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Learning with Purpose February 19, 2013 Learning with Purpose February 19, 2013 22.322 Mechanical Design II Spring 2013.

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Presentation on theme: "Learning with Purpose February 19, 2013 Learning with Purpose February 19, 2013 22.322 Mechanical Design II Spring 2013."— Presentation transcript:

1 Learning with Purpose February 19, 2013 Learning with Purpose February 19, Mechanical Design II Spring 2013

2 Learning with Purpose February 19, 2013 Spur gears teeth are parallel to the axis of the gear. Simplest and least expensive form of gear to make. Spur gears can only be meshed if their axes are parallel. A spur gearset can be 98 to 99% efficient (Power Out/Power In). Lecture 10 Gear Types

3 Learning with Purpose February 19, 2013 Helical gears are ones in which the teeth are at a helix angle with respect to the axis of the gear. Helical gears are quieter and smoother than spur gears because of the gradual contact between the angled surfaces as the teeth mesh together. They are better suited for applications of high speed, large power transmission, or where noise abatement is important. A helical gearset will be 96 to 98% efficient due to the sliding friction along the helix angle. Helical gears also have a reaction force along the axis of the gear and so they require thrust and radial bearings. Lecture 10 Gear Types

4 Learning with Purpose February 19, 2013 When a pair of meshing helical gears are mounted on parallel shafts, they must be of opposite hand. When meshing helical gears are mounted on nonparallel shafts, they are known as crossed helical gears Crossed helical gears are only 50 to 90% efficient. Herringbone gears are two helical gears of identical pitch and diameter but of opposite hand on the same shaft. There is a cancellation of the thrust load and so no thrust bearing is needed. This type of gear is expensive. Lecture 10 Gear Types Side-thrust of one half is balanced by that of the other half

5 Learning with Purpose February 19, 2013 A worm gear has one tooth wrapped continuously around its circumference (similar to a screw thread). A large speed ratio (200 to 1) could not be reasonably achieved in one reduction because of the size of the gear required. If a spur gear pinion had 20 teeth, the larger spur gear would have 4000 teeth. A better solution is to use a worm gear. They are designed not to backdrive and can only be driven from the worm. Lecture 10 Gear Types Driving Driven

6 Learning with Purpose February 19, 2013 A rack and pinion has teeth that are trapezoids but are still involutes (no slipping). They are typically used in steering of automobiles. Lecture 10 Gear Types

7 Learning with Purpose February 19, 2013 Bevel gears are based on rolling cones and are used for non- parallel intersecting shafts Lecture 10 Gear Types The advantages and disadvantages of straight bevel and spiral bevel gears are similar to those of the spur and helical gears. Straight bevel gearsSpiral bevel gears

8 Learning with Purpose February 19, 2013 Hypoid gears are used if the axes between the gears are non- parallel and nonintersecting. They are based on rolling hyperboloids of revolution. Lecture 10 Gear Types Be able to identify different types of gears on the final exam!

9 Learning with Purpose February 19, 2013 Two gears can mesh if and only if they have the same circular pitch or diameteral pitch Lets consider the motion of point A for the following gears Lecture 10 Simple Gear Trains

10 Learning with Purpose February 19, 2013 Lecture 10 Simple Gear Trains A single gearset of spur, helical, or bevel gears is usually limited to a ratio of about 10:1 because of cost, size, manufacturing, and packaging.

11 Learning with Purpose February 19, 2013 a) Two spur gears are meshed together. The pinion has 15 teeth while the gear has 60 teeth. If the pinion is driven at 100 rpm, what is the speed of the gear? Lecture 10 Example N1 = 15 (input)N2=60 (output)Assume an external mesh 1/ 2) = (-N2/N1) = (-60/15) = -4 2 = ( 1/-4) 2 = 100 rpm/-4 = -25 rpm b) If the gear is driven at 100 rpm what is the speed of the pinion? N1 = 60N2=15 1/ 2) = (-15/60) = -1/4 2 = = -4(100 rpm) = -400 rpm What is the angular velocity of the gear in part b? 1 = 100 rot/min * (2 rad/1 rot) * (1 min/60 sec) = rad/s


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