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**Section 2.3 – Product and Quotient Rules and Higher-Order Derivatives**

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The Product Rule The derivative of a product of functions is NOT the product of the derivatives. If f and g are both differentiable, then: In other words, the derivative of a product of two functions is the first function times the derivative of the second function plus the second function times the derivative of the first function. Another way to write the Rule:

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**Example 1 Differentiate the function: u v v u' u v' Product Rule**

Sum/Difference Rule Power Rule Simplify

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Example 2 If h(x) = xg(x) and it is known that g(3) = 5 and g'(3) =2, find h'(3). u v Find the derivative: u v' u v' Product Rule Evaluate the derivative:

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**“Lo-d-Hi minus Hi-d-Lo”**

The Quotient Rule The derivative of a quotient of functions is NOT the quotient of the derivatives. If f and g are both differentiable, then: In other words, the derivative of a quotient is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator. “Lo-d-Hi minus Hi-d-Lo” Another way to write the Rule:

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Example 1 Differentiate the function: u v v u' u v' v2 Quotient Rule

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Example 2 Find an equation of the tangent line to the curve at the point (1,½). Find the derivative (slope of the tangent line) when x=1 Find the Derivative Use the point-slope formula to find an equation

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**Example 3 Differentiate the function:**

The Quotient Rule is long, don’t forget to rewrite if possible. Rewrite to use the power rule Sum and Difference Rules Constant Multiple Rule Power Rule Try to find the Least Common Denominator Simplify

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**The derivation for tangent is in the book.**

Derivative of Secant Differentiate f(x) = sec(x). The derivation for tangent is in the book. Rewrite as a Quotient Quotient Rule Rewrite to use Trig Identities

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**More Derivatives of Trigonometric Functions**

We will assume the following to be true:

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**Example 1 Differentiate the function: Use the Quotient Rule**

v v u' u v' Quotient Rule Always look to simplify Trig Law: 1 + tan2 = sec2

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**Example 2 Differentiate the function: Use the Product Rule u v u v' v**

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Example 1 Let a. Find the derivative of the function.

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Example 1 (Continued) Let b. Find the derivative of the function found in (a).

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Example 1 (Continued) Let c. Find the derivative of the function found in (b).

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Example 1 (Continued) Let d. Find the derivative of the function found in (c).

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Example 1 (Continued) Let e. Find the derivative of the function found in (d). We have just differentiated the derivative of a function. Because the derivative of a function is a function, differentiation can be applied over and over as long as the derivative is a differentiable function.

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**Higher-Order Derivatives: Notation**

First Derivative Second Derivative Third Derivative Fourth Derivative nth Derivative Notice that for derivatives of higher order than the third, the parentheses distinguish a derivative from a power. For example: .

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Example 1 (Continued) Let f. Define the derivatives from (a-e) with the correct notation. You should note that all higher-order derivatives of a polynomial p(x) will also be polynomials, and if p has degree n, then p(n)(x) = 0 for k ≥ n+1.

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**Example 2 If , find . Will ever equal 0? Find the first derivative:**

Find the second derivative: Find the third derivative: No higher-order derivative will equal 0 since the power of the function will never be 0. It decreases by one each time.

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**Example 3 Find the second derivative of . Find the first derivative:**

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**Graphs of a Function and its Derivatives**

What can we say about g, g', g'' for the segment of the graph of y = g(x)? g : Increasing As the graph increases, the tangent lines are getting steeper. g' : Positive, Increasing g'' : Positive Since the first derivative is increasing, the second derivative must be positive.

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**Graphs of a Function and its Derivatives**

What can we say about g, g', g'' for the segment of the graph of y = g(x)? As the graph decreases, the tangent lines are getting less steep. g : Decreasing g' : Negative, Decreasing g'' : Negative Since the first derivative is decreasing, the second derivative must be negative.

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**Graphs of a Function and its Derivatives**

What can we say about g, g', g'' for the segment of the graph of y = g(x)? g : Decreasing As the graph decreases, the tangent lines are steeper. g' : Negative, Increasing g'' : Positive Since the first derivative is increasing, the second derivative must be positive.

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**Graphs of a Function and its Derivatives**

What can we say about g, g', g'' for the segment of the graph of y = g(x)? g : Increasing As the graph increases, the tangent lines are getting less steep. g' : Positive, Decreasing g'' : Negative Since the first derivative is decreasing, the second derivative must be negative.

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**Graphs of a Function and its Derivatives**

What can we say about g, g', g'' for the segment of the graph of y = g(x)? On the right side : On the left side : g : Decreasing g : Decreasing g' : Negative, Increasing g' : Negative, Decreasing g'' : Positive g'' : Negative Find the pieces of this graph that compare to the previous graphs.

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Average Acceleration Acceleration is the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. Example: Estimate the velocity at time 5 for graph of velocity at time t below. Find the average rate of change of velocity for times that are close and enclose time 5. 1 2 3 4 5 6 -2 -4 v(t) t

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**Instantaneous Acceleration**

If s = s(t) is the position function of an object that moves in a straight line, we know that its first derivative represents the velocity v(t) of the object as a function of time. The instantaneous rate of change of velocity with respect to time is called the acceleration a(t) of an object. Thus, the acceleration function is the derivative of the velocity function and is therefore the second derivative of the position function.

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**Position, Velocity, and Acceleration**

Position, Velocity, and Acceleration are related in the following manner: Position: Velocity: Acceleration: Units = Measure of length (ft, m, km, etc) The object is… Moving right/up when v(t) > 0 Moving left/down when v(t) < 0 Still or changing directions when v(t) = 0 Units = Distance/Time (mph, m/s, ft/hr, etc) Speed = absolute value of v(t) Units = (Distance/Time)/Time (m/s2)

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Example Example: The graph below at left is a graph of a particle’s velocity at time t. Graph the object’s acceleration where it exists and answer the questions below Positive acceleration and positive velocity Horizontal 1 2 3 4 5 6 -2 -4 v(t) t a(t) Moving towards the x-axis. Corner Positive acceleration and Negative velocity m = 0 2 m = -4 t 1 2 3 4 5 6 m = 2 Moving away from x-axis. -2 0 acceleration And constant velocity m = 4 -4 Negative acceleration and Positive velocity Negative acceleration and Negative velocity (0,2) U (5,6) When is the particle speeding up? When is the particle traveling at a constant speed? When is the function slowing down? (2,4) (4,5) U (6,7)

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**Speeding Up and Slowing Down**

An object is SPEEDING UP when the following occur: Algebraic: If the velocity and the acceleration agree in sign Graphical: If the velocitycurve is moving AWAY from the x-axis An object is traveling at a CONSTANT SPEED when the following occur: Algebraic: Velocity is constant and acceleration is 0. Graphically: The velocity curve is horizontal An object is SLOWING DOWN when the following occur: Algebraic: Velocity and acceleration disagree in sign Graphically: The velocity curve is moving towards the x-axis

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Example 3 The position of a particle is given by the equation where t is measured in seconds and s in meters. (a) Find the acceleration at time t. The derivative of the velocity function is the acceleration function. The derivative of the position function is the velocity function.

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Example 3 (continued) The position of a particle is given by the equation where t is measured in seconds and s in meters. (b) What is the acceleration after 4 seconds? (c) Is the particle speeding up, slowing down, or traveling at a constant speed at 4 seconds? m/s2 Since the velocity and acceleration agree in signs, the particle is speeding up. m/s m/s2

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Example 3 (continued) The position of a particle is given by the equation where t is measured in seconds and s in meters. (d) When is the particle speeding up? When is it slowing down? + – Velocity: + Speeding Up: (1,2) U (3,∞) Slowing Down: (0,1) U (2,3) Acceleration: – +

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The Derivative Function

The Derivative Function

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