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 2008 Pearson Education, Inc. All rights reserved. 1 4 4 Control Statements: Part 1.

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1  2008 Pearson Education, Inc. All rights reserved. 1 4 4 Control Statements: Part 1

2  2008 Pearson Education, Inc. All rights reserved. 2 4.1 Introduction 4.2 Algorithms 4.3 Pseudocode 4.4 Control Structures 4.5 if Selection Statement 4.6 if...else Double-Selection Statement 4.7 while Repetition Statement 4.8 Formulating Algorithms: Counter-Controlled Repetition 4.9 Formulating Algorithms: Sentinel-Controlled Repetition 4.10 Formulating Algorithms: Nested Control Statements 4.11 Assignment Operators 4.12 Increment and Decrement Operators

3  2008 Pearson Education, Inc. All rights reserved. 3 4.1 Introduction Before writing a program – Have a thorough understanding of the problem – Carefully plan your approach for solving it While writing a program – Know what “building blocks” are available – Use good programming principles

4  2008 Pearson Education, Inc. All rights reserved. 4 4.2 Algorithms Algorithms – Specify the actions to execute – Specify the order in which these actions execute Program control – Specifies the order in which actions execute in a program – Are performed in C++ with control statements

5  2008 Pearson Education, Inc. All rights reserved. 5 4.3 Pseudocode Pseudocode – Artificial, informal language used to develop algorithms Used to “think out” a program before coding it – Easy to convert into a C++ program – Similar to everyday English Only executable statements – No need to declare variables – Not executed on computers

6  2008 Pearson Education, Inc. All rights reserved. 6 Fig. 4.1 | Pseudocode for the addition program of Fig. 2.5.

7  2008 Pearson Education, Inc. All rights reserved. 7 4.4 Control Structures Sequential execution – Statements executed in sequential order Transfer of control – Next statement executed is not the next one in sequence Structured programming – Eliminated goto statements

8  2008 Pearson Education, Inc. All rights reserved. 8 4.4 Control Structures (Cont.) Only three control structures are needed – No goto statements – Demonstrated by Böhm and Jacopini – Three control structures Sequence structure – Programs executed sequentially by default Selection structures – if, if…else, switch Repetition structures – while, do…while, for

9  2008 Pearson Education, Inc. All rights reserved. 9 4.4 Control Structures (Cont.) Single-entry/single-exit control statements – Three types of control statements Sequence statement Selection statements Repetition statements – Combined in one of two ways Control statement stacking – Connects exit point of one to entry point of the next Control statement nesting

10  2008 Pearson Education, Inc. All rights reserved. 10 Fig. 4.3 | C++ keywords.

11  2008 Pearson Education, Inc. All rights reserved. 11 Common Programming Error 4.1 Using a keyword as an identifier is a syntax error.

12  2008 Pearson Education, Inc. All rights reserved. 12 Common Programming Error 4.2 Spelling a keyword with any uppercase letters is a syntax error. All of C++’s keywords contain only lowercase letters.

13  2008 Pearson Education, Inc. All rights reserved. 13 Software Engineering Observation 4.1 Any C++ program we’ll ever build can be constructed from only seven different types of control statements (sequence, if, if... else, switch, while, do... while and for ) combined in only two ways (control-statement stacking and control-statement nesting).

14  2008 Pearson Education, Inc. All rights reserved. 14 4.5 if Selection Statement Selection statements – Choose among alternative courses of action – Pseudocode example If student’s grade is greater than or equal to 60 Print “Passed” – If the condition is true Print statement executes, program continues to next statement – If the condition is false Print statement ignored, program continues – Indenting makes programs easier to read C++ ignores white-space characters

15  2008 Pearson Education, Inc. All rights reserved. 15 4.5 if Selection Statement (Cont.) Selection statements (Cont.) – Translation into C++ if ( grade >= 60 ) cout << "Passed"; – Any expression can be used as the condition If it evaluates to false, it is treated as false

16  2008 Pearson Education, Inc. All rights reserved. 16 Portability Tip 4.1 For compatibility with earlier versions of C, which used integers for Boolean values, the bool value true also can be represented by any nonzero value (compilers typically use 1) and the bool value false also can be represented as the value zero.

17  2008 Pearson Education, Inc. All rights reserved. 17 4.6 if…else Double-Selection Statement if – Performs an action if the condition true if…else – Performs one action if the condition is true, and a different action if the condition is false Pseudocode – If student’s grade is greater than or equal to 60 print “Passed” Else print “Failed” C++ code if ( grade >= 60 ) cout << "Passed"; else cout << "Failed";

18  2008 Pearson Education, Inc. All rights reserved. 18 4.6 if…else Double-Selection Statement (Cont.) Ternary conditional operator ( ?: ) – Three arguments (condition, value if true, value if false ) Code could be written: cout = 60 ? “Passed” : “Failed” ); ConditionValue if trueValue if false

19  2008 Pearson Education, Inc. All rights reserved. 19 4.6 if…else Double-Selection Statement (Cont.) Nested if…else statements – One inside another, test for multiple cases – Once a condition met, other statements are skipped – Example If student’s grade is greater than or equal to 90 Print “A” Else If student’s grade is greater than or equal to 80 Print “B” Else If student’s grade is greater than or equal to 70 Print “C” Else If student’s grade is greater than or equal to 60 Print “D” Else Print “F”

20  2008 Pearson Education, Inc. All rights reserved. 20 4.6 if…else Double-Selection Statement (Cont.) Nested if…else statements (Cont.) – Written In C++ if ( studentGrade >= 90 ) cout = 80 ) cout = 70 ) cout = 60 ) cout << "D"; else cout << "F";

21  2008 Pearson Education, Inc. All rights reserved. 21 4.6 if…else Double-Selection Statement (Cont.) Nested if…else statements (Cont.) – Written In C++ (indented differently) if ( studentGrade >= 90 ) cout = 80 ) cout = 70 ) cout = 60 ) cout << "D"; else cout << "F";

22  2008 Pearson Education, Inc. All rights reserved. 22 Performance Tip 4.1 A nested if...else statement can perform much faster than a series of single-selection if statements because of the possibility of early exit after one of the conditions is satisfied.

23  2008 Pearson Education, Inc. All rights reserved. 23 4.6 if…else Double-Selection Statement (Cont.) Dangling- else problem – Compiler associates else with the immediately preceding if – Example if ( x > 5 ) if ( y > 5 ) cout 5"; else cout << "x is <= 5"; – Compiler interprets as if ( x > 5 ) if ( y > 5 ) cout 5"; else cout << "x is <= 5";

24  2008 Pearson Education, Inc. All rights reserved. 24 4.6 if…else Double-Selection Statement (Cont.) Dangling- else problem (Cont.) – Rewrite with braces ( {} ) if ( x > 5 ) { if ( y > 5 ) cout 5"; } else cout << "x is <= 5"; – Braces indicate that the second if statement is in the body of the first and the else is associated with the first if statement

25  2008 Pearson Education, Inc. All rights reserved. 25 4.6 if…else Double-Selection Statement (Cont.) Compound statement – Also called a block Set of statements within a pair of braces Used to include multiple statements in an if body – Example if ( studentGrade >= 60 ) cout << "Passed.\n"; else { cout << "Failed.\n"; cout << "You must take this course again.\n"; } – Without braces, cout << "You must take this course again.\n"; always executes

26  2008 Pearson Education, Inc. All rights reserved. 26 Software Engineering Observation 4.2 A block can be placed anywhere in a program that a single statement can be placed.

27  2008 Pearson Education, Inc. All rights reserved. 27 Common Programming Error 4.3 Forgetting one or both of the braces that delimit a block can lead to syntax errors or logic errors in a program.

28  2008 Pearson Education, Inc. All rights reserved. 28 4.6 if…else Double-Selection Statement (Cont.) Empty statement – A semicolon ( ; ) where a statement would normally be – Performs no action – Also called a null statement

29  2008 Pearson Education, Inc. All rights reserved. 29 Common Programming Error 4.4 Placing a semicolon after the condition in an if statement leads to a logic error in single- selection if statements and a syntax error in double-selection if...else statements (when the if part contains an actual body statement).

30  2008 Pearson Education, Inc. All rights reserved. 30 4.7 while Repetition Statement Repetition statement – Action repeated while some condition remains true – Pseudocode While there are more items on my shopping list Purchase next item and cross it off my list – while loop repeats until condition becomes false – Example int product = 3; while ( product <= 100 ) product = 3 * product;

31  2008 Pearson Education, Inc. All rights reserved. 31 Common Programming Error 4.5 Not providing, in the body of a while statement, an action that eventually causes the condition in the while to become false normally results in a logic error called an infinite loop, in which the repetition statement never terminates. This can make a program appear to “hang” or “freeze” if the loop body does not contain statements that interact with the user.

32  2008 Pearson Education, Inc. All rights reserved. 32 4.8 Formulating Algorithms: Counter- Controlled Repetition Problem statement A class of ten students took a quiz. The grades (integers in the range 0 to 100) for this quiz are available to you. Calculate and display the total of all student grades and the class average on the quiz. Counter-controlled repetition – Loop repeated until counter reaches certain value – Also known as definite repetition Number of repetitions is known beforehand

33  2008 Pearson Education, Inc. All rights reserved. 33 4.8 Formulating Algorithms: Counter- Controlled Repetition (Cont.) Counter-controlled repetition (Cont.) – Counter variable Used to count – In example, indicates which of the 10 grades is being entered – Total variable Used to accumulate the sum of several values Normally initialized to zero beforehand – Otherwise it would include the previous value stored in that memory location

34  2008 Pearson Education, Inc. All rights reserved. 34 Software Engineering Observation 4.3 Experience has shown that the most difficult part of solving a problem on a computer is developing the algorithm for the solution. Once a correct algorithm has been specified, the process of producing a working C++ program from the algorithm is normally straightforward.

35  2008 Pearson Education, Inc. All rights reserved. 35 Fig. 4.7 | Pseudocode algorithm that uses counter-controlled repetition to solve the class average problem.

36  2008 Pearson Education, Inc. All rights reserved. 36 Outline fig04_08.cpp (1 of 1) Function determineClassAverage implements the class average algorithm described by the pseudocode

37  2008 Pearson Education, Inc. All rights reserved. 37 Outline fig04_09.cpp (1 of 3) If course name was longer than 25 characters, select first 25 characters

38  2008 Pearson Education, Inc. All rights reserved. 38 Outline fig04_09.cpp (2 of 3) Function determineClassAverage implements the class average algorithm described by the pseudocode Declare counter variable gradeCounter Declare total variable total

39  2008 Pearson Education, Inc. All rights reserved. 39 Outline fig04_09.cpp (3 of 3) Initialize the counter variable gradeCounter to 1 Continue looping as long as gradeCounter ’s value is less than or equal to 10 Increment counter by 1, which causes gradeCounter to exceed 10 eventually Perform the averaging calculation and assign its result to the variable average Initialize the total variable total to 0 Add the current grade to total

40  2008 Pearson Education, Inc. All rights reserved. 40 Outline fig04_10.cpp (1 of 1)

41  2008 Pearson Education, Inc. All rights reserved. 41 4.8 Formulating Algorithms: Counter- Controlled Repetition (Cont.) Uninitialized variables – Contain “garbage” (or undefined) values Notes on integer division and truncation – Integer division When dividing two integers performs truncation – Fractional part of the resulting quotient is lost

42  2008 Pearson Education, Inc. All rights reserved. 42 Common Programming Error 4.6 Not initializing counters and totals can lead to logic errors.

43  2008 Pearson Education, Inc. All rights reserved. 43 Error-Prevention Tip 4.2 Initialize each counter and total, either in its declaration or in an assignment statement. Totals are normally initialized to 0. Counters are normally initialized to 0 or 1, depending on how they are used (we will show examples of when to use 0 and when to use 1).

44  2008 Pearson Education, Inc. All rights reserved. 44 Common Programming Error 4.7 Assuming that integer division rounds (rather than truncates) can lead to incorrect results. For example, 7  4, which yields 1.75 in conventional arithmetic, truncates to 1 in integer arithmetic, rather than rounding to 2.

45  2008 Pearson Education, Inc. All rights reserved. 45 Common Programming Error 4.8 Using a loop’s counter-control variable in a calculation after the loop often causes a common logic error called an off-by-one-error. In a counter-controlled loop that counts up by one each time through the loop, the loop terminates when the counter’s value is one higher than its last legitimate value (i.e., 11 in the case of counting from 1 to 10).

46  2008 Pearson Education, Inc. All rights reserved. 46 4.9 Formulating Algorithms: Sentinel- Controlled Repetition Problem statement Develop a class average program that processes grades for an arbitrary number of students each time it is run. Sentinel-controlled repetition – Also known as indefinite repetition – Use a sentinel value Indicates “end of data entry” A sentinel value cannot also be a valid input value Also known as a signal, dummy or flag value

47  2008 Pearson Education, Inc. All rights reserved. 47 Common Programming Error 4.9 Choosing a sentinel value that is also a legitimate data value is a logic error.

48  2008 Pearson Education, Inc. All rights reserved. 48 4.9 Formulating Algorithms: Sentinel- Controlled Repetition (Cont.) Top-down, stepwise refinement – Development technique for well-structured programs – Top step Single statement conveying overall function of the program Example – Determine the class average for the quiz – First refinement Multiple statements using only the sequence structure Example – Initialize variables – Input, sum and count the quiz grades – Calculate and print the total of all student grades and the class average

49  2008 Pearson Education, Inc. All rights reserved. 49 Software Engineering Observation 4.4 Each refinement, as well as the top itself, is a complete specification of the algorithm; only the level of detail varies.

50  2008 Pearson Education, Inc. All rights reserved. 50 Software Engineering Observation 4.5 Many programs can be divided logically into three phases: an initialization phase that initializes the program variables; a processing phase that inputs data values and adjusts program variables (such as counters and totals) accordingly; and a termination phase that calculates and outputs the final results.

51  2008 Pearson Education, Inc. All rights reserved. 51 Common Programming Error 4.10 An attempt to divide by zero normally causes a fatal runtime error.

52  2008 Pearson Education, Inc. All rights reserved. 52 4.9 Formulating Algorithms: Sentinel- Controlled Repetition (Cont.) Top-down, stepwise refinement (Cont.) – Second refinement Commit to specific variables Use specific control structures Example in Fig. 4.11 Fatal logic error – Could cause the program the fail Often called “bombing” or “crashing” – Division by zero is normally a fatal logic error

53  2008 Pearson Education, Inc. All rights reserved. 53 Fig. 4.11 | Class average problem pseudocode algorithm with sentinel-controlled repetition.

54  2008 Pearson Education, Inc. All rights reserved. 54 4.9 Formulating Algorithms: Sentinel- Controlled Repetition (Cont.) Floating-point numbers – A real number with a decimal point – C++ provides data types float and double double numbers can have larger magnitude and finer detail – Called precision Floating-point constant values are treated as double values by default – Floating-point values are often only approximations

55  2008 Pearson Education, Inc. All rights reserved. 55 Outline fig04_12.cpp (1 of 1)

56  2008 Pearson Education, Inc. All rights reserved. 56 Outline fig04_13.cpp (1 of 4) fixed forces output to print in fixed point format (not scientific notation) and forces trailing zeros and decimal point to print setprecision stream manipulator (in header ) sets numeric output precision

57  2008 Pearson Education, Inc. All rights reserved. 57 Outline fig04_13.cpp (2 of 4)

58  2008 Pearson Education, Inc. All rights reserved. 58 Outline fig04_13.cpp (3 of 4) Function determineClassAverage implements the class average algorithm described by the pseudocode Declare local int variables total, gradeCounter and grade, and double variable average while loop iterates as long as grade does not equal the sentinel value -1

59  2008 Pearson Education, Inc. All rights reserved. 59 Outline fig04_13.cpp (4 of 4) Calculate average grade using static_cast to perform explicit conversion

60  2008 Pearson Education, Inc. All rights reserved. 60 Outline fig04_14.cpp (1 of 1)

61  2008 Pearson Education, Inc. All rights reserved. 61 4.9 Formulating Algorithms: Sentinel- Controlled Repetition (Cont.) Unary cast operator – Creates a temporary copy of its operand with a different data type Example – static_cast ( total ) Creates temporary floating-point copy of total – Explicit conversion Promotion – Converting a value (e.g. int ) to another data type (e.g. double ) to perform a calculation – Implicit conversion

62  2008 Pearson Education, Inc. All rights reserved. 62 Common Programming Error 4.13 The cast operator can be used to convert between fundamental numeric types, such as int and double, and between related class types (as we discuss in Chapter 13, Object-Oriented Programming: Polymorphism). Casting to the wrong type may cause compilation errors or runtime errors.

63  2008 Pearson Education, Inc. All rights reserved. 63 4.9 Formulating Algorithms: Sentinel- Controlled Repetition (Cont.) Formatting floating-point numbers – Parameterized stream manipulator setprecision Specifies number of digits of precision to display to the right of the decimal point Default precision is six digits – Nonparameterized stream manipulator fixed Indicates that floating-point values should be output in fixed- point format – As opposed to scientific notation (3.1 × 10 3 ) – Stream manipulator showpoint Forces decimal point to display

64  2008 Pearson Education, Inc. All rights reserved. 64 4.10 Formulating Algorithms: Nested Control Statement Problem statement A college offers a course that prepares students for the state licensing exam for real estate brokers. Last year, ten of the students who completed this course took the exam. The college wants to know how well its students did on the exam. You have been asked to write a program to summarize the results. You have been given a list of these 10 students. Next to each name is written a 1 if the student passed the exam or a 2 if the student failed. Your program should analyze the results of the exam as follows: 1. Input each test result (i.e., a 1 or a 2). Display the prompting message “Enter result” each time the program requests another test result. 2. Count the number of test results of each type. 3. Display a summary of the test results indicating the number of students who passed and the number who failed. 4. If more than eight students passed the exam, print the message “Raise tuition.”

65  2008 Pearson Education, Inc. All rights reserved. 65 4.10 Formulating Algorithms: Nested Control Statement (Cont.) Notice that – Program processes 10 results Fixed number, use counter-controlled loop – Each test result is 1 or 2 If not 1, assume 2 – Two counters can be used One counts number that passed Another counts number that failed – Must decide whether more than eight students passed

66  2008 Pearson Education, Inc. All rights reserved. 66 4.10 Formulating Algorithms: Nested Control Statement (Cont.) Top level outline – Analyze exam results and decide whether tuition should be raised First refinement – Initialize variables Input the 10 exam results and count passes and failures Print a summary of the exam results and decide whether tuition should be raised Second Refinement – Initialize variables to Initialize passes to zero Initialize failures to zero Initialize student counter to one

67  2008 Pearson Education, Inc. All rights reserved. 67 4.10 Formulating Algorithms: Nested Control Statement (Cont.) Second Refinement (Cont.) – Input the ten exam results and count passes and failures to While student counter is less than or equal to 10 Prompt the user to enter the next exam result If the student passed Add one to passes Else Add one to failures Add one to student counter

68  2008 Pearson Education, Inc. All rights reserved. 68 4.10 Formulating Algorithms: Nested Control Statement (Cont.) Second Refinement (Cont.) – Print a summary of the exam results and decide whether tuition should be raised to Print the number of passes Print the number of failures If more than eight students passed Print “Raise tuition”

69  2008 Pearson Education, Inc. All rights reserved. 69 Fig. 4.15 | Pseudocode for examination-results problem.

70  2008 Pearson Education, Inc. All rights reserved. 70 Outline fig04_16.cpp (1 of 1)

71  2008 Pearson Education, Inc. All rights reserved. 71 Outline fig04_17.cpp (1 of 2) Declare function processExamResults ’s local variables

72  2008 Pearson Education, Inc. All rights reserved. 72 Outline fig04_17.cpp (2 of 2) Determine whether this student passed or failed, and increment the appropriate variable Determine whether more than 8 students passed

73  2008 Pearson Education, Inc. All rights reserved. 73 Outline fig04_18.cpp (1 of 2)

74  2008 Pearson Education, Inc. All rights reserved. 74 Outline fig04_18.cpp (2 of 2) More than eight students passed the exam, so “Raise tuition” message is printed

75  2008 Pearson Education, Inc. All rights reserved. 75 4.11 Assignment Operators Assignment expression abbreviations – Addition assignment operator Example c = c + 3; abbreviates to c += 3; Statements of the form variable = variable operator expression ; can be rewritten as variable operator = expression ; Other assignment operators d -= 4 (d = d - 4) e *= 5 (e = e * 5) f /= 3 (f = f / 3) g %= 9 (g = g % 9)

76  2008 Pearson Education, Inc. All rights reserved. 76 Fig. 4.19 | Arithmetic assignment operators.

77  2008 Pearson Education, Inc. All rights reserved. 77 4.12 Increment and Decrement Operators Increment operator ++ – Increments variable by one Example c++ Decrement operator -- – Decrements variable by one Example c--

78  2008 Pearson Education, Inc. All rights reserved. 78 4.12 Increment and Decrement Operators (Cont.) Preincrement – When the operator is used before the variable ( ++c or --c ) – Variable is changed, then the expression it is in is evaluated using the new value Postincrement – When the operator is used after the variable ( c++ or c-- ) – Expression the variable is in executes using the old value, then the variable is changed

79  2008 Pearson Education, Inc. All rights reserved. 79 Fig. 4.20 | Increment and decrement operators.

80  2008 Pearson Education, Inc. All rights reserved. 80 Good Programming Practice 4.9 Unlike binary operators, the unary increment and decrement operators should be placed next to their operands, with no intervening spaces.

81  2008 Pearson Education, Inc. All rights reserved. 81 Outline fig04_21.cpp (1 of 1) Postincrementing the c variablePreincrementing the c variable

82  2008 Pearson Education, Inc. All rights reserved. 82 4.12 Increment and Decrement Operators (Cont.) If c = 5, then cout << ++c; c is incremented to 6 Then 6 is printed cout << c++; Prints 5 (printing occurs before the increment) Then c is incremented to 6

83  2008 Pearson Education, Inc. All rights reserved. 83 4.12 Increment and Decrement Operators (Cont.) When variable is not in an expression – Preincrementing and postincrementing have same effect Example ++c; cout << c; and c++; cout << c; print the same result

84  2008 Pearson Education, Inc. All rights reserved. 84 Common Programming Error 4.14 4 Attempting to use the increment or decrement operator on an expression other than a modifiable variable name or reference, e.g., writing ++(x + 1), is a syntax error.

85  2008 Pearson Education, Inc. All rights reserved. 85 Fig. 4.22 | Operator precedence for the operators encountered so far in the text.


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