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1 Welcome to 620-261 Introduction to Operations Research
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2 620-261: Introduction to Operations Research Lecturer: Moshe Sniedovich Room 150 Richard Berry Building Tel: 8344 5559 E-mail: – m.sniedovich@ms.unimelb.edu.au
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3 Schedule Lectures: Mon, Wed, Friday 3:15 PM Tutorial: Check Notice Board and Web site
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4 Office Hours Monday 2-3 -PM Wednesday 11AM-12PM Friday 2-3PM Other times by appointment Walk in......
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5 Assessment Assignments (weekly): – 10% Final Exam: – 90% Class Performance: – on the fly
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6 Group Projects Your are encouraged to study with friends, but you are expected to compose your own reports.
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7 Communication You are expected to respond to questions asked (by the lecturer) during the lectures Suggestions, comments, complaints: – Directly to lecturer – via Student Representative Don’t wait till you are asked to complain!
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8 Lecture Notes On Sale (Book Room) Limited supply If out-of-print, let us know
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9 Thou Shall Not
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10 Thou Shall Not
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11 Thou Shall Not
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12 Thou Shall Not
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13 Thou Shall Not
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14 Thou Shall Not
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15 Thou Shall Not
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16 Student Representative (SSLC) Pizza!!!!! Two meetings Questionnaire
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17 Web Site http://www.ms.unimelb.edu.au/~moshe/620-261/
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18 Reference Material Lecture Notes Bibliography (10 copies of Winston in Maths library, reserved Shelves) Hand-outs
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19 Computer Literacy
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20 Perspective Universe Applied maths OR 620-261
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21 What is OR ? Controversial question! Surf the WWW for answers Roughly: –.... Applications of quantitative scientific methods to decisions making and support in business, industrial and military organisations, with an objective of improving the quality of managerial decisions.....
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22 Basic Characteristics Applies Scientific methods Adopts a Systems Approach Utilises a team concept Relies on computer technologies
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23 Computers in OR Management Information Systems (MIS) Database Management (DBM) Decision Support Systems (DSS) Expert Systems (ES) Artificial Intelligence (AI) Geographic Information Systems (GIS)
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24 OR Stream 620-261: Introduction to Operations Research 620-262: Decision Making 620-361: Operations Research Methods and Algorithms 620-362: Applied Operations Research
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25 and more Honours MSc PhD Related topics in statistics
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26 Jobs
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27 Reading..... Appendix A Appendix B Appendix E Chapters 1,2,3,4 Web
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28 The OR Problem Solving Schema Solution Formulation Realization Modelling Analysis Implementation Monitoring
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29 In Practice Solution Formulation Realization Modelling Analysis Implementation Monitoring
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30 Important Comment In 620-261: Formulation and Modelling Analysis and Solution
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31 Introducing....
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32 Chapter 2: Optimization Problems General formulation f Objective function x Decision variable Decision Space opt Optimality criterion z* Optimal return/cost
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33 Observe the distinction between f and f(x). Note that f is assumed to be a real valued function on .
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34 Example
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36 We let * denote the set of optimal decisions associated with the optimization problem. That is * denotes the subset of whose elements are optimal solution to the optimization problem. Formally, *:={x*: x* , f(x*)=opt {f(x): x }}. By construction * is a subset of , namely optimality entails feasibility.
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37 Remarks The set of feasible solution, , is usually defined by a system of constraints. Thus, an optimization problem has three ingredients: – Objective function – Constraints – Optimality Criterion
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38 Classification of Optimal Solutions Consider e case where opt=min. Then by definition: x* * iff f(x*) f(x) x If opt=max: x* * iff f(x*) ≥ f(x) x Solutions of this type are called global optimal solutions.
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39 f(x) Global max Global min X
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40 Question: How do we solve optimization problems of this type? Answer: There are no general purpose solution methods. The methods used are very much problem-dependent.
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41 Suggestion Try to think about optimization problems is terms of the format: Z*:= opt f(x) s.t.----------------------------- ----------------------------- constraints -----------------------------
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42 Thus......... Modelling = opt = ? f(x) = ? Constraints = ?
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43 Tip You may find it useful to adopt the following approach: Step 1: Identify and formulate the decision variables. Step 2: Formulate the objective function and optimality criterion. Step 3: Formulate the constraints. But do not be dogmatic about it !!!!!
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44 Example 2.4.2 False Coin Problem N coins N-1 have the same weight (“good”) 1 is heavier (“false”) Find the best weighing scheme using a balance beam.
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45 Observations It does not make sense to put a different number of coins on each side of the scale. The result of any non-trivial weighing must fall into exactly one of the following cases: – False coin is on the left-hand side – False coin is on the right-hand side – False coin is not on the scale
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46 The scheme should tell us what to do at each “trial”, i.e. how many coins to place on each side of the scale, depending on how many coins are still to be inspected. The term “Best” needs some clarification:
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47 Best = ??? “Best” = “fewest number of weighings” is not well defined because a priori we don’t know how many weighings will be needed by a given scheme. This is so because we do not know where the false coin will be placed. The bottom line: who decides where the false coin will be as we implement the weighing scheme ?
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48 We need help!!! Many of the difficulties are nicely resolved if we assume that Mother Nature Always Plays Against Us! Of course, if you are an optimist you may prefer to assume that Mother Nature Always Plays in Our Favour!
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49 Assumption Mother Nature Always Plays Against Us ! Observe that this assumption resolves the question of where the false coin will be. Nature will always select the largest of (n L,n R,n o ) nLnL nRnR nono
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50 Solution Let n := Number of weighings required to identify the false coin. x j := Number of coins placed on each side of the scale in the j-th weighing (j=1,2,3,...,n)
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51 Thus, our objective function is f(x 1,x 2,...,x n ):= n and opt=min. To complete the formulation of the problem we have to determine .
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52 Constraints Let s j := Number of coins left for inspection after the j-th weighing (j = 0,1,2,...,n) Then clearly, s 0 := N (All coins are yet to be inspected) s n := 1 (Only false coin is left for inspection)
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53 x j {0,1,2,...,Int((s j-1 )/2)} where Int(z):= Integer part of z.
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54 Dynamics = ???? We have to specify the dynamics of the process: how the {s j } are related to the {x j }. This is not difficult because we assume that Nature Plays Against Us: s j = max {x j, s j-1 -2x j } xjxj xjxj s j-1 -2x j
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55 xjxj xjxj s j-1 -2x j j-th weighing: (j-1) weighing: s j-1 coins left s j = max {x j, s j-1 -2x j }
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56 Complete Formulation (Erase N)
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57 Complete Formulation
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58 Comments This problem is a good example of a situation where it is much easier to solve the problem than to formulate it mathematically. Make sure that you fully understand and appreciate the difference between “solving” and “formulating” a problem.
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59 Examples of OR Problems Example 2.4.6 Towers of Hanoi Task: Move the discs from left to right Rules: – One disc at a time – No large disc on a small one
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60 Example 2.4.4 Travelling Salesman Problem Visit N cities, starting the tour and terminating it in the home city such that: Each city (except the home city) is visited exactly once The tour is as short as possible. Question: What is the optimal tour?
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61 Remark: There are (N-1)! distinct tours. This means that for 11 cities there are 3,628,800 possible tours and for N=21 cities there are 2x10 18 possible tours !!!!!!!!!!!!!!!
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62 If we try to enumerate all the feasible tours for N=21 using a super fast computer capable of enumerating 1,000,000,000 tours per second, we will complete the enumeration of all the feasible tours in approximately 800 years. This phenomenon is known as The Curse of Dimensionality!
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