Presentation on theme: "Tuning in Action Dennis Shasha. Application Context Each record, when inserted, undergoes several tests to see where and how it should be inserted. Programmer."— Presentation transcript:
Application Context Each record, when inserted, undergoes several tests to see where and how it should be inserted. Programmer temptation is to treat each record separately and in a loop.
Starting Point Input relation consisting of records to be inserted, alloc. Stored procedure selects rows of alloc into local scalar variables in a loop and then processes each one based on conditions. The record itself may be involved in interior loops.
Example Suppose that extra_price is a scalar variable in the stored procedure derived from alloc.extra_price We have a condition of the form: if (extra_price > 0) then select x, y from R, S where R.A = S.B and R.C = extra_price
What Can We Do? If statement can be translated to where clause, possibly linked to an insert. select x, y, alloc.extra_price from alloc, R, S where R.A = S.B and alloc.extra_price = R.extra_price and R.extra_price > 0
Example 2 An input row translates into many output rows, one for each date between start_date and end_date. How does one generate several rows from a single one? One possibility: do it outside the database, but then interfaces change.
What Can One Do? Set up a table that holds only dates alldates. Then can insert as follows: insert V select alloc.id, alloc.etc, alldates.date from alloc, alldates where alloc.startdate <= alldates.date and alloc.enddate >= alldates.date
Example 3 Each date further gets different price values depending on the day of the week. If weekday(this_date) = 0 then price = Sunday_price
What Can We Do? If there is a record for each date, then again the if can be translated to a where update R set price = Sunday_price where weekday(this_date) = 0
Several updates Would need one update per day of week or even per date Better to have a table of prices S(mydate, price) with seven items and then do a join: update R set price = S.price from R, S where R.this_date = S.mydate
General Structure Issues For each row of alloc and each date, we call a stored procedure that does several joins and inserts. What should we attack first?
Your consent to our cookies if you continue to use this website.