2Don’t change your radius! Construction #1Construct a segment congruent to a given segment.This is our compass.Given:ABProcedure:1. Use a straightedge to draw a line. Call it l.Construct: XY = ABDon’t change your radius!2. Choose any point on l and label it X.3. Set your compass for radius AB and make a mark on the line where B lies. Then, move your compass to line l and set your pointer on X. Make a mark on the line and label it Y.lXY
3Construct an angle congruent to a given angle Construction #2Construct an angle congruent to a given angleACBGiven:Procedure:D1) Draw a ray. Label it RY.2) Using B as center and any radius, draw an arc intersecting BA and BC. Label the points of intersection D and E.EConstruct:3) Using R as center and the SAME RADIUS as in Step 2, draw an arc intersecting RY. Label point E2 the point where the arc intersects RYD2RY4) Measure the arc from D to E.E25) Move the pointer to E2 and make an arc that that intersects the blue arc to get point D26) Draw a ray from R through D2
4Bisector of a given angle? Construction #3How do I construct aBisector of a given angle?CABZGiven:XYProcedure:Using B as center and any radius, drawand arc that intersects BA at X and BC at point Y.2. Using X as center and a suitable radius, draw and arc.Using Y as center and the same radius, draw an arcthat intersects the arc with center X at point Z.3. Draw BZ.
5How do I construct a perpendicular bisector to a given segment? Construction #4How do I construct a perpendicularbisector to a given segment?XGiven:ABYProcedure:Using any radius greater than 1/2 AB, draw four arcs ofequal radii, two with center A and two with center B.Label the points of intersection X and Y.Draw XY
6Construction #5 How do I construct a perpendicular bisector to a given segment at a given point?ZGiven:CkXYProcedure:Using C as center and any radius, draw arcs intersectingk at X and Y.Using X as center and any radius greater than CX, draw an arc. Using Y as center and the same radius,draw and arc intersecting the arc with center X at Z.Draw CZ.
7Construction #6 How do I construct a perpendicular bisector to a given segment at a given point outside the line?kPGiven:XYZProcedure:Using P as center, draw two arcs of equal radii thatintersect k at points X and Y.Using X and Y as centers and a suitable radius, draw arcsthat intersect at a point Z.Draw PZ.
8Construction #7 How do I construct a line parallel to a given line through a given point?kP1lGiven:ABProcedure:Let A and B be two points on line k. Draw PA.At P, construct <1 so that <1 and <PAB are congruentcorresponding angles. Let l be the line containing theray you just constructed.
9Concurrent LinesIf the lines are Concurrent then they all intersect at the same point.The point of intersection is called the “point of concurrency”
10What are the 4 different types of concurrent lines for a triangle? Perpendicular bisectorsAngle bisectorsAltitudesMediansCircumcenterIncenterOrthocenterCentriodConcurrent LinesPoint of ConcurrencyCircumcenterSPOrthocenterSPIncenterSPCentroidSP
11Given a point on a circle, construct the tangent to the circle at the given point . Construction #8PROCEDURE:Given: Point A on circle O.1) Draw Ray OA2) Construct a perpendicular through OA at point A.53Now, using the same radius, construct arcs 5 & 6 using point P as the center so that they intersect arcs 3 & 4 to get points X & YConstruct arcs 3 & 4 using point Q as the center and any suitable radius (keep this radius)X3) Draw tangent line XY21OAQPConstruct arcs 1 and 2 using any suitable radius and A as the centerY64
12Construction #9Given a point outside a circle, construct a tangent to the circle from the given point.PROCEDURE:Given: point A not on circle O1) Draw OA.X312) Find the midpoint M of OA (perpendicular bisector of OA)3) Construct a 2nd circle with center M and radius MAMOA4) So you get points of tangency at X & Y where the arcs intersect the red circleConstruct arcs 1& 2 using a suitable radius greater than ½AO( keep this radius for the next step)Construct arcs 3& 4 using the same radius(greater than ½AO)You get arcs 5 & 65) Draw tangents AX & AYY42
13Construction #10 Given a triangle construct the circumscribed circle. PROCEDURE:Given: Triangle ABC78ABC561) Construct the perpendicular bisectors of the sides of the triangle and label the point of intersection F.3412Bisect segment BC; Using a radius greater than 1/2BC from point C construct arcs 5 & 6From point B construct arcs 7 & 8 and draw a line connecting the intersections of the arcs2) Set your compass pointer to point F and the radius to measure FC.F3) Draw the circle with center F , that passes through the vertices A, B, & CradiusNow construct the perpendicular bisector of segment AB and label point F, where the 3 lines meet.Bisect segment AC; Using a radius greater than 1/2AC from point C construct arcs 1 & 2From point A construct arcs 3 & 4 and draw a line connecting the intersections of the arcs
14Construction #11 Given a triangle construct the inscribed circle. PROCEDURE:Given: Triangle ABCABC1) Construct the angle bisectors of angles A, B, & C, to get a point of intersection and call it F2) Construct a perpendicular to side AC from point F, and label this point G.F3) Put your pointer on point F and set your radius to FG.4) Draw the circle using F as the center and it should be tangent to all the sides of the triangle.GXY
15Three congruent segments Remember you made 3 because you are dividing by 3, but if you wanted to divide by, say, 6 you would have to make 6 congruent parts on the ray and so on for 7,8,9…Construction #12Given a segment, divide the segment into a given number of congruent parts.Given: Segment ABPROCEDURE:Divide AB into 3 congruent parts.1) Construct ANY RAY from point A that’s not ABABDC2) Construct 3 congruent segments on the ray using ANY RADIUS starting from point A. Label the new points X, Y, & ZX3) Draw segment ZB and copy the angle AZB ( 1) to vertices X & YSo AC=CD=DBThree congruent segmentsY1Use any suitable radius that will give some distance between the points4) Draw the the rays from X & Y, they should be parallel to the segment ZB and divide AB into 3 congruent parts.ZRemember keep the same radius!!
16Construction #13Given three segments construct a fourth segment (x) so that the four segments are in proportion.abcGiven:Construct: segment x such thatacxbbxPROCEDURE:a1) Using your straight edge construct an acute angle of any measure.1N2) On the lower ray construct “a” and then “c “ from the end of “a”.c3) On the upper ray construct “b” and then connect the ends of “a & b”4) Next copy angle 1 at the end of “c” and then construct the parallel line
17Construction #14 X Given 2 segments construct their geometric mean. Make sure to set your radius to morethan 1/2NM then:Mark off 2 arcs from M. Keep the sameradius and mark off 2 more arcs from N,crossing the first two.Draw the perpendicular bisector PQthrough point OMark off 2 arcs from Y.Keep the same radius and mark off 2 more arcs from X, crossing the first two.abGiven:Construct: segment x such that:Mark off 2 equal distances on eitherside of point O using any radius andthen bisect this new segment(I used the distance from O to M,but remember any radius will do)axbThe orange segment is x the geometric mean between the lengths of a and bPROCEDURE:9731XQK1) Draw a ray and mark off a+b.2) Bisect a+b (XY) and label point M.65XYM3) Construct the circle with center M and radius = MY (or MX)aNOb4) Construct a perpendicular where segment “a” meets segment “b” (point O)81024PL
18The Meaning of LocusIf a figure is a locus then it is the set of all points that satisfy one or more conditions.The term “locus” is just a technical term meaning “a set of points”.So , a circle is a locus.Why??Because it is a set of points a given distance from a given point.
19What can a locus be??Remember it is a SET OF POINTS so if you recall the idea of sets from algebra it is possible for a set to be empty.So a set could be:The empty set. (no points fit the condition or conditions)A single point.Two points, three points….An infinite set of points. (like a line, circle, curve,…)