1. Copyright © 2001 by the McGraw-Hill Companies, Inc. Barnett/Ziegler/Byleen Precalculus: Functions & Graphs, 5 th Edition Chapter Five Trigonometric Functions

2. Wrapping Function 5-1-48

3. If x is a real number and (a, b) are the coordinates of the circular point W(x), then: Circular Functions 5-2-49

4. (a)  positive (b)  negative (c)  and  coterminal (a)  is a quadrantal (b)  is a third-quadrant(c)  is a second-quadrant angle angle angle Angles 5-3-50-1

5. (a) Straight angle(b) Right angle (c) Acute angle (d) Obtuse angle Angles 5-3-50-2

6. Radian Measure 5-3-51

7. Trigonometric Circular Function sin  = x cos  = x tan  = tan x csc  = x sec  = x cot  = cot x If q is an angle with radian measure x, then the value of each trigonometric function at q is given by its value at the real number x. Trigonometric Functions with Angle Domains 5-4-52

8. If q is an arbitrary angle in standard position in a rectangular coordinate system and P(a, b) is a point r units from the origin on the terminal side of q, then: Trigonometric Functions with Angle Domains Alternate Form 5-4-53

9. 1. To form a reference triangle for , draw a perpendicular from a point P(a, b) on the terminal side of  to the horizontal axis. 2. The reference angle  is the acute angle (always taken positive) between the terminal side of  and the horizontal axis. Reference Triangle and Reference Angle 5-4-54

10. 3 1 2 30° 60° (  /6) (  /3) 2 1 1 45° ° (  /4) (  30  —60  and 45  Special Triangles 5-4-55

11. If q is an arbitrary angle in standard position in a rectangular coordinate system and P(a, b) is a point r units from the origin on the terminal side of q, then: Trigonometric Functions with Angle Domains Alternate Form 5-5-53

12. 2   /2  3  (1, 0)(–1, 0) (0, –1) (0, 1) 0 1 P(cosx, sinx) a b b a x a b x y 1 0  2  3  4  –  –2  Period: 2  Domain: All real numbers Range: [–1, 1] Symmetric with respect to the origin Graph of y = sin x y = sin x = b 5-6-56

13. 2   /2  3  (1, 0)(–1, 0) (0, –1) (0, 1) 0 1 P(cosx, sinx) a b b a x a b x y 1 0  2  3  4  –  –2  Period: 2  Domain: All real numbers Range: [–1, 1] Symmetric with respect to the y axis y = cos x = a Graph of y = cos x 5-6-57

14. x y  2  –2  –  0 1 –1 5  2 3  2  2 – 5  2 – 3  2 –  2 Period:  Domain: All real numbers except  /2 + k , k an integer Range: All real numbers Symmetric with respect to the origin Increasing function between asymptotes Discontinuous at x =  /2 + k , k an integer Graph of y = tan x 5-6-58

15.  2  –2  –  0 –  2 x y 1 –1 3  2  2 – 3  2 Period:  Domain: All real numbers except k , k an integer Range: All real numbers Symmetric with respect to the origin Decreasing function between asymptotes Discontinuous at x = k , k an integer Graph of y = cot x 5-6-59

16. x y 1 –1  2  –  –2  0 y = sinx y = cscx sinx 1 = Period: 2  Domain: All real numbers except k , k an integer Range: All real numbers y such that y  –1 or y  1 Symmetric with respect to the origin Discontinuous at x = k , k an integer Graph of y = csc x 5-6-60

17. x y 1 –1  2  –  –2  0 y = cosx y = secx cosx 1 = Period: 2  Domain: All real numbers except  /2 + k , k an integer Symmetric with respect to the y axis Discontinuous at x =  /2 + k , k an integer Range: All real numbers y such that y  –1 or y  1 Graph of y = sec x 5-6-61

18. Step 1.Find the amplitude | A |. Step 2. Solve Bx + C = 0 and Bx + C = 2  : Bx + C =0 and Bx + C = 2  x = – C B x C B + 22 B Phase shift Period Phase shift = – C B Period = 2  B The graph completes one full cycle as Bx + C varies from 0 to 2  — that is, as x varies over the interval       – C B, – C B + 2  B Step 3.Graph one cycle over the interval       – C B, – C B + 22 B. Step 4.Extend the graph in step 3 to the left or right asdesired. 5-7-62

19. x y  2  –2  –  0 1 –1 5  2 3  2  2 – 5  2 – 3  2 –  2 Period:  Domain: All real numbers except  /2 + k , k an integer Range: All real numbers Symmetric with respect to the origin Increasing function between asymptotes Discontinuous at x =  /2 + k , k an integer Graph of y = tan x 5-8-58

20.  2  –2  –  0 –  2 x y 1 –1 3  2  2 – 3  2 Period:  Domain: All real numbers except k , k an integer Range: All real numbers Symmetric with respect to the origin Decreasing function between asymptotes Discontinuous at x = k , k an integer Graph of y = cot x 5-8-59

21. x y 1 –1  2  –  –2  0 y = sinx y = cscx sinx 1 = Period: 2  Domain: All real numbers except k , k an integer Range: All real numbers y such that y  –1 or y  1 Symmetric with respect to the origin Discontinuous at x = k , k an integer Graph of y = csc x 5-8-60

22. x y 1 –1  2  –  –2  0 y = cosx y = secx cosx 1 = Period: 2  Domain: All real numbers except  /2 + k , k an integer Symmetric with respect to the y axis Discontinuous at x =  /2 + k , k an integer Range: All real numbers y such that y  –1 or y  1 Graph of y = sec x 5-8-61

23. For f a one-to-one function and f –1 its inverse: 1. If (a, b) is an element of f, then (b, a) is an element of f –1, and conversely. 2. Range of f = Domain of f –1 Domain of f = Range of f –1 3. 4. If x = f –1 (y), then y = f(x) for y in the domain of f –1 and x in the domain of f, and conversely. 5. f[f –1 (y)] = yfor y in the domain of f –1 f –1 [f(x)] = xfor x in the domain of f Facts about Inverse Functions 5-9-63

24. x y 1 –1 –  2  2 Sine function     –  2, –1      2, 1 x y 1 –1  2 –  2 (0,0) y = sinx     –1, –  2     1,  2 x y 1–1  2 –  2 (0,0) y = sinx = arcsinx –1 D OMAIN =       –  2,  R ANGE = [–1, 1] Restricted sine function D OMAIN = [–1, 1] R ANGE =       –  2,  2 Inverse sine function 2 Inverse Sine Function 5-9-64

25. x y 1 –1  y = cosx x y 1 –1  (0,1) ( , –1) 0  2      2,0 –1 y = cosx = arccosx –1  2 x y 1  (1,0) (–1,  ) 0     0,  2 Cosine function D OMAIN = [0,  ]D OMAIN = [–1, 1] R ANGE = [–1, 1]R ANGE = [0,  ] Restricted cosine functionInverse cosine function Inverse Cosine Function 5-9-65

26. x y 1 –1  2 3  2 3  2 ––  2 y = tanx     –  4, –1      4, 1 x y 1 –1  2 –  2 y = tanx     –1, –  4     1,  4 y = tanx = arctanx –1 x y 1  2 –  2 Tangent function D OMAIN =       –  2,  2 R ANGE = (– ,  ) Restricted tangent function D OMAIN = (– ,  ) R ANGE =       –  2,  2 Inverse tangent function Inverse Tangent Function 5-9-66