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Chapter 17 Rates of Reaction EQUILIBRIUM Collision Theory Reactions can occur: Very fast – such as a firecracker Very slow – such as the time it took.

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Presentation on theme: "Chapter 17 Rates of Reaction EQUILIBRIUM Collision Theory Reactions can occur: Very fast – such as a firecracker Very slow – such as the time it took."— Presentation transcript:

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2 Chapter 17 Rates of Reaction EQUILIBRIUM

3 Collision Theory Reactions can occur: Very fast – such as a firecracker Very slow – such as the time it took for dead plants to make coal A “rate” is a measure of the speed of any change that occurs within an interval of time In chemistry, reaction rate is expressed as the amount of reactant changing per unit time. https://www.youtube.com/watch?v=SbapBWjDA74 https://www.youtube.com/watch?v=SbapBWjDA74

4 Collision Model Key Idea: Molecules must collide to react. However, only a small fraction of collisions produces a reaction. Why? Particles lacking the necessary kinetic energy to react bounce apart unchanged when they collide https://www.youtube.com/watch?v=mBTSwJnZ6Sk

5 Collision Model Collisions must have enough energy to produce the reaction (must equal or exceed the activation energy – the minimum energy needed to react). Pushing a stalled car: it takes a lot of force to overcome the inertia. Once it is rolling, it becomes easy to push. https://www.youtube.com/watch?v=eSInI1xHv h4 https://www.youtube.com/watch?v=eSInI1xHv h4

6 Energy Reaction coordinate Reactants Products Activation Energy - Minimum energy to make the reaction happen

7 Collision Model An “activated complex” is an unstable arrangement of atoms that forms momentarily (typically about 10 - 13 seconds (femptasecond) at the peak of the activation-energy barrier. This is sometimes called the transition state Results in either a) forming products, or b) reformation of reactants Both outcomes are equally likely https://www.youtube.com/watch?v=7qOFtL3VEBc

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9 Collision Model  The collision theory explains why some naturally occurring reactions are very slow  Carbon and oxygen react when charcoal burns, but this has a very high activation energy  At room temperature, the collisions between carbon and oxygen are not enough to cause a reaction

10 Factors Affecting Rate 1) Temperature Increasing temperature always increases the rate of a reaction. 2) Surface Area Increasing surface area increases the rate of a reaction 3) Concentration Increasing concentration USUALLY increases the rate of a reaction 4) Presence of Catalysts

11 Catalysts Catalyst: A substance that speeds up a reaction, without being consumed itself in the reaction Enzyme: A large molecule (usually a protein) that catalyzes biological reactions. Human body temperature = 37 o C, much too low for digestion reactions without catalysts. Inhibitors – interfere with the action of a catalyst; reactions slow or even stop

12 Endothermic Reaction with a Catalyst https://www.youtube.com/watch?v=YacsIU97OFc

13 Exothermic Reaction with a Catalyst http://study.com/academy/lesson/activation-energy-and-catalysts.html

14 REACTION TYPE  HOMOGENOUS REACTION: Reactions with only 1 phase of matter: CH 4(g) +O 2(g)  CO 2(g) +H 2 O (g) HETEROGENOUS REACTION: Reaction with more than 1 phase of matter: Zn (s) + HCl (aq)  H 2(g) + ZnCl 2(aq)

15 FORWARD  REVERSE Up to now, we have assumed reactions go to completion. Meaning the reaction goes to product until 1 of the reactants runs out. Not true for some reactions. CHEMICAL EQUILIBRIUM IS REACHED WHEN THE EXACT BALANCE BETWEEN FORWARD AND REVERSE REACTIONS IS REACHED.

16 CHEMICAL EQUILIBRIUM N 2 O 4(g)  NO 2(g) +NO 2(g) Forward is always towards the product side. Reverse is always towards the reactant side. Dynamic Equilibrium: concentration of reactants and products remains constant as long as conditions remain unchanged. https://www.youtube.com/watch?v=g5wNg_dKsYY

17 Reversible Reactions Some reactions do not go to completion as we have assumed They may be reversible – a reaction in which the conversion of reactants to products and the conversion of products to reactants occur simultaneously Forward: 2SO 2(g) + O 2(g) → 2SO 3(g) Reverse: 2SO 2(g) + O 2(g) ← 2SO 3(g) http://study.com/academy/lesson/dynamic-equilibrium-physical-and-chemical.html 3

18 Reversible Reactions The two equations can be combined into one, by using a double arrow, which tells us that it is a reversible reaction: 2SO 2(g) + O 2(g) ↔ 2SO 3(g) A chemical equilibrium occurs, and no net change occurs in the actual amounts of the components of the system.

19 Reversible Reactions Even though the rates of the forward and reverse are equal, the concentrations of components on both sides may not be equal An equlibrium position may be shown: A B or A B 1% 99% 99% 1%  It depends on which side is favored; almost all reactions are reversible to some extent

20 Le Chatelier’s Principle  The French chemist Henri Le Chatelier (1850-1936) studied how the equilibrium position shifts as a result of changing conditions  Le Chatelier’s principle: If stress is applied to a system in equilibrium, the system changes in a way that relieves the stress https://www.youtube.com/watch?v=7zuUV455zFs Fuse 4.0

21 Le Chatelier’s Principle What items did he consider to be stress on the equilibrium: 1)Concentration 2)Temperature 3)Pressure Concentration – adding more reactant produces more product, and removing the product as it forms will produce more product Each of these will now be discussed in detail

22 Le Chatelier’s Principle Temperature – increasing the temperature causes the equilibrium position to shift in the direction that absorbs heat If heat is one of the products (just like a chemical), it is part of the equilibrium so cooling an exothermic reaction will produce more product, and heating it would shift the reaction to the reactant side of the equilibrium https://www.youtube.com/watch?v=XhQ02egUs5Y Fuse change in temp 3:22 https://www.youtube.com/watch?v=cHAjhM3y3ds Bozeman 3 https://www.youtube.com/watch?v=a8XPNE-y7UQ Change from stress 12;03

23 Le Chatelier’s Principle Pressure – changes in pressure will only effect gaseous equilibria Increasing the pressure will usually favor the direction that has fewer molecules N 2(g) + 3H 2(g) → 2NH 3(g) For every two molecules of ammonia made, four molecules of reactant are used up – the equilibrium shifts to the right with an increase in pressure. https://www.youtube.com/watch?v=PciV_Wuh9V8 Bozeman 7;00

24 PREDICT THE SHIFT IN EQUILBRIUM WHEN PRESSURE IS INCREASED/VOLUME IS REDUCED  N 2 (g) + 3H 2(g)  2NH 3 (g)  P 4 (s) + 6Cl 2 (g)   4PCl 3 (l)  PCl 3 (g) + Cl 2 (g)   PCl 5 (g)  PCl 3(g) + 3NH 3 (g)   P(NH 2 ) 3(g) + 3HCl (g) WHEN NH3 IS REMOVED N 2 (g) + 3H 2(g)  2NH 3 (g) PCl 3(g) + 3NH 3 (g)   P(NH 2 ) 3(g) + 3HCl (g) right No change right left

25 EQUILBRIUM ANALOGY Before the movie starts, people are filling up all the seats until they are full. The movie theater is at equilibrium when the movie starts. The same number of people are coming in as going out. The “people” remain constant. Equilbrium will Design an analogy which demonstrates before equilibrium and during equilibrium. Explain

26 Equilibrium Constants Law of chemical equilibrium: states that the equilibrium condition is demonstrated by the equilibrium expression. Chemists generally express the position of equilibrium in terms of numerical values These values relate to the amounts of reactants and products at equilibrium This is called the equilibrium constant, and abbreviated K eq https://www.youtube.com/watch?v=DP-vWN1yXrY Crash course 9.26

27 Measuring equilibrium At equilibrium the concentrations of products and reactants are constant. We can write a constant that will tell us where the equilibrium position is. K eq equilibrium constant K eq = [Products] coefficients [Products] coefficients [Reactants] coefficients [Reactants] coefficients Square brackets [ ] means concentration in Molarity (moles/liter)

28 Writing Equilibrium Expressions General equationaA + bB cC + dD K eq = [C] c [D] d [A] a [B] b Write the equilibrium expressions for the following reactions. 2H 2 O(g) 2H 2 (g) + O 2 (g) [H 2 ] 2 [O 2 ] [H 2 O] 2

29 Calculating Equilibrium Calculate the equilibrium constant for the following reaction. 3H 2 (g) + N 2 (g) 2NH 3 (g) if at 25ºC there 0.55 M of N 2, 0.30 M of NH 3, and 0.125 M of H 2 in a 1.0 L container. [.30] 2 = 83.782 (No Units) [.125] 3 [.55] If K eq > 1 Products are favored If K eq < 1 Reactants are favored https://www.youtube.com/watch?v=cHAjhM3y3ds Start 5

30 Heterogenous Equilibria  The concentrations of pure solids or liquids cannot be included in an equilibrium expression because their concentrations do not change.  Water is a pure liquid and it concentration is constant.  H 2 O (l)  O 2(g) +H 2(g)  K eq = [H 2 ] 2 [O 2 ]

31 WHAT TO KNOW FOR TEST  How to write a Keq expression.  How to solve for Keq  Pure solids and liquids are not included in Keq expressions.  Vocab words: equilibrium, forward reaction, reverse reaction LeChatlier’s principle, activation energy catalyst, collision theory, transition state, entropy, enthalpy, spontaneous reaction, endothermic and exothermic.  Which direction the reaction will go if pressure, temperature, or concentration is changed.  Keq>1 favors products and Keq<1favors reactants.  What is dynamic equilibrium  How to interpret graph.

32 Entropy Entropy is a measure of disorder, and is measured in units of J/mol. K; there are no negative values of entropy The law of disorder states the natural tendency is for systems to move to the direction of maximum disorder, not vice-versa Your room NEVER cleans itself (disorder to order?) An increase in entropy favors the spontaneous chemical reaction A decrease in entropy favors the nonspontaneous reaction http://www.youtube.com/watch?feature=player_embedded&v=CgppGozbFd4

33 Factors that affect Entropy Temperature – increase, Entropy increase Crushing or dividing a substance increases Entropy When a molecule changes state from solid to liquid to gas, entropy increases Entropy increases when the chemical reaction yields more product molecules than reactant. Ex. 2 H 2 O  2H 2 + O 2 http://www.sciencechannel.com/tv-shows/wonders-with-brian-cox/videos/wonders- of-the-universe-entropy/

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35 Your Mission Create an analogy for the Collision model. Product: 2 pictures showing the collision has enough energy to make it happen and a picture showing too little energy to make it happen. Use same analogy in both pics. Write a short description for each pic. https://www.youtube.com/watch?v=JtyByefOvgQ

36 COLLISION MODEL: My car ran out of gas and I have to push it to the gas station. I am pushing as hard as I can and the car will not move. My friends came by to help me push my car and now it is rolling. More energy was needed to make the car move.


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