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NUCP 2371 Radiation Measurements II

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Presentation on theme: "NUCP 2371 Radiation Measurements II"— Presentation transcript:

1 NUCP 2371 Radiation Measurements II
Gamma Spectroscopy NUCP 2371 Radiation Measurements II

2 Spectrometer Since electromagnetic radiation does not cause any direct ionization Detector system needs to do several things Reasonable probability to convert gamma rays to electrons Must be able to detect these electrons Able to separate signal output from detector

3 EM radiation interactions
Since EM does not have any charge it must interact directly with the electron to cause ionization The more electrons to interact with the higher the probability to create an ion pair Usually if have more electrons will have more Protons More protons usually (but not always) leads to a higher density Density is main characteristic of how EM radiation will interact with mater

4 EM Interactions Rayleigh scattering- scattering of light by very tiny particles not very important because it does not cause ionization Photoelectric effect- electron scattering Comptom scattering- electron scattering and an extra gamma ray Pair Production- creation of two charged particles

5 Photoelectric Interactions
Low energy process Electron absorbs all energy of incoming photon Electron gets ejected with the energy of the photon minus the binding energy of the electron Binding energies are several to tens of eV Kinetic Energy of all electrons should be the same as the incoming photon If all energy is captured in detector will get a single peak corresponding to the photons energy

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7 Compton Interactions Medium energy
Electron absorbs some the incoming photons energy and creates a new lower energy photon Energy distribution is based on the scattered angle All scattered angles will be in detector so electron will have a series of energies

8 Compton (cont) Leads to the Compton continuum, the misc energies of the photon that gets scattered at different angles which lead to different energy deposition in the detector Compton edge distance from photopeak is dependant of energy of photon but is usually limited to 256 keV

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10 Compton Scattering λ1- λ0= h/mec (1- cosθ) λ1= wave after scattering
λ0 = initial wave of EM radiation h/mec= Compton wavelength of electron X m h=planks constant m= mass of electron c= speed of light θ = angle of scatter Energy= h f E= hc/ λ because λf=c h= planks constant= 4.13 E-15 eV s

11 Energy change Determine λ of initial EM radiation
Calculate change in λ Add change in λ to original λ Then calculate the new energy of the scatter EM radiation Start with 500 keV photon that is deflected 45degrees What next?

12 Pair Production High energy process
High energy EM interacts with the strong electric field of the nucleus Produces an electron and positron Energy of the two particles is energy of the EM wave minus 1.022MeV (rest mass energy of a β- and β +) Responsible for single and double escape peaks if energy of these particles escapes the detector

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15 Gamma Spectroscopy The size of the signals generated from scintillators and solid state detectors are proportional to the energy deposited in the crystal. Signals can be organized with respect to energy Each time a signal of a certain magnitude is counted it is added to that energy category So more of the same size signals that get produced from the detector will result in a larger peak at that corresponding energy Result will be a chart (spectrum) of the energies of the gamma rays and their intensities Signals can be sorted by output strength and counted, when arranged in increasing energy order we can create a energy spectrum of the gamma ray energies emitted byt a sample. Then we can compare this energies to nuclides that emit these energies ands [possible identify the unknown nuclide

16 Gamma Spectroscopy Can be used to identify unknown radionuclides
Can be used determine quantity of material present when calibrated Can be quite complicated if have many radionuclides present There are week long classes on how to properly read and interpret gamma spectra.

17 NaI vs HPGE NaI Higher efficiency Lower cost Larger sizes HPGE Better resolution Better for detecting weak sources But if need resolution in complex spectra no better than HPGe

18 NaI and Ge detectors Notice the difference in the gamma spectra from the two different detectors

19 Uranium Spectrum

20 Spectrum Photo peak Xrays Compton edge Single escape peak
Double escape peak Sum peak 511 peak Ge escape peak FWHM

21 Photo Peak Large peak in the spectrum that correlates to the full energy of the EM radiation Ideally would be straight line if all energy from EM would be collected in detector Is a wider peak due to some of the energy of the EM is lost from the detector

22 Photopeak

23 Xrays Low energy peaks that corresponds to either characteristic X-Rays from the sample or the shield material Some of the energy from EM radiation will excite the electron in the shield material, will have prominent peak at the Xray energies of Lead

24 Xrays

25 Single/Double Escape peak
Energy lost from the photo peak which correspond to the energy equivalent of an electron Only in high energy EM radiation (>1.022MeV) will escape peaks be present If have a small peak 511 keV lower than your main photopeak this is the energy of an electron escaping from the detector

26 511 keV 511 keV is a special energy
It is the energy that is emitted when a positron gets annilated by an electron and keV gamma rays are produced. If you get this peak in your spectrum there is a good chance you have a positron emitter in your sample Easy to spot

27 Peaks

28 Sum Peak If you have sample with much activity
May get a peak that is twice the energy of the photo peak This is from the detector seeing 2 independent EM radiations as one large one and will add the energies of them together and have one count but at twice the energy

29 Sum Peak

30 Ge Escape Peak Ge x-rays gets subtracted from the photopeak
Only important in low energy photopeaks In the order of keV

31 FWHM Full width half maximum Measure of the thickness of a peak
Take the width in channels at the point where the counts in those channels are ½ those of the maximum counts The lower the number the more compact and peaky the photo peak will be Can be used to determine if the detector is working correctly

32 Detector Sizes Small detector- Large detector-
size of detector is small compared to the path of secondary gamma rays Will result in significant compton continuum and possible escape peaks Large detector- Detector is large compared to path of secondary gamma rays Will result in a single photo peak and no Compton continuum Most detectors are in between

33 Signal processing Detector-detects radiation and produces an electronic signal Amplifier- amplifies the signal so it can be better seen ADC or Shaper- turns signal from Gaussian function into step function 2 types used in counting Scaler- separates signals according to potential Counter- accumulates counts and displays results

34 Calibration Energy-match energy of photo peak to the energy on the screen Efficiency- match area of peak to activity of source

35 Energy Calibration Purpose- match up the energy of the photopeaks with the energy label on the spectrum How is it done- have a know spectrum of photo peaks and their energies Correlate the channel number to the photopeak energy Need to have at least 3 peaks(5 better) Create an energy curve Save data and apply it to all spectra

36 Efficiency Calibration
Purpose- to have the area of the photopeak match the activity of the source How is it done- have a standard for which you know the activity and the % error Assign that activity to the area of the photo peak Need to have at least 5 peaks from low to high energies Create a efficiency curve that will be applied to all spectra Efficiency will then be used to convert areas to activities for all energies

37 Efficiency Calibtration
Low energies will have low efficiencies EM can not effectively get through the protective covering of the detector High energies will have low efficiencies Higher energy EM will have a lower probability of interacting with the detector

38 Betas High energy beta will create brehmstrahhlung
This will appear on the gamma spectrum as a large broad low energy mound Can interfere with small low energy peaks

39 Neutrons Neutron- too many neutrons will damage the detector
Avoid neutrons

40 QUESTIONS?


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