1. Common Core Standards Covered in this lesson: HSA-CED.A.2 --Create equations in two or more variables to represent relationships between quantities 8.F.A.3 Interpret the equation y=mx + b as defining a linear function, whose graph is a straight line

2. 1) Write an equation of a line in slope- intercept form that passes through the point (1, -2) and has a slope of 3.

3. Point Slope Form Equation: y – y 1 = m(x – x 1 ) Where m is the slope x 1 and y 1 are a point on the line Slope Intercept Form: y = mx + b Where m is the slope b is your y-intercept y – (-2) = 3(x – 1) y + 2 = 3x – 3 y = 3x – 5  y = 3x – 5  SLOPE INTERCEPT FORM

4. 2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).

5.  FIND SLOPE FIRST

6. 2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  Slope = -7  Select a point (you may pick either point you used to find the slope with) Let’s choose (-4, 5)

7. 2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  Now we have a slope (-7) and a point (-4, 5). Put equation in point slope form!

8. 2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  y – 5 = -7(x + 4)  Solve for y to get into slope- intercept form

9. 2. Find the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2).  y – 5 = -7(x + 4) y – 5 = -7x – 28 y = - 7x – 23 y = - 7x – 23

10. y = - 7x – 23 This is the equation of the line in slope- intercept form that passes through the points (-4, 5) and (-3, -2)