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Exponential Applications Exponential Growth and Decay Models.

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Presentation on theme: "Exponential Applications Exponential Growth and Decay Models."— Presentation transcript:

1 Exponential Applications Exponential Growth and Decay Models

2 8/14/2013 Exponential Applications 2 Exponential Functions Increasing and Decreasing Exponential growth : f(x) = C a x for a > 1 and C > 0 Example : f(x) = C2 x Exponential decay : x y f(x) = C2 x (0, C) Domain = R Range = { x x > 0 } Exponential Growth Exponential Compounding

3 8/14/2013 Exponential Applications 3 Exponential Functions Increasing and Decreasing Exponential growth : f(x) = C a x Exponential decay : g(x) = f(–x) = C a –x for a > 1... a reflection of f(x) h(x) = Cb x x y f(x) = C2 x g(x) = f(–x) (0, C) Domain = R Range = { x x > 0 } OR 1 a b =b =, say a = 2, for 0 < b < 1 and = C2 –x h(x) = C ( ) 1 2 x Exponential Decay

4 8/14/2013 Exponential Applications 4 Exponential Functions Increasing and Decreasing Exponential growth : f(x) = C a x Exponential decay : g(x) = f(–x) = C a –x x y f(x) = C2 x g(x) = f(–x) (0, C) Domain = R Range = { x x > 0 } = C2 –x Questions: Intercepts ? Asymptotes ? Growth factor a ? Decay factor a ? One a > 1 0 < a < 1 Exponential Growth Exponential Decay Exponential Compounding

5 8/14/2013 Exponential Applications 5 Exponential Functions Increasing and Decreasing Exponential growth : f(x) = C a x Exponential decay : g(x) = f(–x) = C a –x x y f(x) = C2 x g(x) = f(–x) (0, C) Domain = R Range = { x x > 0 } = C2 –x f = { (x, 2 x ) x R } g = { (x, 2 –x ) x R } As ordered pairs, with C = 1, and

6 8/14/2013 Exponential Applications 6 Exponential Functions Increasing and Decreasing Exponential growth : f(x) = C a x Exponential decay : g(x) = f(–x) = C a –x x y f(x) = C2 x g(x) = f(–x) (0, C) Domain = R Range = { x x > 0 } = C2 –x In tabular form, with C = 1, –2 ¼ 4 –1 ½ ½12½ 24¼24¼ 3 8 –3 8 x 2 x 2 –x –4

7 8/14/2013 Exponential Applications 7 Think about it !

8 8/14/2013 Exponential Applications 8 Solving Equations: Examples 1. World population t P(t) t P( t) P1P1 P2P2 P3P3 ( x 10 9 ) P(t) = 3(1.018) t–1960

9 8/14/2013 Exponential Applications 9 Spare Parts Slide 2 2 | | | ± ½ ½ ½ ¼ ¼ ¼


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