1. Splash Screen

2. Then/Now You used similar triangles to measure distances indirectly. Solve problems involving angles of elevation and depression. Use angles of elevation and depression to find the distance between two objects.

3. Angle of Elevation: formed by a horizontal line and the observers line of sight to an object ABOVE the horizontal line Angle of Depression: formed by a horizontal line and the observers line of sight to an object BELOW the horizontal line

4. Example 1 Angle of Elevation CIRCUS ACTS At the circus, a person in the audience at ground level watches the high-wire routine. A 5-foot-6-inch tall acrobat is standing on a platform that is 25 feet off the ground. How far is the audience member from the base of the platform, if the angle of elevation from the audience member’s line of sight to the top of the acrobat is 27°?

5. Example 1 Angle of Elevation Since QR is 25 feet and RS is 5 feet 6 inches or 5.5 feet, QS is 30.5 feet. Let x represent PQ. Multiply both sides by x. Divide both sides by tan Simplify.

6. Example 1 A.37° B.35° C.40° D.50° DIVING At a diving competition, a 6-foot-tall diver stands atop the 32-foot platform. The front edge of the platform projects 5 feet beyond the ends of the pool. The pool itself is 50 feet in length. A camera is set up at the opposite end of the pool even with the pool’s edge. If the camera is angled so that its line of sight extends to the top of the diver’s head, what is the camera’s angle of elevation to the nearest degree?

7. Example 2 Angle of Depression DISTANCE Maria is at the top of a cliff and sees a seal in the water. If the cliff is 40 feet above the water and the angle of depression is 52°, what is the horizontal distance from the seal to the cliff, to the nearest foot? Make a sketch of the situation. Since are parallel, m  BAC = m  ACD by the Alternate Interior Angles Theorem.

8. Example 2 Angle of Depression Let x represent the horizontal distance from the seal to the cliff, DC. C = 52°; AD = 40, and DC = x Multiply each side by x.

9. Example 2 Angle of Depression Answer: The seal is about 31 feet from the cliff. Divide each side by tan 52°.

10. Example 2 A.19 ft B.20 ft C.44 ft D.58 ft Luisa is in a hot air balloon 30 feet above the ground. She sees the landing spot at an angle of depression of 34 . What is the horizontal distance between the hot air balloon and the landing spot to the nearest foot?

11. Example 3 Use Two Angles of Elevation or Depression DISTANCE Vernon is on the top deck of a cruise ship and observes two dolphins following each other directly away from the ship in a straight line. Vernon’s position is 154 meters above sea level, and the angles of depression to the two dolphins are 35° and 36°. Find the distance between the two dolphins to the nearest meter.

12. Example 3 Use Two Angles of Elevation or Depression UnderstandΔMLK and ΔMLJ are right triangles. The distance between the dolphins is JK or JL – KL. Use the right triangles to find these two lengths. PlanBecause are horizontal lines, they are parallel. Thus, and because they are alternate interior angles. This means that

13. Example 3 Use Two Angles of Elevation or Depression Multiply each side by JL. Divide each side by tan Use a calculator. Solve

14. Example 3 Use Two Angles of Elevation or Depression Answer: The distance between the dolphins is JK – KL. JL – KL ≈ 219.93 – 211.96, or about 8 meters. Multiply each side by KL. Use a calculator. Divide each side by tan

15. Example 3 A.14 ft B.24 ft C.37 ft D.49 ft Madison looks out her second-floor window, which is 15 feet above the ground. She observes two parked cars. One car is parked along the curb directly in front of her window and the other car is parked directly across the street from the first car. The angles of depression of Madison’s line of sight to the cars are 17° and 31°. Find the distance between the two cars to the nearest foot.

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