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Stress and Strain TUTORIAL 6 to answer just click on the button or image related to the answer

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what is stress? Question 1a internal force intensity a force per unit area c internal force b a or c d

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what are the units of stress? Question 1b kN, MN a kPa, MPa c kN / m, MN /m b kNm 2, MNm 2 d

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what is strain? Question 2a a bad back ache a change in size or shape c response to stress b b and d e change in size or shape relative to original state d b and c f

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what are the units of strain? Question 2b mm, cm, m a no units c kN / m b kNm d

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what is the strain in the cable? Question 3a 4 mm a 8 x 10 -4 b 50 kN 5 m 20 mm a 20mm ø high-strength steel cable 5 m long has a weight of 50 kN at its end. Neglecting the self-weight of the cable and Given that the cable lengthens by 4mm 8 x 10 -4 mm c

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what is the stress in the cable? Question 3b 159.2 kPa a 159.2 MPa b 50 kN 5 m 20 mm a 20mm ø high-strength steel cable 5 m long has a weight of 50 kN at its end. Neglecting the self-weight of the cable and Given that the cable lengthens by 4mm 0.15 kPa c

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is the cable strong enough? Question 3c no a yes b 50 kN 5 m 20 mm a 20mm ø high-strength steel cable 5 m long has a weight of 50 kN at its end. Neglecting the self-weight of the cable and Given that the cable lengthens by 4mm Given that the maximum allowable tensile stress for high-strength steel is 1000 MPa

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what factors do we have to take Into consideration? Question 4a strength of the column a slenderness of the column b when a column is under load a and b c

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what is the first means of failure we should check for? Question 4b column breaking under compression a buckling b when a column is under load

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what is the stress in the column? Question 5a 1 MPa a 4 kPa b a reinforced concrete column, 400 x 400 mm and 3.5 m high is subject to a load of 160 kN Given that the column shortens by 0.07 mm 1 kPa c 160 kN 3.5 m 400 mm

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what is the strain in the column? Question 5b 50 a 2 x 10 -5 b a reinforced concrete column, 400 x 400 mm and 3.5 m high is subject to a load of 160 kN Given that the column shortens by 0.07 mm 0.00002 mm c 160 kN 3.5 m 400 mm

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is the column strong enough? Question 5c yes a no b a reinforced concrete column, 400 x 400 mm and 3.5 m high is subject to a load of 160 kN Given that the column shortens by 0.07 mm Given that the maximum allowable stress for the concrete is 20 MPa 160 kN 3.5 m 400 mm

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could you reduce the area of the column? Question 5d yes a no b a reinforced concrete column, 400 x 400 mm and 3.5 m high is subject to a load of 160 kN Given that the column shortens by 0.07 mm Given that the column is understressed 160 kN 3.5 m 400 mm maybe c

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to what size could you theoretically reduce the area of the column? Question 5e 90 mm x 90 mm a 400 mm x 200 mm b a reinforced concrete column, 400 x 400 mm and 3.5 m high is subject to a load of 160 kN Given that the column shortens by 0.07 mm 160 kN 3.5 m 400 mm 200 mm x 40 mm c

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what would be the problem with that? Question 5f none a it would buckle b Given that you want to reduce the column to 90 mm x 90mm 160 kN 3.5 m 400 mm it would be difficult to build c b and c d

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next question enough ! f = F /A – so its force distributed over an area that means its the intensity of the force, not the force itself

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let me try again let me out of here partly correct

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let me try again let me out of here a thousand times NO! a force is a force – not stress

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next question enough ! f = F /A – so its force distributed over an area 1 kN/m 2 = 1 kPa

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let me try again let me out of here thats force units

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let me try again let me out of here go back to the formula f = F / A

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next question enough ! strain is a response to stress and is a relative concept

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let me try again let me out of here No? Then you are the pain

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let me try again let me out of here

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let me try again let me out of here I dont like that the change is just the deformation – not the strain

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next question enough ! length over length means strain is dimensionless

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let me try again let me out of here e = ΔL / L this is length over length

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let me try again let me out of here wheres the force in e = ΔL / L ?

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next question enough ! 0.0008 is also correct but 8 x 10 -4 gives a better feel

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let me try again let me out of here e = ΔL / L whats ΔL, whats L, what are the units for strain?

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let me try again let me out of here what are the units for strain ?

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next question enough ! Well done !

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let me try again let me out of here f = F / A check your calculations and units (its good practice to keep everything to Newtons and mm 1 N/mm 2 = 1 MPa = 1MN/m 2 )

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next question enough ! actual stress of 159 MPa is much less than max allowable stress of 1000 MPa

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and then think again let me try again let me out of here Whats the actual stress? Whats the maximum allowable stress? Is the actual stress less or more than the max allowable stress?

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next question enough ! both are important

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let me try again let me out of here

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next question enough ! we always check to see if a column is slender and would buckle first

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let me try again let me out of here

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next question enough ! Right on ! f = F / A

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let me try again let me out of here How did you get that? f = F / A Whats the force? Whats the area?

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let me try again let me out of here check your calculations and your units? Its good practice to keep everything to Newtons and mms 1 N/mm 2 = 1 MPa = 1 MN/m 2

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next question enough ! 0.00002 is also correct but 2 x 10 -5 is easier to follow

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Check your calculations? Whats ΔL? Whats L? let me try again let me out of here e = ΔL / L

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let me try again let me out of here What are the units of strain ?? e = ΔL / L

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next question enough ! actual stress of 1 MPa is much less than max allowable stress of 20 MPa

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Whats the actual stress? Whats the maximum allowable stress? Is the actual stress less than or greater than the max allowable stress? SO ? let me try again let me out of here

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next question enough ! it depends on how much we reduce it by

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let me try again let me out of here

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If its understressed that means the area is greater than needs be let me try again let me out of here

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next question enough ! according to calculations A = F / f Minimum required area = 8000 mm 2

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let me try again let me out of here not according to the theoretical calculations f = F / A A = F / f

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the end ! Yes its much too slender. It would buckle immediately Also, how could you pour concrete into such a small area?

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let me try again let me out of here think again !

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let me try again let me out of here

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