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Law of Conservation of Energy The total amount of energy in the system remains constant It can only be converted from one form to another BUT No new energy.

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Presentation on theme: "Law of Conservation of Energy The total amount of energy in the system remains constant It can only be converted from one form to another BUT No new energy."— Presentation transcript:

1 Law of Conservation of Energy The total amount of energy in the system remains constant It can only be converted from one form to another BUT No new energy can be created It can never be destroyed

2 Potential and Kinetic Energy Energy: is the ability to do work

3 Potential Energy The energy of position The amount of energy contained in an object at rest

4 Determining Potential Energy By its position and its weight (mass X gravity) PE = (mass)(gravity)(height) = mgh where m is mass in kg g is the force of gravity = 9.8 m/s 2 h is the height The SI unit that represents potential energy is the Joule (J) (kg m 2 /s 2 ).

5 Examine an example of potential energy A flower pot with a mass of 15 kg is sitting on a window sill 15 meters above the ground. How much potential energy does the flower pot contain? PE = (mass)(gravity)(height) = (15 kg)(9.8 m/s 2 )(15 m) = 2205 kg m 2 /s 2 = 2205 J = 2.2 x 10 3 J

6 Kinetic Energy SO…. Once force is applied to an object, the object is set into motion. A moving object is said to contain kinetic energy or energy of motion. The amount is related to the mass of the object in motion and its velocity.

7 Calculating kinetic energy If we know the mass of an object and its velocity we can determine the amount of kinetic energy possessed by using the following formula: kinetic energy = 1/2 (mass of object)(velocity of object) 2 or KE = 1/2 mv 2 or KE = 0.5mv 2 The SI unit for kinetic energy is the Joule (J). A Joule is kg m 2 /s 2

8 A bicycle with a mass of 14 kg traveling at a velocity of 3.0 m/s east has how much kinetic energy? KE = 0.5mv 2 = 0.5(14 kg)(3.0 m/s) 2 = 0.5(14 kg)(9.0 m 2 /s 2 ) = 63 kg m 2 /s 2 = 63 J

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10 What type of energy does the space shuttle have at lift off?

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12 Conversion of Potential to Kinetic Energy In this picture both kinds of energy are evident. Can you point them out?

13 The water at the top has potential energy When water falls to a lower level, the potential energy is converted to kinetic energy.

14 FORCES The term force refers to the interaction of objects and their environment. All forces are exerted on one object by another object. Forces have both size and direction and are normally classified as pushes or pulls. All forces have both size and direction

15 Gravity – most familiar force Gravity is the basic force of attraction that is spread throughout the universe. Gravity pulls objects towards each other. Gravity on earth pulls you and all objects towards the earth. You must overcome gravity each time you lift something. Gravitational force on earth is 9.8m/s 2 Other forces – –Buoyancy -Friction –Electricity-Pressure

16 Calculating Force The relationship between an object's mass m, its acceleration a, and the applied force F Force =(mass)(acceleration) or F = ma The SI units for force is the Newton (N) A Newton is equivalent to the units: N = kg x m s 2

17 Example An object with a mass of 15.0 kg is moving with an acceleration of 25.0 m/s 2. What is the force acting on that object? F = ma = (15.0 kg) x 25.0m/s 2 ) = 375 kg m/s 2 = 375 N

18 Another Force - Weight Weight is a force applied to an object as a result of gravity. Weight = mass x (gravitational force) F w = (m) (g) On earth, the force of gravity is nearly constant = 9.8 m/s 2

19 Mass vs. weight Understand the difference

20 Weight It is different depending on where the object is located and the amount of gravity acting on it. Weight is expressed in Newtons (N) Weight of an object can be determined by the following formula Weight = (mass) (gravity) OR F w = (m)(g)

21 Example If an object has a mass of 75 kg on earth, what is its weight? F w = (m)(g) = (75 kg) x (9.8 m/s 2 ) = 735 kg m/s 2 = 735 N = 740 N

22 Re-Arrange the Formula Solve for weight F w = (m)(g) Solve for mass m= F w ÷ (g) Solve for gravity g= F w ÷ (m)

23 How Energy Relates to Work Energy - the ability to do work Work - a measure of how productive an applied force is

24 Work Work is the product of the force applied to an object time the distance through which the force acts EXAMPLES OF WORK –Lifting a book –Pulling a cart –Pushing a door open Sometimes there are easy ways and hard ways to do the same amount of work.

25 Work The formula for work is: Work = (force) (distance) or W = Fd The unit for work is the Joule J = N * m = kg *m 2 s 2 It is important that you understand that all units used in the equation are in Kg, m and seconds. The problem will not be accurate (or correct) if the units are not in this form.

26 Example A book weighing 3.0N is lifted 5m. How much work is done? W = Fd W = (3.0N) (5m) W = 15J

27 You need to rearrange the equation to get force. F = W ÷ d Rearrange for distance d = w ÷ F

28 Using Simple Machines to do Work More Easy Devices that allow us to perform the same amount of work more easily.

29 Simple Machines Work in One of 3 Ways 1.Can take the force exerted by the individual and redirect it 2.Can turn a small effort or force into a larger force (mechanical advantage) 3.Can magnify the distance that a force acts on Machines do not reduce the amount of work needed to perform a task, they reduce the effort needed from the user.

30 3 Kinds We Will Consider 1.Lever 2.Inclined Plane 3.Pulley

31 The Lever Is a narrow beam that rotates around a single point called the fulcrum By placing an object to be moved, called the load, at one point on the beam and by applying an effort at another point the object can be moved more easily

32 1 st Class Lever 1 st class – where the fulcrum lies between the load and the effort Effort Load Fulcrum

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34 2 nd class lever 2 nd class levers where the fulcrum lies at one end and an effort is placed at the other end. –The load lies in between Effort Load Fulcrum

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36 3 rd Class Lever 3 rd class lever – where the effort is applied between the load (W) and the fulcrum Fulcrum Effort Load

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38 Review of Levers 1 st Class Lever Load – Fulcrum – Effort 2 nd Class Lever Fulcrum – Load – Effort 3 rd Class Lever Fulcrum – Effort - Load

39 Formula for Levers Effort X distance from the fulcrum = weight X distance from the fulcrum The ability of the lever to help perform work is dependent on the length of the lever and on the mass applied to the lever. Too heavy of a mass or too long of lever the lever will break.

40 How much mass can a lever handle? Apparatus for lab looks like this:

41 Inclined Plane Device designed to reduce the force needed to raise an object. For example, pushing a load up a ramp onto a platform requires less force than lifting the load onto the platform. Ramps and steps are forms of inclined planes.

42 Screw Screw is an inclined plane wrapped in a spiral around a shaft.

43 Wedge Wedge is actually 2 inclined planes joined back-to-back The planes exert lateral forces to split the piece of wood

44 Remember! An inclined plane does not reduce the amount of work being done – It simple reduces the force necessary to complete that work by creating a mechanical advantage.

45 Pulleys is a wheel over which a rope or belt is passed for the purpose of transmitting energy and doing work.

46 Pulleys Reduce the effort to raise an object or it redirects the applied force, depending on the type of pulley.

47 Velocity & Acceleration Some Review

48 Defining Velocity Kinetic energy was –KE=1/2 (mass) (velocity) 2 Describes both the rate and direction of the motion If an object speeds up or slows down in the given direction we say there is a change in velocity

49 VELOCITY AND SPEED Velocity is a measure of how fast an object is traveling in a certain direction. –Example: A plane moving at 600mph to the north has a velocity. –Important to realize that for you to use velocity, you must have a direction! –Speed is a measure of how fast something is moving, but there is not a directional element to it.

50 VELOCITY AND SPEED –Speed is a measure of how fast something is moving, but there is not a directional element to it –Is the distance on object moves per time –Speed = Distance X Time (S=D x T) –If speed changes, so does the velocity

51 VELOCITY Velocity = distance ÷ time The units we use are m/s and d is distance. Rearranging the formulas for all possibilities: V= d/t d = vt t = d/v

52 VELOCITY What is the velocity of a car that travels 100m in 2 hours? V = d/t 100.m/2h = 50.0m/h A car travels 65.0m/h for 3.00 hours how far did it go? d = vt (65.0m/h) (3.00h) = 195m = How long would it take a car to travel 200 miles at a velocity of 70m/h? t = d/v t = 200m/70m/h t = 2.9h = 3hr Make sure you work your problems so that units cancel out.

53 ACCELERATION Acceleration is the change in velocity per unit of time. An example of this is when you travel in your car. Your velocity is not constant throughout the entire trip as you slow down and speed up as necessary. A positive acceleration means that you are speeding up and a negative acceleration means that you are slowing down.

54 ACCELERATION Acceleration has the formula: Acceleration = (Final Velocity) – (initial velocity) (Final time) – (Initial time) OR (time it takes to change velocity) A = v f – v i = v means change in t f – t i t Acceleration has the units of (distance unit)/(time unit) Ex: m/s 2 or mi/h 2

55 ACCELERATION Example acceleration problems Calculate the acceleration of an object with: »Initial Velocity : 0.0m/s »Final Velocity: 14m/s »Time 4s »A = 14m/s – 0m/s 4s A = 3.5m/s 2

56 ACCELERATION A car stops from a velocity of 55m/s in 15 seconds. What is the cars acceleration? Is the car speeding up or slowing down? A = 0 – 55m/s -55m/s 15 s 15s A = -3.7m/s 2 Car is slowing down


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