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Sample Questions 91587. Example 1 Billys Restaurant ordered 200 flowers for Mothers Day. They ordered carnations at $1.50 each, roses at $5.75 each, and.

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Presentation on theme: "Sample Questions 91587. Example 1 Billys Restaurant ordered 200 flowers for Mothers Day. They ordered carnations at $1.50 each, roses at $5.75 each, and."— Presentation transcript:

1 Sample Questions 91587

2 Example 1 Billys Restaurant ordered 200 flowers for Mothers Day. They ordered carnations at $1.50 each, roses at $5.75 each, and daisies at $2.60 each. They ordered mostly carnations, and 20 fewer roses than daisies. The total order came to $ How many of each type of flower was ordered?

3 Decide your variables Billys Restaurant ordered 200 flowers for Mothers Day. They ordered carnations at $1.50 each, roses at $5.75 each, and daisies at $2.60 each. They ordered mostly carnations, and 20 fewer roses than daisies. The total order came to $ How many of each type of flower was ordered?

4 Write the equations Billys Restaurant ordered 200 flowers for Mothers Day. c + r + d = 200 They ordered carnations at $1.50 each, roses at $5.75 each, and daisies at $2.60 each. 1.5c r + 2.6d = They ordered mostly carnations, and 20 fewer roses than daisies. d – r = 20 The total order came to $ How many of each type of flower was ordered?

5 Order the equations Billys Restaurant ordered 200 flowers for Mothers Day. c + r + d = 200 They ordered carnations at $1.50 each, roses at $5.75 each, and daisies at $2.60 each. 1.5c r + 2.6d = They ordered mostly carnations, and 20 fewer roses than daisies. d – r = 20 The total order came to $ How many of each type of flower was ordered?

6 Solve using your calculator and answer in context There were 80 carnations, 50 roses and 70 daisies ordered.

7 Example 2 If possible, solve the following system of equations and explain the geometrical significance of your answer.

8 Calculator will not give you an answer. If possible, solve the following system of equations and explain the geometrical significance of your answer.

9 Objective - To solve systems of linear equations in three variables. Solve.

10 There is no solution. The three planes form a tent shape and the lines of intersection of pairs of planes are parallel to one another Inconsistent, No Solution

11 Example 2 Solve the system of equations using Gauss- Jordan Method

12 Example Solve the system of equations using Gauss- Jordan Method

13 Example Solve the system of equations using Gauss- Jordan Method

14 Example Solve the system of equations using Gauss- Jordan Method

15 Example Solve the system of equations using Gauss- Jordan Method No solution

16 Example 3 Consider the following system of two linear equations, where c is a constant: 1.Give a value of the constant c for which the system is inconsistent. 2.If c is chosen so that the system is consistent, explain in geometrical terms why there is a unique solution.

17 Give a value of the constant c for which the system is inconsistent. The lines must be parallel but not a multiple of each other c = 10

18 If c is chosen so that the system is consistent, explain in geometrical terms why there is a unique solution. It means that the 2 lines must have different gradients so they intersect to give a unique solution.

19 Example 4 The Health Club serves a special meal consisting of three kinds of food, A, B and C. Each unit of food A has 20 g of carbohydrate, 2 g of fat and 4 g of protein. Each unit of food B has 5 g of carbohydrate, 1 g of fat and 2 g of protein. Each unit of food C has 80 g of carbohydrate, 3 g of fat and 8 g of protein. The dietician designs the special meal so that it contains 140 g of carbohydrate, 11 g of fat and 24 g of protein. Let a, b and c be the number of units of food A, B and C f respectively) used in the special meal. Set up a system of 3 simultaneous equations relating a, b and c. Do not solve the equations.

20 For this type of problem it is easier if you make a table The Health Club serves a special meal consisting of three kinds of food, A, B and C. Each unit of food A has 20 g of carbohydrate, 2 g of fat and 4 g of protein. Each unit of food B has 5 g of carbohydrate, 1 g of fat and 2 g of protein. Each unit of food C has 80 g of carbohydrate, 3 g of fat and 8 g of protein. The dietician designs the special meal so that it contains 140 g of carbohydrate, 11 g of fat and 24 g of protein. Let a, b and c be the number of units of food A, B and C f respectively) used in the special meal. Set up a system of 3 simultaneous equations relating a, b and c. Do not solve the equations.

21 CarbohydrateFatProtein A B C

22 Each unit of food A has 20 g of carbohydrate, 2 g of fat and 4 g of protein CarbohydrateFatProtein A2024 B C

23 Each unit of food B has 5 g of carbohydrate, 1 g of fat and 2 g of protein CarbohydrateFatProtein A2024 B512 C

24 Each unit of food C has 80 g of carbohydrate, 3 g of fat and 8 g of protein CarbohydrateFatProtein A2024 B512 C8038

25 The dietician designs the special meal so that it contains 140 g of carbohydrate, 11 g of fat and 24 g of protein. CarbohydrateFatProtein A2024 B512 C8038 Total

26 Write the equations CarbohydrateFatProtein A2024 B512 C8038 Total

27 Example 5 Consider the following system of three equations in x, y and z. 4x + 3y + 2z = 11 3x + 2y + z = 8 7x + 5y + az = b Give values for a and b in the third equation which make this system: 1. inconsistent, 2.consistent, but with an infinite number of solutions.

28 Inconsistent Add the first two equations and put it with the third equation 4x + 3y + 2z = 11 3x + 2y + z = 8 7x + 5y + 3z = 19 7x + 5y + az = b a = 3, b 19

29 Consistent with an infinite number of solutions Add the first two equations and put it with the third equation 4x + 3y + 2z = 11 3x + 2y + z = 8 7x + 5y + 3z = 19 7x + 5y + az = b a = 3, b = 19

30 Example 6 Consider the following system of three equations in x, y and z. 2x + 2y + 2z = 9 x + 3y + 4z = 5 Ax + 5y + 6z = B Give possible values of A and B in the third equation which make this system: 1. inconsistent. 2.consistent but with an infinite number of solutions.

31 Example 6 2x + 2y + 2z = 9 x + 3y + 4z = 5 3x + 5y + 6z = 14 Ax + 5y + 6z = B Ax + 5y + 6z = B 1. inconsistent. A = 3, B 14 2.consistent but with an infinite number of solutions. A = 3, B = 14


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