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Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = V 2 = A = D = T =

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Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s

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Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no

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Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2

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Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2 D = ?

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Acceleration A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s V 2 = no A = 6.1 m/s 2 D = ? T = 7 sec.

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Solution #1 D = V 1 t + at 2 2

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Solution #1 D = ½ at 2 D = (6.1 m/s 2 )(7 sec) 2 2

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Solution #1 D = ½ at 2 D = (6.1 m/s 2 )(7 sec) 2 2 D = 150 m

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Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = V 2 = A = D = T =

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Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ?

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Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s

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Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2

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Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2 D = 484 m

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Acceleration#2 What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s 2 and comes to rest in 484 m? V 1 = ? V 2 = 0 m/s A = -8.0 m/s 2 D = 484 m T = no

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Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad

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Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad 0 m/s = V 1 2 + 2(-8.0m/s)( 484 m)

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Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad 0 m/s = V 1 2 + 2(-8.0m/s 2 )( 484 m) 7744 m 2 /s 2 = V 1 2

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Solution #2 Use equation # 7 V 2 2 = V 1 2 + 2ad 0 m/s = V 1 2 + 2(-8.0m/s 2 )( 484 m) 7744 m 2 /s 2 = V 1 2 V 1 = 88 m/s

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Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = V 2 = A= D= T=

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Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s

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Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s V 2 = 8.5 m/s

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Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? V 1 = 25.6 m/s V 2 = 8.5 m/s A = ?

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Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. V 1 = 25.6 m/s V 2 = 8.5 m/s A = ? D = no

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Acceleration #3 What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. V 1 = 25.6 m/s V 2 = 8.5 m/s A = ? D = no T = 4.6 sec

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Solution #3 Use Equation #2 A = V 2 - V 1 t

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Solution #3 A = V 2 - V 1 t A = 8.5 m/s – 25.6 m/s 4.6 sec

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Solution #3 A = V 2 - V 1 t A = 8.5 m/s – 25.6 m/s 4.6 sec A = -3.7 m/s 2

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Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid? V 1 = V 2 = A = D = T =

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Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s

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Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s

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Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no

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Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no D = ?

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Acceleration #4 A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? V 1 = 14 m/s V 2 = 0 m/s A = no D = ? T = 5.0 sec

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Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2

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Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2 D = (14m/s + 0 m/s)5 sec 2

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Solution #4 Use equation # 4 D = (V 2 +V 1 ) t 2 D = (14m/s + 0 m/s)5 sec 2 D = 35 m

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Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = V 2 = a= d= t=

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Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s

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Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ?

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Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2

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Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2 D = 50 m

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Acceleration #5 An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s 2 over 50 meters. What is its final velocity? V 1 = 16 m/s V 2 = ? A = 4.0 m/s 2 D = 50 m T = no

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Solution #5 Use equation #7 V 2 2 = V 1 2 + 2ad

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Solution #5 Use equation #7 V 2 2 = V 1 2 + 2ad V 2 2 = 16 m/s + 2(4.0m/s 2 )(50m)

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Solution #5 Use equation #7 V 2 2 = V 1 2 + 2ad V 2 2 = 16 m/s + 2(40.0m/s 2 )(50m) V 2 = 26 m/s

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Acceleration a change in velocity ( speed or direction or both ) over time –speeding up or slowing down –changing direction moving in a circle is always.

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