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AP Statistics CHAPTER 16: CHAPTER 16: RANDOM VARIABLES Unit 4.

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Presentation on theme: "AP Statistics CHAPTER 16: CHAPTER 16: RANDOM VARIABLES Unit 4."— Presentation transcript:

1 AP Statistics CHAPTER 16: CHAPTER 16: RANDOM VARIABLES Unit 4

2 random variable A random variable assumes a value based on the outcome of a random event. We use a capital letter, like X, to denote a random variable. A particular value of a random variable will be denoted with the corresponding lower case letter, in this case x. EXPECTED VALUE: CENTER

3 There are two types of random variables: Discrete Discrete random variables can take one of a countable number of distinct outcomes. Example: Number of credit hours, amount of people at an event Continuous Continuous random variables can take any numeric value within a range of values. Example: Cost of books this term, daily temperature EXPECTED VALUE: CENTER (CONT.)

4 probability model A probability model for a random variable consists of: The collection of all possible values of a random variable (x), and the probabilities P(x) that the values occur. Of particular interest is the value we expect a random variable to take on, notated μ (for population mean) or E(X) for expected value. EXPECTED VALUE: CENTER (CONT.)

5 expected value The expected value of a (discrete) random variable can be found by summing the products of each possible value by the probability that it occurs: Note: Be sure that every possible outcome is included in the sum and verify that you have a valid probability model to start with. EXPECTED VALUE: CENTER (CONT.)

6 Derek took his car in for repair recently because his air conditioner was cutting out intermittently. The mechanic identified the problem as dirt in the control unit. He said that in about 75% of such cases, drawing down and then recharging the coolant a couple of times cleans up the problem-and it costs only $60. If that fails, then the control unit must be replaced at an additional cost of $100 for parts and $40 for labor. Define the random variable and construct the probability model. What is the expected value of the cost of this repair? What does that mean in this context? EXAMPLE

7 In order to anticipate the variability, we need measure the spread. standard deviation For data, we calculated the standard deviation by first computing the deviation from the mean and squaring it. We do that with discrete random variables as well. variance The variance for a random variable is: standard deviation The standard deviation for a random variable is: FIRST CENTER, NOW SPREAD…

8 Lets do a basic example. Calculate the mean and standard deviation: Strikers has a chicken wing special on Thursdays. The pub owners purchase wings in cases of 300. The random variable x represents the number of cases used during the special. FIRST CENTER, NOW SPREAD… EXAMPLE

9 RECALL: Adding or subtracting a constant from data shifts the mean but doesnt change the variance or standard deviation: E(X ± c) = E(X) ± c Var(X ± c) = Var(X) Example: Consider everyone in a company receiving a $5000 increase in salary. MORE ABOUT MEANS AND VARIANCES

10 In general, multiplying each value of a random variable by a constant multiplies the mean by that constant and the variance by the square of the constant (since we multiply the standard deviation by the constant): E(aX) = aE(X)Var(aX) = a 2 Var(X) Example: Consider everyone in a company receiving a 10% increase in salary. MORE ABOUT MEANS AND VARIANCES (CONT.)

11 In general, The mean of the sum of two random variables is the sum of the means. The mean of the difference of two random variables is the difference of the means. E(X ± Y) = E(X) ± E(Y) If the random variables are independent, the variance of their sum or difference is always the sum of the variances. Var(X ± Y) = Var(X) + Var(Y) MORE ABOUT MEANS AND VARIANCES (CONT.)

12 Dicks Sporting Goods is offering a promotion where customers can pull from a bucket of frisbees to reveal a possible discount of $20. The frisbees are thrown back in and thoroughly mixed. The manager says the discounts will vary with an average of $5.83 and a standard deviation of $8.62. Dunhams, up the street, is offering a discount by selecting tennis balls under a wrapper. The balls are thrown back in and thoroughly mixed. Dunhams manager says the discounts vary with an average of $10 and a standard deviation of $15. How much more can you expect to save at Dunhams? With what standard deviation? EXAMPLE

13 Recall: Dicks Sporting Goods is offering a promotion where customers can pull from a bucket of frisbees to reveal a possible discount of $20. The fribees are thrown back in and thoroughly mixed. The manager says the discounts will vary with an average of $5.83 and a standard deviation of $8.62. The manager expects 40 customers to come in the day of the promotion. What is the expected total of the discounts that the manager will give? With what standard deviation? EXAMPLE 2

14 Suppose the time it takes a customer to get and pay for Pirates seats at the ticket window at PNC park is a random variable with a mean of 100 seconds and a standard deviation of 50 seconds. When you get there, you find only two people in line in front of you. How long do you expect to wait for your turn to get tickets? Can you assume the two customers are independent events? If so, what is the standard deviation of your wait time? EXAMPLE 3

15 continuous random variables Random variables that can take on any value in a range of values are called continuous random variables. Now, any single value wont have a probability, but… Continuous random variables have means (expected values) and variances. We wont worry about how to calculate these means and variances in this course, but we can still work with models for continuous random variables when were given the parameters. CONTINUOUS RANDOM VARIABLES

16 Good news: nearly everything weve said about how discrete random variables behave is true of continuous random variables, as well. When two independent continuous random variables have Normal models, so does their sum or difference. This fact will let us apply our knowledge of Normal probabilities to questions about the sum or difference of independent random variables. CONTINUOUS RANDOM VARIABLES (CONT.)

17 Probability models are still just models. Models can be useful, but they are not reality. Question probabilities as you would data, and think about the assumptions behind your models. If the model is wrong, so is everything else. WHAT CAN GO WRONG?

18 Dont assume everythings Normal. Normality Assumption You must Think about whether the Normality Assumption is justified. Watch out for variables that arent independent: You can add expected values for any two random variables, but You can only add variances of independent random variables. WHAT CAN GO WRONG? (CONT.)

19 Dont forget: Variances of independent random variables add. Standard deviations dont. Dont forget: Variances of independent random variables add, even when youre looking at the difference between them. Dont write independent instances of a random variable with notation that looks like they are the same variables. WHAT CAN GO WRONG? (CONT.)

20 We know how to work with random variables. We can use a probability model for a discrete random variable to find its expected value and standard deviation. The mean of the sum or difference of two random variables, discrete or continuous, is just the sum or difference of their means. And, for independent random variables, the variance of their sum or difference is always the sum of their variances. RECAP

21 Normal models are once again important. Sums or differences of Normally distributed random variables also follow Normal models. RECAP (CONT.)

22 Day 1: Day 1: # 1, 3, 7, 9, 15, 17, 25, 29, 35, 43 Day 2: Day 2: # 2, 4, 10, 19, 21, 23, 27, 33, 37, 38, 45 Day 3: Day 3: # 6, 8, 16, 20, 30, 41 ASSIGNMENTS: PP. 383 – 387


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