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Section 4.3 Pg. 169-171.  This often involves integrating two or more concepts.  I.e. Boyle’s and Charles’ Laws were combined to create the Combined.

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Presentation on theme: "Section 4.3 Pg. 169-171.  This often involves integrating two or more concepts.  I.e. Boyle’s and Charles’ Laws were combined to create the Combined."— Presentation transcript:

1 Section 4.3 Pg. 169-171

2  This often involves integrating two or more concepts.  I.e. Boyle’s and Charles’ Laws were combined to create the Combined Gas Law  Similarly, Avogadro’s Theory and the Mole concept can also be combined:  Avogadro: “Equal volumes of any gases at the same temperature and pressure contain equal numbers of entities”  Therefore, for all gases at a specific temperature and pressure, there must be a certain volume, the ___________________________, that contains one mole of entities  Molar Volume:

3  Molar volume is the ______________ for all gases at the same temperature and pressure (remember, all gases have the same physical properties)  At STP, molar volume = ________________(101.325 kPa and 0°C)  At SATP, molar volume = _______________(100 kPa and 25°C)  This can be used as a conversion factor just like molar mass! At STP, one mole of gas has a volume of 22.4 L, which is approximately the volume of 11 “empty” 2 L pop bottles. STP = 22.4L/mol SATP = 24.8 L/mol

4  Chemists created the concept of molar volume to convert between volume and chemical amount Molar Volume as a Conversion Factor V n litres mol Remember the conversion factor will be different at STP and SATP!

5  Why are we dealing with molar volume instead of molar mass???  It’s a lot ____________________ to measure the volume of a gas than trying to measure its mass.  You would have to trap the gas in a container and measure its mass on a balance and them make corrections for the buoyant force of the surrounding air... not easy

6 1. Calculate the volume occupied by 0.024 mol of carbon dioxide at SATP. 2. What chemical amount of oxygen is available for a combustion reaction in a volume of 5.6 L at STP? STP = 22.4L/mol SATP = 24.8 L/mol

7 3. What volume does 3.50 g of helium gas (He) occupy at SATP?  Once these calculations are clearly understood, they can be combined into a single calculation using unit analysis. All units except the final unit will cancel. STP = 22.4L/mol SATP = 24.8 L/mol

8 4. A propane tank for a barbecue contains liquefied propane. IF the tank mass drops by 9.1 kg after a month’s use, what volume of propane gas at SATP was used for cooking? Molar mass (M): C 3 H 8(g) =  What if I wanted your answer in litres? STP = 22.4L/mol SATP = 24.8 L/mol 5.1 kL x 1000L = 5100 L= 5.1 x 10 3 L 1 kL

9 STP = 22.4L/mol SATP = 24.8 L/mol Molar volume: the volume that one mole of a gas occupies at a specified temperature and pressure Homework: pg. 171 #5 - 12


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