2INTRO Intro battery/wire/light bulb activity Use multi meter to look at battery voltage.
35.1.1 Define electric potential difference 5.1.2 Determine the change in potential energy when a charge moves between two points at different potentials.
45.1.1 Define electric potential difference When two charges interact there is an electric force between them.Potential energy from this is: Electrical Potential EnergySimilar to gravitational forceType of mechanical energyMetotal = KE + PEg + PEspring + PEelectric
5Where does the “potential” come from With potential gravity, an object can “potentially” fall from a height.With electrical potential, a charge can “potentially” fall down an electric field.A positive charge is placed in a uniform electric field and is displaced.The new position will have a ∆PE
6Where does the “potential” come from With potential gravity, an object can “potentially” fall from a height.With electrical potential, a charge can “potentially” fall down an electric field.A positive charge is placed in a uniform electric field and is displaced.The new position will have a ∆PE
7Electric Potential Energy Difference between two points in an electric field is equal to the work done in moving a charge from one position to a position of higher electrical potential energy in an electric field.See VideoMake Drawing
8Equation ∆PEelectric = -q Ed q = charge E = electric field strength d = displacement from reference point(-) = inidcates that the electrical potential energy will INCREASE if the charge is NEGATIVEUnit is a Joule(J)
9Potential DifferenceA measure of the difference in the electrical potential energy between two positions in space.AKA “voltage”Describes a change in energy per unit chargeUnit is volt (V)Most batteries are 1.5VSimilar idea to a water slide***Draw diagram***
10Equation ∆V = ∆PEelectric / q ∆V = voltage ∆PEelectric = electric potential energyq = charge
11Equation Combine the PEelectric equations with the ∆V and you get…. ∆V = -Ed***show substitution***New Equation:
12Last one ∆V = kc q/r kc = Coulomb constant (8.99 x 109Nm2/C2) q = charger = distance separating the two charges
135.1.4 Solve problems involving electric potential difference. Pg 599, Practice A1) 6.4 x 10-192) -750V3) (charge of electron = 1.6x10-19)2.3 x 10-16JSection Review pg 601
14CAPACITANCE!!!Relate capacitance to the storage of electrical potential energy in the form of separated charges.Calculate the capacitance of various devices.Calculate the energy stored in a capacitor.
15Capacitor Device that stores electrical potential energy. Uses tuning the frequency of radiosEliminating sparking in automobile ignition systemsStoring energy in electronic flash units
16Capacitor If, energized or charged has energy Energized by connecting the plates to the terminals of a battery.Charge transfer between the plates stops when the potential difference between the plates is equal to the pd of the battery.
17CapacitanceIs the ability of a conductor to store energy in the form of electrically separated charges.Is the ratio of charge to potential differenceSo…Capacitance = magnitude of charge/potential differenceC = Q/∆VSI unit is farad (F)
18Capacitance Depends on the size and shape of the capacitor. Many capacitors have parallel plates with no material between themThe equation shows that as the area of increases the capacitance increasesC = ε A/dε = permittivity of a vacuum (8.85 x10-12 C2/Nm2)A = area of one of the platesd = distance between the plates
19Dielectric The space between isn’t always empty Dielectric – insulating material that fills the space between two capacitor’s platesEx – air, rubber, glass, waxed paperCapacitance increases with use of dielectric.Molecules in a dielectric can align with the field of the patesReduces the charge on the capacitor plates.Q= C∆V
20The space between isn’t always empty Dielectric – insulating material that fills the space between two capacitor’s platesEx – air, rubber, glass, waxed paperCapacitance increases with use of dielectric.Molecules in a dielectric can align with the field of the patesReduces the charge on the capacitor plates.
21Discharge Is the opposite of charging After the two plates are charged they will stay charged until…Connected with a conductive material.Charges move back from one plate to the other until both are balanced and uncharged.This is because this is the lowest potential energy.
22DischargeExamples:Flash in cameraKeyboardsSize of capacitors video
23Stored Energy A charged capacitor stores electrical potential energy. If each plate is neutral, then it takes almost no work to move charges in the circuit.Once the plates start to build up a charge, a potential difference develops
24Stored EnergyThis requires more and more work to be done to move the charge through the pd.This builds the electric potential energy.The work done on these charges is the transfer of energy.
25Stored Energy This energy can be calculated by: Electric potential energy = ½ (charge on plate)(final potential difference)PEelectric = ½ Q ∆VBy substitution this can becomePEelectric = Q2/2CC= capacitance
26ExampleA capacitor, connected to a 12V battery, holds 36 μC of charge on each plate. What is the capacitance of the capacitor? How much electrical potential energy is stored in the capacitor?Identify your variables. Identify your equations. Watch your units.Answer: C = 3.0 x 10-6 μF, PE = 2.2 x 10-4 J
27Practice Pg 607 Practice B #1-4 1) a) 4.8 x 10-5 C, b) 4.5 x 10-6 J 2) a) 4.8 x 10-6 F, b) 5.4 x 10-6 J3) a) 9.00V b) 5.0 x C4) 1.13 x 108 m2, ???
29CURRENT So far static electricity (charges in electric fields) Static electricity isn’t very usefulMoving electricity IS!!
30CURRENT The movement of electric charge Could be positive or negative chargesUsed everywhereLights, radios, TV, air conditioners, Cars, computersBodies, discovered in mid 1700s.Luigi Galvani experimented next to a dissected frogCurrent transmit messages between muscles and brain
31CURRENT More specifically…. Imagine a cross section of wire Electrons are now moving through that wireCurrent is the rate these charges move
32CURRENTCurrent is the ratio of the amount of charge to the time interval∆q is amount of charge∆t is the time it takes these charges to pass a point
33CURRENTCurrent is the ratio of the amount of charge to the time interval∆q is amount of charge∆t is the time it takes these charges to pass a pointI = ∆q/∆tI = currentUnit is Ampere, A
34CURRENT ***Special note*** Current is the OPPOSITE direction of the movement of the negative charges.
35ExampleThe current in a light bulb is 0.835A. How long does it take for a total charge of 1.67C to pass through the filament of the bulb?Identify what you know. Identify what you want to know. Identify your correct equation.Answer: 2.00s
36Practice Pg 609 Practice C #2-5 Answers: 1) 400s 2) 1.00s 3) 600s 5) a) 2.6 x 10-3A, b) 1.6 x 1017 electronsc) 5.1 x 10-3A
37Drift VelocityWhen you flip the switch how fast do the lights come on? Instantaneously?Does this mean the electrons are moving at the speed of light?Not quite.
38Drift VelocityWhen you turn on the light the electron motion near the switch changes the electric field there.That change in the electric field then propagates throughout the wire at nearly the speed of light.The charges move much more slowly.
39Drift VelocityWhen these charges do move do they move in a straight line?Not quite. Sorry. Remember that electrons in a metallic bond jump from nucleus to nucleus.These jumps are random and sporadic.
40Drift Velocity What causes these crazy movements? As they move the individual atoms are vibrating. (see Brownian Movement)In these collisions energy is transferred, which causes more vibration and an increase in temperature. (think friction)
41Drift VelocityElectrons want to accelerate in this electrical field but can’t because of these collisions.Eventually things will balance out.Drift velocity is the net velocity of these individual movements.
42Drift Velocity So how fast does an electron really move??? In a wire with current 10A, the drift speed would be 2.46 x 10-4m/s.Meaning it would take about 68 minutes for it to travel 1 meter.
43Resistance5.1.6 – Define resistance – Apply the equation for resistance – State and apply Ohm’s Law
44Resistance What is a conductor? What is an insulator? What is a resistor?Is there a difference between an insulator and a resistor?Is there a difference between a conductor and a resistor?
45Resistance A resistor is a conductor. It’s just not a good conductor. Opposition to the motion of charge through a conductor is RESISTANCE.For many materials… resistance is constant over a wide rang of applied potential differences.
47ResistanceEarlier we learned that electrons do not move in straight-lines through conductors.This is because of collisions with the metal atoms.Anything that affect the number of collisions will also affect the materials resistance.Primarily 4 factors.LengthCross-sectional AreaMaterialTemperature
48Resistance Two are purely geometrical factors. Length – the longer the wire the more collisions which means more resistance.Cross-Sectional Area – a thinner wire physically restricts the path an electron can take, increasing the resistance.
49ResistanceMaterial – different material have different structures of atoms. Some are more conductive than others.Examples….Temperature – Temperature is a measure of how much an object’s atoms are vibrating. More vibrations means it’s harder for atoms to travel, which means more resistance.
50ResistanceThe relationship between resistance, voltage and current can be expressed by saying resistance is the ratio of potential difference to current.ORR = ∆V / ISI unit for resistance is ohm, Ω
51Ohm’s LawOhm’s law states that voltage will cause a current to flow through a resistor.Commonly stated as V = IRWatch Video:https://www.youtube.com/watch?v=zYS9kdS5 6l8
52Ohm’s LawOhm’s law states that voltage will cause a current to flow through a resistor.Commonly stated as V = IRWatch Video:https://www.youtube.com/watch?v=zYS9kdS5 6l8
53Electric current and resistance Three different types of conductorsOhmicFilament LampDiode
54Electric current and resistance Resistor is “ohmic” if the current flowing is proportional to the voltage across its ends.Metals are ohmic if the temperature is constant.Gives a straight line on I-V graphOhmic conductors obey “Ohm’s Law”
55Electric current and resistance The filament lamp gets hot as there is an creasing voltage. This means the resistance increases with higher voltages.
56Electric current and resistance DiodesLets very little ore no current flow until voltage reaches a threshold.0.6V is very commonOnce the threshold is met, there is essentially zero risistance and a large amount of current can flow.Act as a switch, only allowing current to flow in one direction.Can turn AC in to DC
57PracticeThe resistance of a steam iron is 19.0 Ω. What is the current in the iron when it is connected across a potential difference of 120V?Identify what you know. Identify what you are looking for. Identify your equations. Solve.Answer: 6.32Ω
58PracticeA 1.5V battery is connected to a small light bulb with a resistance of 3.5Ω. What is the current in the bulb?Identify what you know. Identify what you are looking for. Identify your equations. Solve.Answer: 0.43A
64Electric Circuits A path through which charges can flow. A schematic diagram is also called circuit diagram.All circuits must have a source of potential difference (ex… ), resistance, also called a “load” (ex… ), and some thing connecting them (ex… )It must be a continous/complete loop for the charges to flow and work.
65Short circuitsWith out a load, or resistance, the circuit has very little resistance to the movement of electrons.Happens when un-insulated wires connect accidentally.They heat up, could possible melt/spark/catch fire.
675.2.1Apply the equations for resistors in series.Ch 18, Sec 2, Practice A, SR pg656
68Current in series Break up into groups of two. Each group gets a battery/wire/bulbBuild a circuit.
69Current in series Break up into groups of two. Each group gets a battery/wire/bulbBuild a circuit.Combine and make both bulbs turn on.What happened to the second bulb?
70CurrentCharge is conserved…. Meaning that the charge that enters one bulb is the same amount of charge that exits in a given time interval
71CurrentOnly one path…. Meaning that charge that exits the first bulb is the same amount of charge that enters the second bulb in a given time interval
72CurrentCurrent is the amount of charge per time…. Meaning the current in bulb 1 is the same current in bulb 2.CONCLUSION: When many resistors are connected in series, the current in each resistor is the same!
73CurrentCONCLUSION: When many resistors are connected in series, the current in each resistor is the same!OR…. Current is constant in a series circuit
74ResistanceThe total current in a series circuit depends on how many resistors there are.To find the total current you must find the total resistance,Total resistance is called equivalent resistanceEquivalent resistance of a series combination of resistors is always greater than any individual resistance.Req = R1 + R2 + R3….
75Voltage in a seriesThe potential difference across the battery, ∆V, must equal the potential difference across the load, ∆V1 + ∆V2…,So ∆V = ∆V1 + ∆V2….CONCLUSTION: The total voltage is equal to the sum of all the individual voltages.
76Voltage in a series With a little substitution you get…. ∆V = IReq ∆V = ∆V1 + ∆V2 + ∆V3….∆V = IR1 + IR2 + IR3….and∆V1 = IR1 and ∆V2 = IR2 and ∆V3 = IR3
77Conclusions for a SERIES CIRCUIT Current is constant∆Vtotal = ∆V1 + ∆V2 + ∆V3 …..Req = R1 + R2 + R3 …..∆V1 = IR1 and ∆V2 = IR2 and ∆V3 = IR3
78PS What happens when you unscrew one of the light bulbs? They all go out. Why?Note: all elements MUST be connected for a series circuit to work.
79Sample Problem AA 9.0V battery is connected to four light bulbs. They have 2.0Ω, 4.0Ω, 5.0Ω and 7.0Ω resistance respectively. Find the equivalent resistance for the circuit and the current in the circuit.Draw a schematic. Label it. Identify what you need. Identify what you know. Solve.Answer: Req = 18.0Ω, I = 0.50A
80Practice as classA 12.0V storage battery is connected to three resistors, 6.75Ω, 15.3Ω, and 21.6Ω respectively. The resistors are joined in series.a) Calculate the equivalent resistance.b) What is the current in the circuit?Draw a schematic. Label it. Identify what you need. Identify what you know. Solve.Answer: Req = 43.65Ω, I = 0.27A
825.2.2Apply the equations for resistors in parallel.Ch 18, Sec 2, Practice B, SR pg 656
83Get back into those groups. Now make both bulbs turn on in a parallel circuit. Meaning one can be unscrewed and the other still stay on.
84What happens to the brightness of the bulbs as one is connected/disconnected? Resistors in parallel have the same potential differences across them.Meaning….∆Vtotal = ∆V1 = ∆V2 = ∆V3….
85Current in parallel circuits When the charges flow through the wire the reach one bulb first. Some move through the first bulb. Others move through the second bulb.If one bulb has less resistance, more charges move through that bulb. This is because that bulb offers less opposition to the flow of charges.
86Current in parallel circuits The sum of currents in parallel resistors is equal to the total current.I = I1 + I2 + I3 ….Based upon that and ∆V = IR…. I = ∆V/RSo …. (∆V/Req) = (∆V/R1) + (∆V/R2) + (∆V/R3) …
87Resistors in parallel Since ∆Vtotal = ∆V1 = ∆V2 = ∆V3…. And (∆V/Req) = (∆V/R1) + (∆V/R2) + (∆V/R3)We can then simplify to….(1/Req) = (1/R1) + (1/R2) + (1/R3)The total resistance must always be less than the smallest resistor!?!?
88Conclusions for a PARRALLES CIRCUIT Voltage is constantI = I1 + I2 + I3 ….(1/Req) = (1/R1) + (1/R2) + (1/R3)
89Sample Problem BA 9.0V battery is connected to four resistors in a parallel fashion. They include 7.0Ω, 5.0Ω, 4.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the total current in the circuit.Draw a schematic. Label it. Identify what you need. Identify what you know. Solve.Answer: Req = 0.917Ω, I = 9.8A
90Class PracticeThe potential difference across the equivalent resistance in sample problem B equals the potential difference across each of the individual parallel resistors. Calculate the value for the current in each resistor.Draw a schematic. Label it. Identify what you need. Identify what you know. Solve.Answer: 1.3A, 1.8A, 2.25A, 4.5A