Presentation on theme: "Chapter 5 Momentum Ewen et al. 2005)"— Presentation transcript:
1Chapter 5 Momentum Ewen et al. 2005) 5.1 Impulse and MomentumObjective:Use impulse and momentum in describing motion.
2MomentumIs a measure of the amount of inertia and motion and object has.Another way to think about momentum is how difficult it is to bring a moving object to rest.It is the product of mass and velocity.Units?kgm/s and slugft/sMomentum is a vector quantity.
3Example 1Find the momentum of an auto with mass 105 slugs traveling 60.0 mi/h.
4Example 2Find the momentum of an auto with mass 1350 kg traveling 75.0 km/h.
5Example 3Find the velocity a bullet of mass 1.00 x 10-2 kg would have to have so that it has the same momentum as a lighter bullet of mass 1.80 x 10-3 kg and velocity of 325 m/s.Problems 5.1:Do problems 1-11, odd.
6ImpulseImpulse on an object is the product of the force and the time interval during which the force acts on the object.How are impulse and momentum related?Recall that and
7Combining Eq. 1 and Eq. 2Then, distributing mMultiply both sides by tThus impulse (Ft) is equal to final minus initial momentums (mv), i.e. change in momentum.
8Some interesting outcomes After this analysis, we see that impulse is the measure of the change in momentum of an object in response to an exerted force.Some interesting outcomesGiven enough time and distance, any force no matter how small can bring the largest object to p = 0 when given enough time.The importance of “followthough” in sports.
9Example 4A 17.5-g bullet is fired at a muzzle velocity of 582 m/s from a gun with a mass of 8.00 kg and a barrel length of 75.0 cm.How long is the bullet in the barrel?What is the force on the bullet while it is in the barrel?Find the impulse exerted on the bullet while it is in the barrel.Find the bullet’s momentum as it leaves the barrel.
10Law of Conservation of Momentum When no outside forces are acting on a system of moving objects, the total momentum of a system remains constant.
11Example of Conservation of Momentum Both at RestAfter Pushvboy = m/svman = ?mman = 75 kgmboy = 35 kg