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Stoichiometry - House Method 1. Start with a balanced chemical equation. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3.

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Presentation on theme: "Stoichiometry - House Method 1. Start with a balanced chemical equation. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3."— Presentation transcript:

1 Stoichiometry - House Method 1. Start with a balanced chemical equation. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3

2 Stoichiometry - House Method 2. Place the given information above the proper compounds in the equation. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3 120 gX g

3 Stoichiometry - House Method 3. Draw a simple house around each compound used in the problem. Add moles to the downstairs of each house. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3 120 gX g mole

4 Stoichiometry - House Method 4. Draw arrows to show the path of the conversion from beginning to end. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3 120 gX g mole

5 Stoichiometry - House Method 5. Set up your factor label conversions in the direction of the arrows. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3 120 gX g mole 120 g Na 2 CO 3 X 1 mol Na 2 CO 3 X mol NaOH X 40.0 g NaOH = 106.0 g Na 2 CO 3 mol Na 2 CO 3 1 mol NaOH Notice that there are no numbers in front of the mol to mol conversion…YET !

6 Stoichiometry - House Method 6. The numbers in front of the mol to mol conversion are the addresses (coefficients) of the compounds. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3 120 gX g mole 1 1 120 g Na 2 CO 3 X 1 mol Na 2 CO 3 X mol NaOH X 40.0 g NaOH = 106.0 g Na 2 CO 3 mol Na 2 CO 3 1 mol NaOH 2121

7 Stoichiometry - House Method 6. Solve the math. Na 2 CO 3 + Ca(OH) 2 2 NaOH + CaCO 3 120 gX g mole 120 g Na 2 CO 3 X 1 mol Na 2 CO 3 X mol NaOH X 40.0 g NaOH = 106.0 g Na 2 CO 3 mol Na 2 CO 3 1 mol NaOH 2121 90.6 g NaOH

8 N 2 + 3 H 2 2 NH 3 Calculate the number of grams of NH 3 produced by the reaction with 5.40 grams of H 2 with excess nitrogen.

9 Calculate the number of grams of N 2 needed to produce 7.4 grams of NH 3.


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