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Aldehydes and ketones: nucleophilic addition reactions.

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Presentation on theme: "Aldehydes and ketones: nucleophilic addition reactions."— Presentation transcript:

1 Aldehydes and ketones: nucleophilic addition reactions

2 Aldehydes and ketones contain a carbonyl group, C=O.

3 Oxygen is a very electronegative element and the C=O bond is highly polar.

4 Nucleophiles can attack the partially positively charged carbon atom.

5 A covalent bond forms between the nucleophile and the carbon atom.

6 A pair of electrons from the carbon–oxygen double bond moves to the oxygen atom.

7 A carbon–oxygen single bond forms and the oxygen atom gains a negative charge.

8 A covalent bond forms between the oxygen atom and a hydrogen ion, H +. This ion can come from the solvent, water.

9 A hydroxyl group forms in the final product.

10 This is a general mechanism for nucleophilic addition in carbonyl compounds.

11 Let's look at the mechanism of the reaction between a carbonyl compound and the cyanide ion, CN –.

12 Oxygen is a very electronegative element and the C=O bond is highly polar.

13 The cyanide ion has a lone pair of electrons on its carbon atom. It acts as a nucleophile and it can attack the partially positively charged carbon atom.

14 A covalent bond forms between the cyanide ion and the carbon atom.

15 A pair of electrons from the carbon–oxygen double bond moves to the oxygen atom.

16 A carbon–oxygen single bond forms and the oxygen atom gains a negative charge.

17 A covalent bond forms between the oxygen atom and a hydrogen ion, H +. This ion can come from the solvent, water.

18 A hydroxyl group forms.

19 The final product is a hydroxynitrile.

20 Let’s look at the reaction mechanism when the carbonyl compound is an aldehyde, ethanal.

21 The final product is 2-hydroxypropanenitrile. It contains an asymmetric carbon atom and shows optical isomerism.

22 Let’s look at the reaction mechanism when the carbonyl compound is a ketone, propanone. The final product is 2-hydroxy-2-methylpropanenitrile, which does not show optical isomerism.

23 Let's look at the mechanism of the reaction between an aldehyde, ethanal, and a reducing agent such as sodium tetrahydridoborate(lll), NaBH 4.

24 Oxygen is a very electronegative element and the C=O bond is highly polar.

25 The BH – ion provides the hydride ion, H –. This has a lone pair of electrons and it acts as a nucleophile. It can attack the partially positively charged carbon atom.

26 A covalent bond forms between the hydride ion and the carbon atom.

27 A pair of electrons from the carbon–oxygen double bond moves to the oxygen atom.

28 A carbon–oxygen single bond forms and the oxygen atom gains a negative charge.

29 A covalent bond forms between the oxygen atom and a hydrogen ion from water, the solvent.

30 A hydroxyl group forms.

31 The final product is a primary alcohol, in this case ethanol.

32 This is the reaction mechanism when the carbonyl compound is a ketone, propanone. The final product is a secondary alcohol, in this case propan-2-ol.


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