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UNIT III LECT BASIC DEFINITIONS 2PRINCIPLES OF PHOTOMETRY 3LUMMER – BRODHUN PHOTOMETER 4PROBLEMS PH 0101 UNIT- 3 LECT - 1

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UNIT III LECT - 12 PHOTOMETRY Introduction : The light emitted or reflected by the objects can be measured in comparison with a standard source. The branch of optics which deals with the measurement of light is known as Photometry. (Photo means light and metry means measurement).

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UNIT III LECT - 13 BASIC DEFINITION : Luminous Flux (F) : The amount of light energy radiated from a source or an illuminating object in all directions per second is known as luminous flux. It is denoted by the letter F or and its unit is lumen. Definition of 1 Lumen : 1 Lumen =

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UNIT III LECT - 14 Luminous Intensity or Illuminating Power (I) : The luminous intensity (or) illuminating power (I) of a point source in any direction is defined as the luminous flux emitted or radiated per unit solid angle in that direction. If F is the luminous flux radiated by a source within a solid angle in any particular direction, then luminous intensity I = F /

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UNIT III LECT - 15 F is measured in lumen and in steradian, the unit for I Definition of One Candela : It is the luminous intensity of one sixtieth (1/60) th of a square centimetre of platinum at its fusion point. (1769 o C) or one candela is the luminous intensity of the source if it emits 1 lumen per steradian.

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UNIT III LECT - 16 Illumination (or) Intensity of Illumination (E) : The illumination (or) intensity of illumination at a point on the surface is defined as the luminous flux (F) received on an unit area (A) of the surface surrounding the point. Its unit is lumen /m 2.

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UNIT III LECT - 17 Other units of illumination : Lux : It is equal to 1 lumen per square metre. It can also be defined as the intensity of illumination over a surface area of 1m 2, placed at a distance of 1m from a point source of 1 Candela. Phot : It is the intensity of illumination of a source which receives one lumen per square centimetre. 1 phot = 10 4 lux.

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UNIT III LECT - 18 Inverse square law of illumination : The intensity of illumination (E) of a surface due to a light source is directly proportional to the luminous intensity or illuminating power (I) of the source and inversely proportional to the square of the distance between the source and the surface (r 2 ). (or)

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UNIT III LECT - 19 Principle of Photometry : The principle of photometry is based on the adjustment of the distances of the two light sources from the measuring point they produce equal intensity of illumination at the point.

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UNIT III LECT E 1 and E 2 be the intensity of illumination due to two sources S 1 and S 2 at a surface S, r 1 and r 2 be the distances of the two sources from the surface. The inverse square law of illumination, and Where I 1 and I 2 are the luminous intensities of the two sources. By adjusting r 1 and r 2, E 1 and E 2 are made equal. i.e., E 1 = E 2

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UNIT III LECT = (or) = The luminous intensity of one source is known, by comparison, the luminous intensity of another source can be determined. Photometer : It is an instrument which is used to compare the luminous intensities of two sources. If the luminous intensity of one of the source is known, the luminous intensity of the other one can be measured.

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UNIT III LECT LUMMER – BRODHUN PHOTOMETER : This is one of the most accurate photometers used for comparing the luminous intensities of two sources. LUMMER – BRODHUN PHOTOMETER

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UNIT III LECT Screen S : This is a specially prepared screen made of some white diffusing material of high reflecting power such as plaster of paris or magnesium carbonate. The light rays from the two sources are incident on the two sides of this screen.

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UNIT III LECT Totally reflecting prism P 1 and P 2 : P 1 and P 2 are two isosceles right angled prisms whose angles are 45 o, 90 o and 45 o. The light rays scattered from the screen S, fall normally on one face of the prism, enter into the prisms without any change in their direction, undergo total internal reflection and emerge normally from the other face of these prisms.

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UNIT III LECT Lummer Brodhun Cube A and B : It consists of two right-angled isosceles prisms A and B in contact with each other. The edges of prism A are cut in such a way that it is slightly curved at the outer edge while flat in the central part. The prisms are cemented together at the central part with Canada Balsam, whose refractive index is the same as that of the material of the prisms.

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UNIT III LECT The two prisms are in optical contact with each other at the central part and enclose an air film between them at other parts. Telescope T : The telescope (T) is used to receive the light coming from Lummer – Brodhun cube. The whole apparatus is enclosed in a metallic box blackened from inside.

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UNIT III LECT Working : S 1 and S 2 are two sources whose luminous intensities are to be compared. These sources can be moved along an optical bench. They are placed on the opposite side of the screen S at equal distances and illuminate the screen normally. The light rays reflected diffusively from each side of screen are incident on the prisms P 1 and P 2. These light rays undergo total internal reflection from the prisms and fall on Lummer Brodhun cube.

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UNIT III LECT Contd. The outer rays from the source S 1 undergo total internal reflection at prism A, while the middle ray passes into the prism B through the point of contact of the prisms A and B without any deviation. The outer rays from S 2 undergo total internal reflection at B, while the middle ray passes into the prism A through the point of contact without any deviation.

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UNIT III LECT Contd. In this way, middle ray from source S 1 and outer rays from source S 2 enter into the telescope. Since the luminous intensities of the two sources are different, the field of view of the eyepiece of the telescope consists of a central part illuminated by light from S 1 and an outer part illuminated by light from S 2 of different brightness. Now the distances of S 1 and S 2 are adjusted in such a way that the field of view appears equally bright.

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UNIT III LECT Field of view in a Lummer – Brodhun Photometer When the two sources are of different intensities When the sources are having equal intensities.

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UNIT III LECT Comparison of luminous intensities of two sources : When the distances of S 1 and S 2 are so adjusted that the illuminations on the two sides of S are equal, the whole field of view appears uniformly bright and the boundary dividing the two fields disappears. Let I 1 and I 2 be the luminous intensities of S 1 and S 2 and r 1 and r 2 are their respective distances from S, then according to inverse square law of illumination,

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UNIT III LECT = (or) The luminous intensities of the two sources can be compared. If I 1 is known, I 2 can be calculated from the relation, (or) Thus the luminous intensities of the two sources can be compared.

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UNIT III LECT This photometer is best suited for the comparison of luminous intensities of two light sources producing same colour. If the sources produce different colour the readings are unreliable, and flicker photometer is used.

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UNIT III LECT Solved Problem (1) : Two lamps of 32 candle power and 8 candle power respectively are placed 2 metres apart. A screen is placed between them. Where should the screen be placed in order that it may be equally illuminated by the lamps on both sides ? Given I 1 = 32 candle power I 2 = 8 candle power r 1 + r 2 = 2m

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UNIT III LECT Formula : Let x be the distance from where the screen has to be placed to get equal illumination on the screen. Then r 1 = x

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UNIT III LECT (4+x 2 -4x) = 8x 2 24x 2 – 128x = 0 3x 2 – 16x + 16 = 0 3x 2 – 4x – 12x + 16 = 0 r 1 (3x-4)-4(3x-4) = 0 (x-4) (3x-4) = 0 Hence x can be either 4 or 4/3 Since the separation between the two lamps in 2m, x cannot be 4 m. Here x = 4/3m. i.e. when the screen is placed at a distance of 4/3m from the lamp of 32 candle power, the screen is illuminated equally by the lamps on both sides.

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UNIT III LECT Solved Problem (2) : Two lamps of 32.c.p. and 8 c.p. respectively are placed 2 meters apart. Where should a screen be placed in order that it may be equally illuminated by the lamps ? There are two possible positions of the screen. (i) Both the sources lie on the same side of the screen. Let the distance of the first lamp (8 c.p.) from the screen be x as shown. When the screen is equally illuminated by the two lamps, then

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UNIT III LECT - 128

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UNIT III LECT x = 200 cm. or Thus the screen should be placed at a distance 200 cm from the lamp L 1 (8 c.p.) and 400 cm from the second lamp L 2 (32 c.p.)

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UNIT III LECT (ii) The screen is between two sources. When the screen is equally illuminated by the two lamps.. x = cm. Thus the screen should be placed at a distance of cm from the first lamp L 1 (8 c.p.) and cm from the second lamp L 2 (32 c.p.)

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UNIT III LECT Solved Problem (3) : Two identical sources are at a distance of 60 cm from each other. Where must a screen be placed in between them so that one side of the screen may be illuminated four times greater than the other Let the screen be placed at a distance xcm from first source. Now the distance of the second source will be (60-x) cm. If the illumination of one side is E, then the illumination of the other side should be 4E. Let both the sources have illuminating power I. Then

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UNIT III LECT Case. (i)Considering +ve sign 120-2x = x or x = 40 cm. Case. (ii)Considering –ve sign 120 – 2x = - x or x = 120 cm. which is impossible because it is greater than 60cm. Thus the distance of the screen must be 40 cm from one source and 20cm from the other source.

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UNIT III LECT Exercise Problem (1) : Two lamps of 20 candle power and 10 candle power are placed A metre apart. A screen is placed such that both the lamps are on the same side of the screen and line joining the lamps is perpendicular to the screen. At what distance the screen has to be placed so that it may be equally illuminated by the lamps placed on the same side. At a distance of 9.655m from the lamp of 10 candle power.

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UNIT III LECT Thank u

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