on what you have read, what are the three types of projectiles? Give an illustration for each type. _____________________________________________ A projectile is an object upon which the only force is ___________. Worksheet #4: The Projectile

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Worksheet #5: Galileos Experiment Does an object falling straight down reach the ground faster than one that also has lateral motion? Let us answer this question by performing Galileos Experiment. When the page pops on your screen, click Projectiles and follow the procedures.Galileos Experiment Now, crumple two sheets of pad paper. Drop the two crumpled papers from the same heights; one must be thrown straight down and the other one must be thrown horizontally. 1.Did you get the same result as of Galileos experiment? __________ 2.Why do you think this happened? _____________________________ _____________________________ _____________________________ What did you learn from Galileos experiment? ___________________ ___________________ ___________________ ___________________ ___________________

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Worksheet #6: The Greatest Range Let us now focus on range traveled by a projectile. Click this interactive page and answer the guide questions after filling-up the table below: interactive page Set the height of the platform at zero and the launching speed at 50 m/s. Determine the range for the following projection angles: Launching Angle Range 15 O 30 O 45 O 60 O 75 O Guide Questions: 1.To which launching angle did the greatest range occur? _____________ 2.What happens as you increase the launching angle? ________________________ ________________________ ________________________ ________________________ ________________________ ________________________ ________________________ ________________________

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Worksheet #7: Formula Hunt Form a group of five and brainstorm to determine the formula of the quantities below based on their descriptions. QuantityDescriptionFormula Vertical velocity component (V y ) This is equal to the initial velocity multiplied to the sine of the launching angle. Horizontal velocity component (V x ) This is equal to the initial velocity multiplied to the cosine of the launching angle. Maximum Height Reached (d y ) This is equal to the square of the vertical velocity component divided by twice acceleration due to gravity. Time of Flight (t)This is equal to twice the vertical velocity component divided by acceleration due to gravity. Range (R)This is equal to the horizontal velocity component times the time of flight

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Worksheet #8: Group Guided Practice With your group mates, answer the following problem. A bullet is fired from a gun mounted at an angle of 60 degrees. If the muzzle velocity is 400 m/s. Calculate: Vertical velocity component Horizontal velocity component Maximum height reached Time of flightRange

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Worksheet #9: Independent Practice Individually, answer the following problem. Show complete solution. A ball is thrown horizontally from a height of 5.50 m with a velocity of 25.0 m/s. a.How long will it take the ball to reach the ground? b. At what horizontal distance from the point of release will it strike the ground?

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Worksheet #10: A View From The Top Going back to the situation given at the beginning of this module, can you now identify the quantities needed by Mark to estimate when is the perfect timing he must release the relief goods, so that they arrive precisely at the survivors location ? The needed quantities are: _______________________ _______________________ _______________________ It is now time for us to answer the problem! Show an organized solution. The helicopter is flying horizontally at an altitude of 235 m with a speed of 72.5 m/s. When is the perfect timing Mark must release the relief goods so that they arrive precisely at the survivors location?

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Worksheet #11: Quiz A 1. How many items were you able to answer correctly? _____ 2. Which item/s did you find difficult? Why? _______________________________________________________________ _______________________________________________________________ _______________________________________________________________ _______________________________________________________________ 3. What should you remember in order to answer this correctly next time? _______________________________________________________________ _______________________________________________________________ _______________________________________________________________ Now that we have done some guided and independent practices, its time for us to have a short quiz. Ready?! Take the QUIZ now!QUIZ

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Worksheet #12: Quiz B Kevin Mirus created a quiz which we can definitely answer. Click his page and show your organized solution here. Good luck!his page a.b.c.d

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Worksheet #13: Reflective Log Use complete sentences in answering the following questions: Which of the quantities learned in this module is the most difficult to solve? Why? __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ How can I make the solving easier next time? __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ What is the benefit of knowing how to solve quantities involving projectile motion? __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________ __________________

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It is now time to create your own WORD PROBLEM. You will need a ball pen and a bond paper in writing the word problem. We will grade your output using the RUBRIC on the next page RUBRIC WHAT TO DO? Create a word problem that would reflect your daily experiences in work, home, school, etc. This word problem should have a solution that would use the skills on projectile motion you have learned from this LCLE module Final Output

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Rubric We will grade your output using the rubric below. The perfect score is ten (10) points. Criteria for Scoring ExcellentDevelopingBeginning The Word Problem The problem can be solved using skills related to projectile motion and the problem reflects daily experiences. (3 - 4) The problem can be solved using skills related to projectile motion but the problem doesnt reflect daily experiences. (1 - 2) The problem cannot be solved using skills related to projectile motion. (0) The Solution The solution is step- by-step and the final answer is correct. (3 - 4) The solution is not step-by-step but the final answer is correct. (1 - 2) The solution is not step-by-step and the final answer is wrong. (0) Grammar The sentences are easily understood and there are no grammatical errors. (2) The sentences can be understood but with some grammatical errors. (1) The sentences cannot be understood at all. (0)

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Projectile Motion Quiz DIRECTION. Read each item carefully and choose the correct answer for each question. Good luck! Lets START now!START

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Question #1 Joseph kicks a soccer ball 12 m/s at an angle of 30 degrees above the horizontal. What is the horizontal velocity component of the soccer ball? a.6.0 m/s6.0 m/s b m/s10.39 m/s c.360 m/s360 m/s d.720 m/s720 m/s

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Incorrect! As we have discussed, the horizontal velocity component is equal to the initial velocity multiplied to the cosine of the launching angle. You probably used the wrong formula. Go back and compute again. Go back

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Correct! The horizontal velocity component is equal to the initial velocity multiplied to the cosine of the launching angle. Proceed to Question #2Question #2

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Joseph kicks a soccer ball 12 m/s at an angle of 30 degrees above the horizontal. What is the vertical velocity component of the soccer ball? a.6.0 m/s6.0 m/s b m/s10.39 m/s c.360 m/s360 m/s d.720 m/s720 m/s

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Something is Wrong! Havent we mentioned that the vertical velocity component is equal to the initial velocity multiplied to the sine of the launching angle? You probably used the wrong formula. Go back and compute again. Go back

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Correct! The vertical velocity component is equal to the initial velocity multiplied to the sine of the launching angle. Proceed to Question #3Question #3

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Joseph kicks a soccer ball 12 m/s at an angle of 30 degrees above the horizontal. What is the ball's maximum height? a.0.61 m0.61 m b.1.06 m1.06 m c.1.84 m1.84 m d.5.51 m5.51 m

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Very Good! The maximum height reached by the projectile is equal to the square of the vertical velocity component divided by twice acceleration due to gravity. You can now proceed to Question #4. Question #4

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Oooppss… Something went wrong on your computation! The maximum height reached by the projectile is equal to the square of the vertical velocity component divided by twice acceleration due to gravity. Go backGo back and try solving it again.

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Question #4 Joseph kicks a soccer ball 12 m/s at an angle of 30 degrees above the horizontal. How long is the soccer ball in the air? a.0.61 s0.61 s b.1.06 s1.06 s c.1.22 s1.22 s d.2.12 s2.12 s

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Excellent! Nice job! The time of flight is equal to twice the vertical velocity component divided by acceleration due to gravity. Proceed now to the last question.last question

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Oh no! You probably used the wrong formula. The time of flight is equal to twice the vertical velocity component divided by acceleration due to gravity. Go backGo back and check your calculation.

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Question #5 Joseph kicks a soccer ball 12 m/s at an angle of 30 degrees above the horizontal. What is the ball's maximum range? a m0.732 m b m1.268 m c.7.32 m7.32 m d m12.68 m

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Yeeha! Woohoo! You have reached the end of the quiz. Congratulations! You may now go back to your LCLE module.LCLE module Always remember that the range of the projectile is equal to the horizontal velocity component times the time of flight.

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Nope! Please double check the formula you used. The range of the projectile is equal to the horizontal velocity component times the time of flight. Go backGo back and check your computation.

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