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# Which graph(s) could correctly show the energy-momentum 4-vectors for a particle with the worldline shown? Or choose (e) more than one could be correct.

## Presentation on theme: "Which graph(s) could correctly show the energy-momentum 4-vectors for a particle with the worldline shown? Or choose (e) more than one could be correct."— Presentation transcript:

Which graph(s) could correctly show the energy-momentum 4-vectors for a particle with the worldline shown? Or choose (e) more than one could be correct

In a completely inelastic collision, the two objects stick together afterwards. Consider a completely inelastic collision between two identical masses A and B, where B is initially stationary. The initial velocity of A cannot exceed c, so the final velocity cannot exceed c/2. A] true B] false

In a completely inelastic collision, the two objects stick together afterwards. Consider a completely inelastic collision between two identical masses A and B, where B is initially stationary. The initial velocity of A cannot exceed c, so the final velocity cannot exceed c/2. FALSE.

In a completely inelastic collision, the two objects stick together afterwards. Consider a completely inelastic collision between two identical masses A and B, where B is initially stationary. The final rest mass of the AB lump is: A] 2m B] smaller than 2m C] larger than 2m

Consider a completely inelastic collision between two identical masses A and B, where B is initially stationary. The final rest mass of the AB lump is larger than 2m. The rest mass of an object containing internal parts will increase if the internal parts move faster in the rest frame of the object. The rest mass will also increase if there is any stored internal energy. (Consider two masses connected by a spring… its clear from P conservation that the mass increases when the masses are moving. But when the spring is stretched or compressed, they arent moving, but the mass cant be different from when they are moving.)

We will call m the effective mass or even sometimes just the mass. P x = m v cP t = m c 2 = mc 2 + K At low speeds, these expressions turn into Newtonian formulas for P and K.

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