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Hints and Examples in Chapter 37Part 2

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Hints 37-28 Use Equation 37.30 37-30 Use Equation 37.27 37-32 Use E=mc 2 (part A) and Take answer in joules and convert to eV (1.602 x 10 -19 =1 eV) 37-42 Use information in last problem 10 7 eV=1 MeV 37-46 The percentage of mass converted to energy can be found (1-(mass of 4He/2*mass of H)) and multiplying by the energy in 1 kg of matter Part b) take total energy consumption and divide by part a 37-60 Part a) use ½ mv 2 Part b) Use equation 37.36 Part c) use equation 37.22 Part d) Use equation 37.16 but solve for l 0 Part E) Use distance divided by given velocity Part F) Use equation 37.16 and divide by the given velocity

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37.29 At what speed is the momentum of a particle twice as great as the result obtained from non-relativistic momentum?

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Equation 37.27

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37.39 A particle has a rest mass of 6.64 x 10 -27 kg and a momentum of 2.10 x 10 -18 kg*m/s a) What is the total energy (kinetic plus rest energy) of the particle? b) What is the kinetic energy of the particle? c) What is the ratio of the kinetic energy to the rest mass of the particle?

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Equation 37.39 E 2 = p 2 c 2 +m 2 c 4 E 2 =(2.1 x 10 -18 ) 2 * 9 x 10 16 + (6.64 x 10 -27 ) 2 * (9 x 10 16 ) 2 E=8.68 x 10 -10 J

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Equation 37.38 E=K+mc 2 K=8.68 x 10 -10 – 6.64 x 10 -27 * 9 x 10 16 K=2.7 x 10 -10 J

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Ratio of Energies Ratio = 2.71 x 10 -10 / (6.64 x 10 -27 *9 x 10 16 ) Ratio= 0.45

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Kinda 46 In a hypothetical nuclear-fusion reactor, two helium nuclei combine or "fuse" to form one beryllium nucleus. The mass of a deuterium nucleus, expressed in atomic mass units (u), is 4.003 u; that of a helium nucleus is 8.004 u. (1u = 1.66 x 10 -27 kg) How much energy is released when 1 kg of He is fused?

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Find the amount of matter converted to energy

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Essential Cell Biology

Essential Cell Biology

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