 # COMPLEX ZEROS OF A QUADRATIC FUNCTION

## Presentation on theme: "COMPLEX ZEROS OF A QUADRATIC FUNCTION"— Presentation transcript:

COMPLEX ZEROS OF A QUADRATIC FUNCTION
SECTION 2.7 COMPLEX ZEROS OF A QUADRATIC FUNCTION

SQUARE ROOTS OF NEGATIVE NUMBERS
Is a value we have dealt with up to now by simply saying that it is not a real number. And, up to now, we have dealt with the following equation by simply saying it has no solution: x2 + 4 = 0

DEFINITION OF i i 2 = - 1 The number i is called an imaginary number. Imaginary numbers, along with the real numbers, make up a set of numbers known as the complex numbers.

COMPLEX NUMBERS Imaginary Real i 2i 5 -1 - 3i 2/3i 1/2 .7
5 -1 1/2 .7

COMPLEX NUMBERS All numbers are complex and should be thought of in the form: a + bi Imaginary Part Real Part

COMPLEX NUMBERS a + bi Real Part Imaginary Part
When b = 0, the number is a real number. Otherwise, the number is imaginary.

OPERATING ON COMPLEX NUMBERS
Addition: Example: (3 + 5i) + ( i) Subtraction: (6 + 4i) - ( 3 + 6i)

OPERATING ON COMPLEX NUMBERS
Multiplication: Example: (5 + 3i) • (2 + 7i) (3 + 4i) • ( 3 - 4i)

CONJUGATES 2 + 3i = 2 - 3i Multiplying a complex number by its conjugate always yields a nonnegative real number.

THEOREM: If z = a + bi z z = a2 + b2

Writing the reciprocal of a complex number in standard form.
Example:

Writing the quotient of complex numbers in standard form.
Example:

Writing the quotient of complex numbers in standard form.
Example:

POWERS OF i i1 = i i2 = - 1 i3 = - i i4 = 1 i5 = i and so on

QUADRATIC EQUATIONS WITH A NEGATIVE DISCRIMINANT
Quadratic equations with a negative discriminant have no real solution. But, if we extend our number system to the complex numbers, quadratic equations will always have solutions because we will then be including imaginary numbers.

EXAMPLE

EXAMPLE Solve the following equations in the complex number system: x2 = 4 x2 = - 9

WARNING!

EXAMPLE Solve the following equation in the complex number system: x2 - 4x + 8 = 0

DISCRIMINANT If b2 - 4ac > 0 Two unequal real sol’ns
If b2 - 4ac = 0 One double real root If b2 - 4ac < 0 Two imaginary solutions

EXAMPLE: Without solving, determine the character of the solution of each equation in the complex number system: 3x2 + 4x + 5 = 0 2x2 + 4x + 1 = 0 9x2 - 6x + 1 = 0

CONCLUSION OF SECTION 2.7