Presentation is loading. Please wait.

Presentation is loading. Please wait.

Problem 2.133 Cable AB is 65 ft long, and the tension in that cable is 3900 lb. Determine (a) the x, y, and z components of the force exerted by the cable.

Similar presentations


Presentation on theme: "Problem 2.133 Cable AB is 65 ft long, and the tension in that cable is 3900 lb. Determine (a) the x, y, and z components of the force exerted by the cable."— Presentation transcript:

1 Problem Cable AB is 65 ft long, and the tension in that cable is 3900 lb. Determine (a) the x, y, and z components of the force exerted by the cable on the anchor B, (b) the angles x, y, and z defining the direction of that force. O x y z 56 ft D B C A 50 o 20 o

2 Solving Problems on Your Own O x y z 56 ft D B C A 50 o 20 o Cable AB is 65 ft long, and the tension in that cable is 3900 lb. Determine (a) the x, y, and z components of the force exerted by the cable on the anchor B, (b) the angles x, y, and z defining the direction of that force. 1. Determine the rectangular components of a force defined by its magnitude and direction. If the direction of the force F is defined by the angles y and, projections of F through these angles or their components will yield the components of F. Problem 2.133

3 Solving Problems on Your Own Cable AB is 65 ft long, and the tension in that cable is 3900 lb. Determine (a) the x, y, and z components of the force exerted by the cable on the anchor B, (b) the angles x, y, and z defining the direction of that force. 2. Determine the direction cosines of the line of action of a force. The direction cosines of the line of action of a force F are determined by dividing the components of the force by F. cos x = FxFx F cos y = FyFy F cos z = FzFz F O x y z 56 ft D B C A 50 o 20 o Problem 2.133

4 Problem Solution z y Determine the direction cosines of the line of action of a force. O x B A FyFy FzFz F FxFx 20 o y 65 ft From triangle AOB: cos y = 56 ft 65 ft = y = o (a) F x = _ F sin y cos 20 o = _ (3900 lb) sin o cos 20 o F x = _ 1861 lb F y = + F cos y = (3900 lb)( ) F y = lb F z = + (3900 lb) sin o sin 20 o F z = lb 56 ft

5 Problem Solution O x B A FyFy FzFz F FxFx 20 o y 65 ft y Determine the direction cosines of the line of action of a force. (b) cos x = FxFx F = _ 1861 lb 3900 lb cos x = _ x = o From above (a): y = 30.5 o cos z = FzFz F = lb 3900 lb = z = 80.0 o 56 ft


Download ppt "Problem 2.133 Cable AB is 65 ft long, and the tension in that cable is 3900 lb. Determine (a) the x, y, and z components of the force exerted by the cable."

Similar presentations


Ads by Google