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Published byDane Nickolson
Modified over 2 years ago
Milagros Duran & Keslie Chapa December 18, 2013 7+8A
A pair of boots and a pair of tennis shoes cost $196.12. The difference in their cost is $44.38. Determine the cost of each. Problem Situation
Define Variables X= cost of a pair of boots Y= cost of a pair of tennis shoes
X –Y = 44.38 System of Equations X + Y = 196.12
Elimination Add the equations to eliminate the variable Y. Solution Method
X + Y = 196.12 Add the equations X –Y = 44.38 2X = 240.50 X = 120.25 Step 1 of Solution
X + Y = 196.12 Rewrite knowing that X equals 120.25 120.25 + Y = 196.12 Subtract 120.25 from both sides. Y = 75.87 Step 2 of Solution
(X, Y) (120.25, 75.87) Solution to the System of Equations
151.74+44.38=196.12 Check of Solution
The cost of a pair of boots is $120.25. The cost of a pair of tennis shoes is $75.87. Solution in the Problem Situation
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