Presentation is loading. Please wait.

Presentation is loading. Please wait.

Chapter 10.3: Logic Gates Based on Slides from Discrete Mathematical Structures: Theory and Applications and by Aaron Bloomfield.

Similar presentations


Presentation on theme: "Chapter 10.3: Logic Gates Based on Slides from Discrete Mathematical Structures: Theory and Applications and by Aaron Bloomfield."— Presentation transcript:

1 Chapter 10.3: Logic Gates Based on Slides from Discrete Mathematical Structures: Theory and Applications and by Aaron Bloomfield

2 2 Learning Objectives Explore the application of Boolean algebra in the design of electronic circuits. The basic elements of circuits are gates. Each type of gate implements a Boolean operation. We will study combinational circuits - the circuits whose output depends only on the input and not on the current state of the circuit (no memory).

3 3 Logical Gates and Combinatorial Circuits

4 4

5 5

6 6 In circuitry theory, NOT, AND, and OR gates are the basic gates. Any circuit can be designed using these gates. The circuits designed depend only on the inputs, not on the output. In other words, these circuits have no memory. Also these circuits are called combinatorial circuits. The symbols NOT gate, AND gate, and OR gate are also considered as basic circuit symbols, which are used to build general circuits.

7 7 Logical Gates and Combinatorial Circuits

8 8

9 9

10 10

11 11

12 12

13 13

14 14

15 15

16 16 Draw a circuit diagram for = (xy' + x'y)z.

17 17

18 18

19 19

20 20 A circuit for two light switches EXAMPLE 3, p. 714 F(x,y)=1 when the light is on F(x,y)=0 when the light is off When both switches are closed, the light is on: F(1,1)=1, this implies When we open one switch, the light is off: F(1,0)=F(0,1)=0 When the other switch is also open, the light is on: F(0,0)=1

21 21 Thus, we get: xyF(x,y) 111 100 010 001 Which Boolean expression is given by F? Draw a circuit for F, i.e., a circuit to control two light switches. F(x,y) = xy + x'y'

22 22

23 23

24 24

25 25

26 26

27 27

28 28

29 29

30 30

31 31 Logical Gates and Combinatorial Circuits A NOT gate can be implemented using a NAND gate (a). An AND gate can be implemented using NAND gates (b). An OR gate can be implemented using NAND gates (c).

32 32 Logical Gates and Combinatorial Circuits Any circuit which is designed by using NOT, AND, and OR gates can also be designed using only NAND gates. Any circuit which is designed by using NOT, AND, and OR gates can also be designed using only NOR gates.

33 33 Adders: Logical gates to add two numbers We need to use a circuit with more than one output, which clearly more powerful than a Boolean expression.

34 34 How to add binary numbers Consider adding two 1-bit binary numbers x and y 0+0 = 0 0+1 = 1 1+0 = 1 1+1 = 10 Carry is x AND y Sum is x XOR y The circuit to compute this is called a half-adder xyCarrySum 0000 0101 1001 1110

35 35 xysc 1101 1010 0110 0000 = s (sum) c (carry)

36 36 x 11110000 y 11001100 c 10101010 s (sum) 10010110 c (carry) 11101000 A full adder is a circuit that accepts as input thee bits x, y, and c, and produces as output the binary sum cs of a, b, and c.

37 37 The full adder The full circuitry of the full adder

38 38 We can use a half-adder and full adders to compute the sum of two Boolean numbers 1 1 0 0 + 1 1 1 0 010? 001 Adding bigger binary numbers

39 39 Adding bigger binary numbers Just chain one half adder and full adders together, e.g., to add x=x 3 x 2 x 1 x 0 and y=y 3 y 2 y 1 y 0 we need:

40 40 Adding bigger binary numbers A half adder has 4 logic gates A full adder has two half adders plus a OR gate Total of 9 logic gates To add n bit binary numbers, you need 1 HA and n-1 FAs To add 32 bit binary numbers, you need 1 HA and 31 FAs Total of 4+9*31 = 283 logic gates To add 64 bit binary numbers, you need 1 HA and 63 FAs Total of 4+9*63 = 571 logic gates

41 41 More about logic gates To implement a logic gate in hardware, you use a transistor Transistors are all enclosed in an IC, or integrated circuit The current Intel Pentium IV processors have 55 million transistors!

42 42 Flip-flops Consider the following circuit: What does it do? R S Q Q RS Function 10Reset 01Set 11Hold 001/1 It holds a single bit of memory.

43 43 Memory A flip-flop holds a single bit of memory The bit flip-flops between the two NAND gates In reality, flip-flops are a bit more complicated Have 5 (or so) logic gates (transistors) per flip- flop Consider a 1 Gb memory chip 1 Gb = 8,589,934,592 bits of memory Thats about 43 million transistors! In reality, those transistors are split into 9 ICs of about 5 million transistors each


Download ppt "Chapter 10.3: Logic Gates Based on Slides from Discrete Mathematical Structures: Theory and Applications and by Aaron Bloomfield."

Similar presentations


Ads by Google