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A DOZEN roses = 12 roses A PAIR of shoes = 2 shoes.

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Presentation on theme: "A DOZEN roses = 12 roses A PAIR of shoes = 2 shoes."— Presentation transcript:

1

2 A DOZEN roses = 12 roses

3 A PAIR of shoes = 2 shoes

4 a DOZEN eggs = 12 eggs

5 a REAM of paper = 500 sheets

6 A GROSS of pencils = 144 pencils

7 A SIX –PACK of beer = 6 cans

8 TRIO

9 QUARTET

10 When you have a dozen of something, no matter what you are talking about, you have 12 of that thing. -A dozen donuts - a dozen eggs -a dozen cars, -a dozen chemistry problems are all 12 of that material.

11 The mole is the exact same concept. You can have: -a mole of eggs - a mole of donuts - a mole of cars - a mole of chemistry problems. However a mole is MUCH bigger than 12...it is 602 sextillion. Obviously a mole of chemistry problems is way too many problems.

12 The mole is typically used for counting or grouping very very small things, like atoms

13 a MOLE ( mol ) 1. The mole is an SI unit that allows us to count # of: -Atoms - molecules -formula units without actually seeing them Representative particles

14 2. 1 mol = 6.02 x representative particles 3. The number is called Avogadros number in honor of the Italian scientist Amadeo Avogadro

15 Avogadros number Atoms or Molecules or FUNs 1 mole of anything = 6.02 x 10 23

16 MOLE DAY

17 4. REPRESENTETIVE particles: 1.ATOMs (elements on the PT) 2. MOLECULES (_______compounds – all elements are non metals) EX: CO 2, NO 2, C 12 H 22 O Formula Units (_____compounds – at least one element must be a metal) EX: NaCl, CuCl 2, FeO covalent ionic

18 A DOZEN MASS of a dozen limes = MASS of a dozen cars

19 A MOLE CARBON COPPER MASS of a mole carbon = MASS of a mole copper 6.02 x C atoms = 6.02 x10 23 Cu atoms

20 HOW DO YOU DETERMINE THE MASS OF A MOLE ?

21 MOLAR MASS – the mass of 1 mole of any pure substance (element and compound) Molar Mass (MM) = Atomic mass (AM) MM units - g/mol AM - Atomic Mass units - amu ( atomic mass units) EX: Mn amu = g/mol

22 EXAMPLES: 1.1 mole of Al : 2. 1 mole of CO 2 : AM (C) = amu = MM # of atoms = # of moles AM (O) = amu x 2 = MM (16.00) = g/mole AM g =MM g/mol

23 3. 1 mole of Cu(NO 2 ) 2 : AM (Cu) amu = MM g/mole AM (N) 14 x 2 amu = MM g/mole AM (O) 16 x 4 amu = MM g/mole (14) + 4 (16) =155.5 g/mole


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