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Area under a graph Car travelling at 70 mph Area = This is the distance travelled, 140 miles 2  70 = 140 v mph t hours 0 2 70.

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Presentation on theme: "Area under a graph Car travelling at 70 mph Area = This is the distance travelled, 140 miles 2  70 = 140 v mph t hours 0 2 70."— Presentation transcript:

1 Area under a graph Car travelling at 70 mph Area = This is the distance travelled, 140 miles 2  70 = 140 v mph t hours

2 Car accelerating steadily from 0 to 45 mph in 10 seconds Area = Distance travelled = 110 yards = 110 v mph t seconds mph = = 22 yards per second 22

3 Car travelling between 2 sets of traffic lights 0 Area of A = t (s) v (ms -1 ) v ms -1 t seconds A A CC B B = 70 Area of C == 17 Area of B = = 13 Total Area = 5 Distance travelled = 70 metres

4 y x 0 a b Integration As  x  0 Integration is the inverse of differentiation. lim  x  0 A = As  A =  y  x A = xx y  y  x AA The gradient of the graph of A against x.

5 Rules of Integration = x y = 5x = 5 y = c = 0 Function Derivative Reverse to give integral = 5x y = = x 2 y = = x 3 y = + c

6 13 Example Find the area under y = 2x 3 - 9x x + 6 between x = 1 and x = 3 y x 0 y = 2x 3 - 9x x + 6 A = + 6x - 3x 3 + 6x  3 -3    1 -3   1 2 = = 22 square units

7 Distance = The distance travelled is 140 miles = 140 Car travelling at 70 mph v mph t hours Velocity-time graphs v = 70

8 Car accelerating steadily from 0 to 22 yd/s (45 mph) in 10s v yd/s t seconds gradient = v = 2.2t intercept = 0 = 2.2 Distance = The distance travelled is 110 yards = 110

9 Car travelling between 2 sets of traffic lights t v v ms -1 t seconds 0 12 Distance travelled = 72 metres v = 0.25t(12 - t) Distance = = 72


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