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7.4B HW Answers. 2. Jose has $2.45 in nickels and dimes. He has ten more nickels than dimes. How many of each does he have? 0.05n + 0.10d = 2.45 n = d.

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Presentation on theme: "7.4B HW Answers. 2. Jose has $2.45 in nickels and dimes. He has ten more nickels than dimes. How many of each does he have? 0.05n + 0.10d = 2.45 n = d."— Presentation transcript:

1 7.4B HW Answers

2 2. Jose has $2.45 in nickels and dimes. He has ten more nickels than dimes. How many of each does he have? 0.05n d = 2.45 n = d (d + 10) + 10d = 245 5d d = d + 50 = d = 195 d = 13 = = 25 5n + 10d = 245

3 3. A jar filled with only dimes and quarters contains a total of 59 coins. The value of all the coins in the jar is $9.65. How many quarters are in the jar? 0.10d q = 9.65 d + q = 59 (–10) 10d + 25q = d–10q = q = 25 15q = 375

4 4. Ernie has $3.65 in nickels and dimes. He has 13 more nickels than dimes. How many of each coin does he have? 0.05n d = 3.65 n = d (d + 13) + 10d = 365 5d d = d + 65 = d = 300 d = 20 = = 33 5n + 10d = 365

5 5. A jar filled with only nickels and quarters contains a total of 65 coins. The value of all the coins in the jar is $9.65. How many quarters are in the jar? 0.05n q = 9.65 n + q = 65 (–5) 5n + 25q = n – 5q = q = 32 20q = 640

6 6. Tickets to a local movie were sold at $6.00 for adults and $4.50 for students. If 210 tickets were sold for a total of $1,065, how many student tickets were sold? 6a s = 1065 a + s = 210 (–600) 600a + 450s = a–600s = s = s =

7 7. Tickets to a play were sold for $25 for adults and $15 for children. If 441 tickets were sold for a total of $8415, how many children tickets were sold? 25a + 15c = 8415 a + c = 441 (–25) 25a + 15c = a –25c = c = c = -2610

8 8. The Steele Canyon ASB sold advance tickets to the dance for $4 per ticket. Anyone who attended and purchased their ticket at the door had to pay $5 a ticket. A total of 480 students attended the dance and ASB earned $2100. How many students bought tickets at the door? 4a + 5d = 2100 a + d = 480 (–4) 4a + 5d = a – 4d = d = 180

9 9. Altogether 292 tickets were sold for a high school basketball game. An adult ticket costs $3 and a student ticket costs $1. Ticket sales were $470. How many of each type of ticket were sold? 3a + 1s = 470 a + s = 292 (–1) 3a + s = 470 -a – s = a = 89 2a = 178 s = s = 292


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