Presentation on theme: "ELECTRICAL APPLIANCES"— Presentation transcript:
1 ELECTRICAL APPLIANCES Our home is full of electrical appliances. They change electricity into a more useful form of energy.Some appliances use more energy than others – their POWER RATING is higher.Plugs are fitted with a fuse to protect the flex connected to the appliance. As a general rule a 3A fuse is fitted for appliances that use up to 700W and a 13A fuse is fitted for appliances that use more than 700W.
2 The table contains some general information: ApplianceEnergy changeFlex 2/3 corePower rating (W)Fuse (A)Clock2103Table lamp100T.V.25013Hairdrier1000Iron1200Kettle2000Fire3000Cooker11500
3 FUSESFuses are used to limit the current flowing through a circuit or into an appliance. A fuse will melt when the current flowing through it exceeds the rating of the fuse. This protects the flex from overheating which could result in a fire. The circuit is then broken and the flow of current stops.
4 HUMAN CONDUCTIVITYThe human body is a conductor of electricity. Water (moisture) increases the body’s ability to conduct.
5 EARTH WIREThe earth wire is a safety feature which prevents the metal casing of an appliance becoming dangerous to touch when a fault occurs. A large current will flow through the earth wire and the fuse will melt, protecting the appliance.
6 CIRCUIT BREAKERThe circuit breaker is an absolutely essential device in the modern world, and one of the most important safety mechanisms in your home. Whenever electrical wiring in a building has too much current flowing through it, these simple machines cut the power until somebody can fix the problem.
7 DOUBLE INSULATION Double insulated appliances If you are fitting a plug to a double insulated appliance (labelled with the double insulated symbol), you should not have an earth conductor in your flex.
8 3 – PIN PLUG Know colours and names of each wire. Note how outer insulation is secured by cable grip.
9 ELECTRIC CHARGEA current of electricity is a steady flow of electrons. When electrons move from one place to another, round a circuit, they carry electrical energy from place to place like marching ants carrying leaves. Instead of carrying leaves, electrons carry a tiny amount of electric charge.Charge is calculated using:QQ = ItIt
10 MEASURING CURRENT 1LEARNING To build a series circuit and measure the INTENTION current at different points in the circuit.APPARATUS: power supply, 2 lamps, connecting leads, switch and ammeter...CABMETHOD: Build circuit and measure current at points A, B and C
11 POSITION CURRENT (A) A B C RESULTS: CONCLUSION: Current is the same at all points in a series circuit.IA = IB = IC
12 MEASURING VOLTAGEL. INT To build a series circuit and measure the voltage across L1, L2 and Vs.APPARATUS: power supply, 2 lamps, connecting leads, switch and voltmeter+Vs-L1L2METHOD: Build circuit and measure voltage across L1, L2 and Vs.
13 POSITION VOLTAGE (V) L1 L2 Vs RESULTS: CONCLUSION: The supply voltage equals the sum of the voltages across the 2 lampsVs = V1 + V2
14 CHANGING THE CURRENTL. INT. To investigate what happens to the current when components called resistors are placed in a circuit.APPARATUS: power supply, lamp, resistors with different values, connecting leads, switch and ammeter.Vs-+AMETHOD: Build circuit using smallest resistor and measure corresponding current. Repeat for other resistors.
15 RESISTOR RESISTANCE ( ) CURRENT (mA) A 10 B 33 C 47 D 100 RESULTS: ( )CURRENT(mA)A10B33C47D100CONCLUSION:As the resistance increases the current decreases.
16 VOLTAGE, CURRENT & RESISTANCE L. INT. To find the relationship between voltage, current and resistance.APPARATUS: power supply, resistors, connecting leads, switch, ohmmeter, voltmeter and ammeter.Vs+-ACircuit 1VCircuit 2METHOD: Measure value of resistors using circuit 1. Put smallest resistor into circuit 2, measure current and voltage. Repeat for other resistors.
17 RESULTS:ResistorR ( )V (V)I (A)V/IABCDCONCLUSION:V = I x R
18 RESISTANCE OF A TORCH BULB L. INT. To investigate how the resistance of a torch bulb varies when the brightness changesAPPARATUS: power supply, bulb, voltmeter, ammeter, connecting leads.METHOD: Build circuitSet supply at 2vMeasure current & voltageRecord in table & repeat for different voltagesVs+-AV
19 2 0.71 0.51 1.4 4 6 8 10 12 RESULTS: CONCLUSION: POWER SUPPLY (v) Voltage across bulb (V)Current (A)Resistance ( )20.710.511.44681012CONCLUSION:
20 RESISTANCE OF A THERMISTOR A thermistor is a temperature dependent resistor.L. INT. To find out how the thermistor varies with temperatureAPPARATUS: thermistor, ohmmeter, hot & cold waterMETHOD: (i) connect thermistor to ohmmeter(ii) place thermistor in cold water, record resistance(iii) place thermistor in hot water, record resistanceRESULTS:CONCLUSION:WaterResistance ( )ColdHotAs the temperature increases the resistance decreases.
21 RESISTANCE OF AN LDR An LDR is a light dependent resistor. Light level L. INT. To find out how the LDR varies with lightAPPARATUS: LDR, ohmmeter,METHOD: (i) connect LDR to ohmmeter(ii) place LDR in the dark, record resistance(iii) place LDR in the light, record resistanceRESULTS:CONCLUSION:Light levelResistance ( )DarkLightAs the light level increases the resistance decreases.
22 POWER, ENERGY & TIMETo find the ENERGY used by an electrical appliance we need to know the POWER RATING of the appliance and the TIME the appliance is on. The energy can be found by multiplying the power by the time:-Where E = energy (J)P = power (W)T = time (s)E = P x T
23 POWER , CURRENT & VOLTAGE LEARNING To investigate the relationship between POWER, INTENTION CURRENT & VOLTAGE.APPARATUS: power supply, lamps ( different power ratings ), ammeter, voltmeter & connecting leads.VsMETHOD: Build circuit using 24W lamp. Switch on and record current and voltage. Repeat for 36W lamp.+-AV
24 24 12 2 36 3 48 RESULTS: LAMP RATING (W) VOLTAGE (V) CURRENT (A) CURRENT X VOLTAGE2412236348CONCLUSION: By comparing the first and last column we have shown that the POWER equals the CURRENT multiplied by the VOLTAGE.P = I x V
25 MEASURING CURRENT 2LEARNING To build a parallel circuit and measure the INTENTION current at different points in the circuit.APPARATUS: power supply, 2 bulbs, connecting leads, switch and ammeter..+ -.ABCMETHOD: Build circuit and measure current at points A, B and C
26 POSITION CURRENT (A) A 0.24 0.16 B 0.12 0.05 C 0.12 0.11 RESULTS: BCCONCLUSION: the current at A equals the sum of the currents at B and CIA = IB + IC
27 MEASURING VOLTAGE 2LEARNING To build a parallel circuit and measure the INTENTION voltage across bulbs 1 & 2 and VsAPPARATUS: power supply, 2 bulbs, connecting leads, switch and voltmeter.VsMETHOD: Build circuit and measure voltage across both lamps.
28 supply voltage 5V bulb 1 bulb 2 RESULTS: CONCLUSION: Supply voltage equals the voltage across bulb 1 which equals the voltage across bulb 2Vs = V1 = V2
29 FAULT FINDINGTwo common electrical faults are ‘open circuits’ and ‘short circuits’. As every electrical component, from a lamp to a piece of wire, has a resistance, we can use this knowledge to identify such faults using an ohmmeter.OPEN CIRCUIT: the ohmmeter reads infinity as this is the result of a broken wire or a burnt out element.SHORT CIRCUIT: the ohmmeter reads a value that is less than expected for that component, as it’s the result of a touching wire.
30 RESISTANCE IN SERIESLESRNING To investigate how the individual resistors INTENTION compare with the total resistance in a series circuitAPPARATUS: resistors, ohmmeter & connecting leadsMETHOD: measure each resistor individually connect them in series measure total resistanceRESULTSCONCLUSION:RT = R1 + R2
31 RESISTANCE IN PARALLEL LEARNING To investigate how the individual resistors INTENTION compare with the total resistance in a parallel circuitAPPARATUS: resistors, ohmmeter & connecting leadsMETHOD: measure each resistor individually connect them in parallel measure total resistanceRESULTSCONCLUSION:1/RT = 1/R1 + 1/R2
32 CONSUMER UNITThe consumer unit contains the fuses or circuit breakers that protect the mains wiring.
33 Kilowatt-hourElectricity companies charge their customers for each unit of electricity used. 1 unit of electricity is equal to 1Kilowatt-hour (1KWh), which is the amount of energy a 1KW appliance uses in 1 hour. It can be calculated using E = P x t. If power is in KW and time in hrs then E will equal the number of units used.
34 RING MAINThe power sockets in a house are connected by means of a ring circuit. There are 2 paths to each socket which means half the current in 1 path and half in the other. The cables are thinner and therefore cheaper and less heat is produced in them.
35 ELECTROMAGNETAn electromagnet is simply a coil of wire which is wrapped around a soft iron core. When the wire is connected to a power source a magnetic field is created and the iron core acts like a permanent magnet. The strength of an electromagnet can be increased by using more turns of wire or a larger current.
36 ELECTRIC MOTORWhen a current flows along a wire which is in a magnetic field, the wire experiences a force, causing it to move (see crocodile physics).Rotation of motor can be changed by changing the direction of current or the direction of the magnetic field.Commutator reverses current; multi-segment commutators give smoother rotation; brushes allow current to flow into commutator.