Download presentation

Presentation is loading. Please wait.

Published byDane Nickolson Modified over 3 years ago

1
Milagros Duran & Keslie Chapa December 18, 2013 7+8A

2
A pair of boots and a pair of tennis shoes cost $196.12. The difference in their cost is $44.38. Determine the cost of each. Problem Situation

3
Define Variables X= cost of a pair of boots Y= cost of a pair of tennis shoes

4
X –Y = 44.38 System of Equations X + Y = 196.12

5
Elimination Add the equations to eliminate the variable Y. Solution Method

6
X + Y = 196.12 Add the equations X –Y = 44.38 2X = 240.50 X = 120.25 Step 1 of Solution

7
X + Y = 196.12 Rewrite knowing that X equals 120.25 120.25 + Y = 196.12 Subtract 120.25 from both sides. Y = 75.87 Step 2 of Solution

8
(X, Y) (120.25, 75.87) Solution to the System of Equations

9
151.74+44.38=196.12 Check of Solution

10
The cost of a pair of boots is $120.25. The cost of a pair of tennis shoes is $75.87. Solution in the Problem Situation

Similar presentations

OK

Another method for solving systems of equations is elimination

Another method for solving systems of equations is elimination

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on beautiful places in india Ppt on causes of road accidents Download free ppt on global warming Ppt on seven segment display alphabet Free ppt on mobile number portability pdf Ppt on mathematician carl friedrich gauss Ppt on series and parallel circuits quiz Ppt on index numbers in excel Download ppt on squares and square roots Ppt online application form 2016