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Complex numbers i or j

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**An Imaginary Number, when squared, gives a negative result.**

Complex numbers An Imaginary Number, when squared, gives a negative result. imaginary2 = negative

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**i = √-1 Complex numbers i is used in maths But**

j is used in electronics and engineering (because i is already used as a symbol for current)

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Complex numbers i = √-1 i2 = -1 i3 = -√-1 i4 = 1 i5 = √-1

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Complex numbers Example What is i6 ? i6 = i4 × i2 = 1 × -1 = -1

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**Adding complex numbers**

(4 +j3) + (3 + j5) 4 +j j5 7 + j8

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**Adding complex numbers**

(3 +j6) + (2 – j3) 3 +j6 + 2 – j3 5 + j3

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**Subtracting complex numbers**

(6 +j8) - (2 + j3) 6 +j8 - 2 – j3 4 + j5 Note the change of sign

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**Multiplying complex numbers**

Example 1, 6(3 +j4) = 18 + j24 Example 2 j8 + 3(3 – j2) = j8 + 9 – j6 j2 + 9

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**Multiplying complex numbers**

(3 + j2)(4 + j) Use F.O.I.L. (3x4) + (3xj) + (j2 x4) + (j2 x j) 12 + j3 + j8 + j22 j2 = -1 12 +j11 – 2 10 + j11

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**Multiplying complex numbers**

(5 - j2)(2 + j2) Use F.O.I.L. (5 x 2) + (5 x j2) - (j2 x2) - (-j2 x j2) 10 + j10 – j4 - j24 j2 = -1 10 – j6 + 4 14 - j10

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**Multiplying complex numbers**

(4 - j2)(3 - j) Use F.O.I.L. (4 x 3) - (4 x j) - (j2 x3) + (j2 x j) 12 – j4 – j6 + j22 j2 = -1 12 - j10 – 2 10 - j10

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**Multiplying a conjugate pair**

(4 - j2)(4 + j2) Use F.O.I.L. (4 x 4) + (4 x j2) - (j2 x 4) - (j2 x j2) 16 + j8 – j8 - j24 j2 = -1 16 + 4 20

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**Dividing complex numbers**

(2 +6j)/2j = 2/2j + 6j/2j = 1/j +3 J-1 + 3

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**Dividing complex numbers**

(6 + j3)/ (3+j2) Multiply by the conjugate of the denominator (6 + j3) x (3 – j2) (3 + j2) (3 - j2) 18 – j12 +j9 –j26 9 – j6 + j6 –j24

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**Dividing complex numbers**

18 - j – j24= 24 – j

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Argand Diagrams Imaginary axis y Real axis x Z = x +yj

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Argand Diagrams r r = √(x2 + y2)

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Argand Diagrams tanΦ = y/x Φ

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**Argand Diagrams x = r cosΦ r yj = r sinΦ Z = x +yj Φ Imaginary axis y**

Real axis x Z = x +yj x = r cosΦ r yj = r sinΦ Φ

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**Argand diagrams are used to calculate impedance in RLC circuits**

Example Argand diagrams are used to calculate impedance in RLC circuits

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Example The impedance of a circuit is given by the complex number 3 +j4 Construct the Argand diagram for 3 +j4

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Example Imaginary axis y Real axis x Z = 3 +j4 3 r j4

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Example From the Argand diagram derive the expression for the impedance in polar form

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**Example r = √(32 + 42) = √(9 + 16) √(25) = 5 r Z = 3 +j4 3**

Imaginary axis y Real axis x Z = 3 +j4 3 r j4

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**Example r tanΦ = 4/3 Φ = 53.13 Z = 3 +j4 3 Imaginary axis y j4**

Real axis x Z = 3 +j4 3 r j4

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**Example r Answer Z = 5 53.13 Z = 3 +j4 3 Imaginary axis y j4**

Real axis x Z = 3 +j4 3 r j4

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**Multiplying and dividing polar form**

6∟20° x 4∟30° Multiply the length (modulus) and add the argument (angle) = 24∟50° 9∟10° / 3∟40° = 9/3 ∟(10°-40°) divide the length (modulus) and subtract the argument (angle) = 3∟-30°

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**Argand diagrams as phasor diagrams**

The voltage of a circuit is given as V = 3 + j3 and the current drawn is given as I = 8 + j2 Find the phase difference between V and I Find the power (VI.cosФ)

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**Argand diagrams as phasor diagrams**

Voltage = √ ( ) = √18 = 4.24 Volts Current = √( ) = √ 68 = amps

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**Argand diagrams as phasor diagrams**

Voltage phase angle tanΦ = 3/3 =1, Φ = 45o Current phase angle tanΦ = 2/8 =0.25, Φ = 14.0o

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**Argand diagrams as phasor diagrams**

Phase difference between V and I = 45o o = 31o power = VIcosΦ 4.24 x 8.25 cos31o 4.24 x 8.25 x .86 = 30 watts

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