Presentation is loading. Please wait.

Presentation is loading. Please wait.

Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = V 2 = A = D = T =

Similar presentations


Presentation on theme: "Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = V 2 = A = D = T ="— Presentation transcript:

1 Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = V 2 = A = D = T =

2 Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s

3 Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no

4 Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2

5 Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2 D = ?

6 Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2 D = ? T = 7 sec.

7 Solution #1 D = V 1 t + at 2 2

8 Solution #1 D = ½ at 2 D = (6.1 m/s 2 )(7 sec) 2 2

9 Solution #1 D = ½ at 2 D = (6.1 m/s 2 )(7 sec) 2 2 D = 150 m

10 Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = V 2 = A = D = T =

11 Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ?

12 Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s

13 Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2

14 Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2 D = 484 m

15 Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2 D = 484 m T = no

16 Solution #2 Use equation # 7 V 2 2 = V ad

17 Solution #2 Use equation # 7 V 2 2 = V ad 0 m/s = V (-8.0m/s)( 484 m)

18 Solution #2 Use equation # 7 V 2 2 = V ad 0 m/s = V (-8.0m/s 2 )( 484 m) 7744 m 2 /s 2 = V 1 2

19 Solution #2 Use equation # 7 V 2 2 = V ad 0 m/s = V (-8.0m/s 2 )( 484 m) 7744 m 2 /s 2 = V 1 2 V 1 = 88 m/s

20 Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = V 2 = A= D= T=

21 Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s

22 Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s V 2 = 8.5 m/s

23 Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s V 2 = 8.5 m/s A = ?

24 Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. V 1 = 25.6 m/s V 2 = 8.5 m/s A = ? D = no

25 Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. V 1 = 25.6 m/s V 2 = 8.5 m/s A = ? D = no T = 4.6 sec

26 Solution #3 Use Equation #2 A = V 2 - V 1 t

27 Solution #3 A = V 2 - V 1 t A = 8.5 m/s – 25.6 m/s 4.6 sec

28 Solution #3 A = V 2 - V 1 t A = 8.5 m/s – 25.6 m/s 4.6 sec A = -3.7 m/s 2

29 Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid? V 1 = V 2 = A = D = T =

30 Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s

31 Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s

32 Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no

33 Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no D = ?

34 Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no D = ? T = 5.0 sec

35 Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2

36 Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2 D = (14m/s + 0 m/s)5 sec 2

37 Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2 D = (14m/s + 0 m/s)5 sec 2 D = 35 m

38 Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = V 2 = a= d= t=

39 Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s

40 Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ?

41 Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2

42 Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2 D = 50 m

43 Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2 D = 50 m T = no

44 Solution #5 Use equation #7 V 2 2 = V ad

45 Solution #5 Use equation #7 V 2 2 = V ad V 2 2 = 16 m/s + 2(4.0m/s 2 )(50m)

46 Solution #5 Use equation #7 V 2 2 = V ad V 2 2 = 16 m/s + 2(40.0m/s 2 )(50m) V 2 = 26 m/s


Download ppt "Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = V 2 = A = D = T ="

Similar presentations


Ads by Google