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**B: Tangent to the Circle**

Circular Motion B C A B: Tangent to the Circle Use this to motivate circular motion involves acceleration. A ball is going around in a circle attached to a string. If the string breaks at the instant shown, which path will the ball follow? 16

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**Uniform Circular motion**

FN mw= mass (downward) v FT FN = mg r m FT = Tension Force mg FT = ma FT = m (v2 / r) mw T = mwg as it is at rest. mwg = m v2 / r

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**Uniform Circular motion**

FT = m (v2 / r) v mg FN T r mw FT What is the physical meaning of the formula? What happens if the initial speed v of the bob is forced to move faster? A greater T is needed, the greater mw, to keep the radius of motion r. It will slide out to attain a greater r. What happens if there is energy lost due to friction on the plane? v decreases By T = mv2 / r, r decreases What happen if an additional mass is added to the weight mw? M moves down r decreases and T increases v increases

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**Uniform Circular motion Uniform circular motion in a horizontal plane**

FT = m (v2 / r) v mg FN FTz r m M v mg FN FTz r m M v mg FN FTz r m M v mg FN FTz r m M Name 3 events as a result of a cable suddenly breaking: Tension suddenly disappears and there is no more centripetal force Circular motion cannot be maintained. The bob will move with its velocity tangent to the circle at the instant the string breaks

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**Circular Motion Review**

When we see an object carrying out circular motion, we know that there must be force acting on the object, directed towards the center of the circle. When you look at the circular motion of a ball attached to a string, the force is provided by the tension in the string. When the force responsible for the circular motion disappears, e.g. by cutting the string, the motion will become linear.

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**Circular Motion Review 2**

In most cases, the string force not only has to provide the force required for circular motion, but also the force required to balance the gravitational force. Important consequences: You can never swing an object with the string aligned with the horizontal plane. When the speed increases, the acceleration increases up to the point that the force required for circular motion exceeds the maximum force that can be provided by the string.

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**Circular Motion and its Connection to Friction**

When you drive your car around a corner you carry out circular motion. In order to be able to carry out this type of motion, there must be a force present that provides the required acceleration towards the center of the circle. This required force is provided by the friction force between the tires and the road. But remember ….. The friction force has a maximum value, and there is a maximum speed with which you can make the turn. Required force = Mv2/r. If v increases, the friction force must increase and/or the radius must increase.

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Questions 2 You are driving a car with constant speed around a horizontal circular track. On a piece of paper, draw a Free Body Diagram for the car. How many forces are acting on the car? A) B) C) D) E) 5 Normal Tension 3 forces, Tension (friction), gravity and the normal force Gravity The net force on the car is A. Zero B. Pointing radially inward C. Pointing radially outward B: Force of tension is pointing inward 25

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Question 3 Davain sits on the outer rim of a merry-go-round, and Diego sits midway between the center and the rim. The merry-go-round makes one complete revolution every two seconds. Diego’s velocity is: Diego Davian (a) the same as Davian’s (b) Faster than Davian’s Slower than Davian’s a = V2/r (C) Diego is slower than the velocity of Davian

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**Summary Uniform Circular Motion Speed is constant**

Direction is changing Acceleration toward center a = v2 / r Newton’s Second Law F = ma

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