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Working With Triple Integrals Basics ideas – extension from 1D and 2D Iterated Integrals Extending to general bounded regions.

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Presentation on theme: "Working With Triple Integrals Basics ideas – extension from 1D and 2D Iterated Integrals Extending to general bounded regions."— Presentation transcript:

1 Working With Triple Integrals Basics ideas – extension from 1D and 2D Iterated Integrals Extending to general bounded regions

2 Riemann Sums This is one way to define an iterated Integral over box B (what other ways can you think of?)

3 Example 1 Evaluate the following function over the region B = [0,3]×[-2,2] ×[1,3]

4 Example 2 What does mean if f(x,y,z) = 1

5 Triple Integrals over General Bounded Regions The z-values are sandwiched between two functions: u 2 (x,y) and u 1 (x,y) This constrains z in the following way: You can now use region D(x,y) to express x in terms of y or vice versa Your final choice is determined by the range of one of the remaining variables General = “non parallelepiped” This is usually described by region “types” cleverly named type 1, type 2 or type 3!

6 Region types Type 1 if z is constrained between functions in (x,y) Type 2 if x is constrained between functions in (y,z) Type 3 if y is constrained between functions in (x,z)

7 Example 3 Sketch, assign “type” and find the volume of the region created by the intersection of the cylinder x 2 + y 2 = 1 and the planes z = -1 and x + y + z = 4

8 The iterated integral looks like this Note the pattern in the limits: “constant”  “function 1 variable”  “function in 2 variables”

9 The inner integral: = 5 - x - y = 5 

10 Example 4 (try this at home!) Evaluate in the region created by the intersection of the cylinder x 2 + y 2 = 1 and the planes z = -1 and x + y + z = 4 (answer is 0!)

11 Example 5 Find the volume bounded by the paraboloids y = x 2 + z 2 and y = 4 – x 2 - z 2

12 y values are constrained by the two Paraboloids, so x & z values are constrained by the intersection of the paraboloids:


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