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More rate problems, Example 1 Hayley travelled at a constant speed. She travelled 720km in 9h. a) What is her speed? b) If she was later travelling at.

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Presentation on theme: "More rate problems, Example 1 Hayley travelled at a constant speed. She travelled 720km in 9h. a) What is her speed? b) If she was later travelling at."— Presentation transcript:

1 More rate problems, Example 1 Hayley travelled at a constant speed. She travelled 720km in 9h. a) What is her speed? b) If she was later travelling at the same speed, i) how far did she travel in 3¾ hours? ii) how long did it take her to travel 420km? a) Speed = = 80km/h To find the numerator To find the denominator MULTIPLY by rate DIVIDE by rate b i) distance = 3¾ × 80 = 300km b ii) time = 420  80 = 5¼ h Finding the numerator  multiply by rate Finding the denominator  divide by rate

2 Example 2 Charlie pays $3/L of shampoo. a) What is the cost of 8L of shampoo? b) How much shampoo can she buy for $27? To find the numerator MULTIPLY by rate To find the denominator DIVIDE by rate a) cost = 8 × 3 = $24 b) volume = 27  3 = 9L Finding the numerator  multiply by rate Finding the denominator  divide by rate

3 Example 3 Luke buys Turkish delight at 100 g/$. a) What is the cost of 750g of Turkish delight? b) How much Turkish delight can he buy for $5? a) cost = 750  100 = $7·50 b) weight = 5 × 100 = 500g To find the numerator MULTIPLY by rate To find the denominator DIVIDE by rate Finding the numerator  multiply by rate Finding the denominator  divide by rate

4 Example 4 Last night 1 Aussie dollar (AUD) could purchase 0·74 US dollars (USD). a) How many USD can you purchase for 359 AUD? b) After a holiday Belinda has 52 USD, how many AUD is this? a) USD = 0·74 × 359 = 265·66 USD b) AUD = 52  0·74 = 70·27 AUD Rate is 0·74 USD/AUD To find the numerator MULTIPLY by rate To find the denominator DIVIDE by rate Finding the numerator  multiply by rate Finding the denominator  divide by rate

5 Today’s work Yesterday’s work Ex 2:01A Q1, 2, 6, 7 & 8.


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