The background measurement of acceleration when stationary fluctuates between 1g and 1.04g spending approximately 50% of the time at each reading. Thus the stationary reading should be 1.02g. Taking a reading of the maximum acceleration on the upwards journey gives a value of 1.12g. This corresponds to an additional upwards acceleration of (1.12-1.02)=0.1g = 0.98m/s 2. Finding the Acceleration
Finding the Velocity Integrating acceleration with respect to time gives the velocity reached by the lift. Thus the area under the graph is the velocity reached. Approximating the area as a triangle gives the velocity reached as:
Finding the Distance Travelled The distance traveled by the lift can be approximated by assuming that the lift travels at the calculated velocity (0.98m/s 2 ) for a time of 10.2-1.2=9.0 seconds giving a distance traveled of 8.8m.