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Liquids and Solids.

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Presentation on theme: "Liquids and Solids."— Presentation transcript:

1 Liquids and Solids

2

3 Phase Changes Solid to Liquid Melting Fusing
Ice melts at 0 degrees Celsius

4 Phase Changes Liquid to gas vaporization Evaporation Boiling
A vapor is the gas phase of a substance that is liquid at room temperature water boils at 100 degrees Celsius

5 Phase Changes Gas to Liquid Condensation
Water vapor condenses to water liquid at 100 degrees Celsius

6 Phase Changes Liquid to Solid solidification freezing Crystallization
water freezes at 0 degrees Celsius

7 Solid to Gas (skip liquid)
Phase Changes Solid to Gas (skip liquid) sublimation Dry ice (Solid carbon dioxide) sublimes into carbon dioxide gas at room temperature

8 Gas to Solid (skip liquid)
Phase Changes Gas to Solid (skip liquid) deposition Water vapor deposits into ice crystals on cold surfaces

9 Heating Curve

10 Heating Curve of Water

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12 Cooling Curve

13 Cooling Curve gas condensing liquid freezing solid

14 During a phase change: The temperature does not change (flat line)
Average kinetic energy does not change Potential Energy changes!

15 KE increases PE increases

16 Energy equations Q = mcΔt
Can only be used when there is no phase change occurring

17 Energy equations Q = mhf
Can only be used when there is melting or freezing occurring Hf is the heat of fusion (Notice there is no temperature term, since temp does not change)

18 Hv is the heat of vaporization
Energy equations Q = mhv Can only be used when there is boiling or condensing occurring Hv is the heat of vaporization (Notice there is no temperature term, since temp does not change)

19 Example # 1 Which equation would you use for this problem?
How many joules of heat are absorbed when 50 g of water is heated from 30.2 degrees C to 58.6 degrees C? Q = mcΔt

20 Answer Q = 50g x 4.18 J/goc x (58.6 – 30.2 oC) Q = 5936J

21 Example # 2 Which equation would you use for this problem?
How many joules of heat are required to melt 225 g of ice at 0 degrees C? Q = mHf

22 Answer Q = 225g x 334 J/g Q = 75,150 J Q = kJ

23 Example # 3 Which equation would you use for this problem?
How many joules of heat are required to vaporize 423 g of water at 100 degrees C? Q = mHv

24 Answer Q = 423g x 2260 J/g Q = 955,980 J Q = kJ

25 Why does boiling 1 g of water require so much more energy than melting 1 g of water?
Boiling = 2260 J/g Melting = 334 J/g

26 Lots of energy needed to separate the particles from liquid to gas


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