1. Welcome to Interactive Chalkboard
Algebra 1 Interactive Chalkboard
Copyright © by The McGraw-Hill Companies, Inc.
Send all inquiries to:
GLENCOE DIVISION
Glencoe/McGraw-Hill
8787 Orion Place
Columbus, Ohio
Welcome to Interactive Chalkboard

2. Splash Screen

3. Lesson 12-1 Inverse Variation Lesson 12-2 Rational Expressions
Lesson 12-3 Multiplying Rational Expressions
Lesson 12-4 Dividing Rational Expressions
Lesson 12-5 Dividing Polynomials
Lesson 12-6 Rational Expressions with Like Denominators
Lesson 12-7 Rational Expressions with Unlike Denominators
Lesson 12-8 Mixed Expressions and Complex Fractions
Lesson 12-9 Solving Rational Equations
Contents

4. Example 1 Graph an Inverse Variation
Example 3 Solve for x
Example 4 Solve for y
Example 5 Use Inverse Variation to Solve a Problem
Lesson 1 Contents

5. Manufacturing The owner of Superfast Computer Company has calculated that the time t in hours that it takes to build a particular model of computer varies inversely with the number of people p working on the computer. The equation can be used to represent the people building a computer. Complete the table and draw a graph of the relation. p 2 4 6 8 10 12 t
Example 1-1a

6. Solve the equation for the other values of p.
Solve for
Original equation
Replace p with 2.
Divide each side by 2.
Simplify.
Answer: p 2 4 6 8 10 12 t 6 3 2
1.5
1.2 1
Solve the equation for the other values of p.
Example 1-1b

7. Graph the ordered pairs: (2, 6), (4, 3), (6, 2), (8, 1. 5), (10, 1
Graph the ordered pairs: (2, 6), (4, 3), (6, 2), (8, 1.5), (10, 1.2), and (12, 1).
Answer:
As the number of people p increases, the time t it takes to build a computer decreases.
Example 1-1c

8. Manufacturing The foreman of a package delivery company has found that the time t in hours that it takes to prepare packages for delivery varies inversely with the number of people p that are preparing them. The equation can be used to represent the people preparing the packages. Complete the table and draw a graph of the relation.
Answer: p 2 4 6 8 10 12 t 18 9
4.5
3.6 3 p 2 4 6 8 10 12 t
Example 1-1d

9. Answer:
Example 1-1e

10. Graph an inverse variation in which y varies inversely as x and
Solve for k.
Inverse variation equation
The constant of variation is 4.
Example 1-2a

11. Choose values for x and y whose product is 4. x y –4 –1 –2
undefined 1 4 2
Example 1-2b

12. Graph an inverse variation in which y varies inversely as x and
Answer:
Example 1-2c

13. If y varies inversely as x and find x when
Method 1 Use the product rule.
Product rule for inverse variations
Divide each side by 15.
Simplify.
Example 1-3a

14. Method 2 Use a proportion.
Proportion rule for inverse variations
Cross multiply.
Divide each side by 15.
Answer: Both methods show that
Example 1-3b

15. If y varies inversely as x and find x when
Answer: 8
Example 1-3c

16. If y varies inversely as x and find y when
Use the product rule.
Product rule for inverse variations
Divide each side by 4.
Simplify.
Answer:
Example 1-4a

17. If y varies inversely as x and find y when
Answer: –25
Example 1-4b

18. Physical Science When two objects are balanced on a lever, their distances from the fulcrum are inversely proportional to their weights. How far should a 2-kilogram weight be from the fulcrum if a 6-kilogram weight is 3.2 meters from the fulcrum?
Example 1-5a

19. Answer: The 2-kilogram weight should be 9.6 meters from the fulcrum.
Original equation
Divide each side by 2.
Simplify.
Answer: The 2-kilogram weight should be 9.6 meters from the fulcrum.
Example 1-5b

20. Physical Science How far should a 10-kilogram weight be from the fulcrum if a 4 kilogram weight is 2.5 meters from the fulcrum?
Answer: 1 m
Example 1-5c

21. End of Lesson 1

22. Example 1 One Excluded Value Example 2 Multiple Excluded Values
Example 3 Use Rational Expressions
Example 4 Expression Involving Monomials
Example 5 Expression Involving Polynomials
Example 6 Excluded Values
Lesson 2 Contents

23. State the excluded value of
Exclude the values for which
The denominator cannot equal zero.
Subtract 7 from each side.
Answer: b cannot equal –7.
Example 2-1a

24. State the excluded value of
Answer: –3
Example 2-1b

25. State the excluded values of
Exclude the values for which
The denominator cannot equal zero.
Factor.
Use the Zero Product Property to solve for a. or
Answer: a cannot equal –3 or 4.
Example 2-2a

26. State the excluded values of
Answer: 2, 3
Example 2-2b

27. The original mechanical advantage was 5.
Landscaping Refer to Example 3 on page 649. Suppose Kenyi finds a rock that he cannot move with a 6-foot bar, so he gets an 8-foot bar. But this time, he places the fulcrum so that the effort arm is 6 feet long, and the resistance arm in 2 feet long.
Explain whether he has more or less mechanical advantage with his new setup.
The original mechanical advantage was 5.
Example 2-3a

28. Use the expression for mechanical advantage to write an expression for the mechanical advantage in the new situation.
Simplify.
Answer: Even though the bar is longer, because he moved the fulcrum he has a mechanical advantage of 3, so his mechanical advantage is less than before.
Example 2-3b

29. If Kenyi can apply a force of 180 pounds, what is the greatest weight he can lift with the longer bar?
Answer: Since the mechanical advantage is 3, Kenyi can lift 3 • 180 or 540 pounds with the longer bar.
Example 2-3c

30. a. Use the formula to find the mechanical advantage.
Landscaping Sean and Travis are responsible for clearing an area for a garden. They come across a large rock that they cannot lift. Therefore, they use a 5-foot bar as a lever, and the fulcrum is 1 foot away from the rock.
a. Use the formula to find the mechanical advantage.
b. If they can apply a force of 200 pounds, what is the greatest weight they can lift?
Answer: 4
Answer: 800 lb
Example 2-3d

31. The GCF of the numerator and denominator is
Simplify
The GCF of the numerator and denominator is
Divide the numerator and denominator by 1
Answer:
Simplify.
Example 2-4a

32. Simplify
Answer:
Example 2-4b

33. Divide the numerator and denominator by the GCF, x – 7.
Simplify
Factor.
Divide the numerator and denominator by the GCF, x – 7. 1
Answer:
Simplify
Example 2-5a

34. Simplify
Answer:
Example 2-5b

35. Simplify State the excluded values of x.
Factor.
Divide the numerator and denominator by the GFC, x + 4. 1
Simplify.
Answer:
Example 2-6a

36. Exclude the values for which equals 0.
The denominator cannot equal zero.
Factor.
Zero Product Property
Example 2-6b

37. Check. Verify the excluded values by substituting
Check Verify the excluded values by substituting them into the original expression.
Evaluate.
Simplify.
Example 2-6c

38. Answer: The expression is undefined when and Therefore,
Evaluate.
Simplify.
Answer: The expression is undefined when and Therefore,
Example 2-6d

39. Simplify State the excluded values of w.
Answer:
Example 2-6e

40. End of Lesson 2

41. Example 1 Expressions Involving Monomials
Example 2 Expressions Involving Polynomials
Example 3 Dimensional Analysis
Lesson 3 Contents

42. Method 1 Divide by the greatest common factor after multiplying.
Find
Method 1 Divide by the greatest common factor after multiplying.
Multiply the numerators.
Multiply the denominators.
The GCF is 98xyz.
Simplify.
Example 3-1a

43. Method 2 Divide the common factors before multiplying.
Divide by common factors and z. 1 x 6
z 2
y 3
Multiply.
Answer:
Example 3-1a

44. Divide by common factors and r.
Find
Divide by common factors and r. 1 2
d 2
q 2
r 3
Multiply.
Answer:
Example 3-1a

45. a. Find
b. Find
Answer:
Answer:
Example 3-1b

46. Find Factor the numerator. The GCF is Simplify. Answer: x 2 1
Example 3-2a

47. Find
Factor.
The GCF is 1
Example 3-2a

48. Multiply.
Simplify.
Answer:
Example 3-2a

49. a. Find
b. Find
Answer:
Answer:
Example 3-2b

50. Space The velocity that a spacecraft must have in order to escape Earth’s gravitational pull is called the escape velocity. The escape velocity for a spacecraft leaving Earth is about 40,320 kilometers per hour. What is this speed in meters per second?
Example 3-3a

51. Answer: The escape velocity is 11,200 meters per second.
1120 10 1
Simplify.
Multiply.
Answer: The escape velocity is 11,200 meters per second.
Example 3-3a

52. Answer: 1188 kilometers per hour
Example 3-3b
Aviation The speed of sound, or Mach 1, is approximately 330 meters per second at sea level. What is the speed of sound in kilometers per hour?
Answer: 1188 kilometers per hour

53. End of Lesson 3

54. Example 1 Expression Involving Monomials
Example 2 Expression Involving Binomials
Example 3 Divide by a Binomial
Example 4 Expression Involving Polynomials
Example 5 Dimensional Analysis
Lesson 4 Contents

55. Multiply by the reciprocal of
Find
Multiply by the reciprocal of
Divide by common factors 5, 6, and x. 1 4 15 x3
Answer:
Simplify.
Example 4-1a

56. Find
Answer:
Example 4-1b

57. Multiply by the reciprocal of
Find
Multiply by the reciprocal of
Factor
Example 4-2a

58. The GCF is 1 or
Simplify.
Answer:
Example 4-2b

59. Find
Answer:
Example 4-2c

60. Multiply by the reciprocal of
Find
Multiply by the reciprocal of
Factor
Example 4-3a

61. The GCF is 1
Simplify.
Answer:
Example 4-3b

62. Find
Answer:
Example 4-3c

63. Multiply by the reciprocal,
Find
Multiply by the reciprocal,
Factor
Example 4-4a

64. The GCF is 1
Simplify.
Answer:
Example 4-4b

65. Find
Answer:
or (k – 10) (k – 2) 10
Example 4-4c

66. Use the formula for rate, time, and distance.
Aviation In 1986, an experimental aircraft named Voyager was piloted by Jenna Yeager and Dick Rutan around the world non-stop, without refueling. The trip took exactly 9 days and covered a distance of 25,012 miles. What was the speed of the aircraft in miles per hour? Round to the nearest mile per hour.
Use the formula for rate, time, and distance.
Divide each side by 9 days.
Example 4-5a

67. Answer: Thus, the speed of the aircraft was about 116 miles per hour.
Convert days to hours.
Answer: Thus, the speed of the aircraft was about 116 miles per hour.
Example 4-5b

68. Answer: about 149 miles per hour
Aviation Suppose that Jenna Yeager and Dick Rutan wanted to complete the trip in exactly 7 days. What would be their average speed in miles per hour for the 25,012-mile trip? 
Answer: about 149 miles per hour
Example 4-5c

69. End of Lesson 4

70. Example 1 Divide a Binomial by a Monomial
Example 2 Divide a Polynomial by a Monomial
Example 3 Divide a Polynomial by a Binomial
Example 4 Long Division
Example 5 Polynomial with Missing Terms
Lesson 5 Contents

71. Write as a rational expression.
Find
Write as a rational expression.
Divide each term by 2x. 2x 9 1
Simplify each term.
Simplify.
Answer:
Example 5-1a

72. Find
Answer:
Example 5-1b

73. Write as a rational expression.
Find
Write as a rational expression.
Divide each term by 3y. 2y 1 3
Simplify each term. y
Simplify.
Answer:
Example 5-2a

74. Find
Answer:
Example 5-2b

75. Write as a rational expression.
Find
Write as a rational expression.
Factor the numerator. 1
Divide by the GCF.
Simplify.
Answer:
Example 5-3a

76. Find
Answer:
Example 5-3b

77. Find
Step 1 Divide the first term of the dividend, x2, by the first term of the divisor, x. x
Multiply x and x – 2.
Subtract.
Example 5-4a

78. Step 2. Divide the first term of the partial dividend,
Step 2 Divide the first term of the partial dividend, 9x – 15, by the first term of the divisor, x. x
+ 9
Subtract and bring down –15.
Subtract.
Multiply 9 and x – 2.
Example 5-4b

79. Answer:. The quotient of. is
Answer: The quotient of is with a remainder of 3, which can be written as
Example 5-4c

80. Answer: The quotient is with a remainder of 2.
Find
Answer: The quotient is with a remainder of 2.
Example 5-4d

81. Rename the x2 term by using a coefficient of 0.
Find
Rename the x2 term by using a coefficient of 0.
Example 5-5a

82. Answer: Multiply x2 and x – 5. Subtract and bring down –34x.
Multiply –9 and x – 5.
Answer:
Example 5-5b

83. Answer: The quotient is
Find
Answer: The quotient is
Example 5-5c

84. End of Lesson 5

85. Example 1 Numbers in Denominator Example 2 Binomials in Denominator
Example 3 Find a Perimeter
Example 4 Subtract Rational Expressions
Example 5 Inverse Denominators
Lesson 6 Contents

86. The common denominator is 15.
Find
The common denominator is 15.
Add the numerators.
Divide by the common factor, 5. 4 3
Simplify.
Answer:
Example 6-1a

87. Find
Answer:
Example 6-1b

88. The common denominator is c + 2.
Find
The common denominator is c + 2.
Factor the numerator.
Divide by the common factor, c + 2. 1
Simplify.
Answer:
Example 6-2a

89. Find
Answer: 5
Example 6-2b

90. Geometry Find an expression for the perimeter of rectangle WXYZ.
Perimeter formula
Example 6-3a

91. The common denominator is
Distributive Property
Combine like terms.
Factor.
Example 6-3b

92. Answer: The perimeter can be represented by the expression
Example 6-3c

93. 18 Geometry Find an expression for the perimeter of rectangle PQRS.
Answer: 18
Example 6-3d

94. The common denominator is
Find
The common denominator is
The additive inverse of is
Distributive Property
Example 6-4a

95. Simplify.
Answer:
Example 6-4b

96. Find
Answer:
Example 6-4c

97. Rewrite using common denominators.
Find
The denominator is the same as or . Rewrite the second expression so that it has the same denominator as the first.
Rewrite using common denominators.
Example 6-5a

98. The common denominator is
Simplify.
Answer:
Example 6-5b

99. Find
Answer:
Example 6-5c

100. End of Lesson 6

101. Example 1 LCM of Monomials Example 2 LCM of Polynomials
Example 3 Monomial Denominators
Example 4 Polynomial Denominators
Example 5 Binomials in Denominators
Example 6 Polynomials in Denominators
Lesson 7 Contents

102. Find the prime factors of each coefficient and variable expression.
Find the LCM of
Find the prime factors of each coefficient and variable expression.
Use each prime factor the greatest number of times it appears in any of the factorizations.
Answer:
Example 7-1a

103. Find the LCM of
Answer:
Example 7-1b

104. Express each polynomial in factored form.
Find the LCM of
Express each polynomial in factored form.
Use each factor the greatest number of times it appears.
Answer:
Example 7-2a

105. Find the LCM of
Answer:
Example 7-2b

106. Factor each denominator and find the LCD.
Since the denominator of is already 5z, only needs to be renamed.
Example 7-3a

107. Distributive Property
Multiply by
Distributive Property
Add the numerators.
Answer:
Simplify.
Example 7-3b

108. Find
Answer:
Example 7-3c

109. Factor the denominators.
Find
Factor the denominators.
The LCD is
Example 7-4a

110. Add the numerators.
Simplify.
Answer:
Example 7-4b

111. Find
Answer:
Example 7-4c

112. Find
Factor.
The LCD is
Add the numerators.
Example 7-5a

113. Multiply.
Simplify.
Answer:
Example 7-5b

114. Find
Answer:
Example 7-5c

115. Multiple-Choice Test Item FindA B C D
Example 7-6a

116. Step 1 Factor each denominator and find the LCD.
Read the Test Item
The expression represents the difference of two rational expressions with unlike denominators.
Solve the Test Item
Step 1 Factor each denominator and find the LCD.
The LCD is
Example 7-6b

117. Step 2. Change each rational expression into an
Step 2 Change each rational expression into an equivalent expression with the LCD. Then subtract.
Example 7-6c

118. Answer: C
Example 7-6d

119. Multiple-Choice Test Item FindA B C D
Answer: C
Example 7-6e

120. End of Lesson 7

121. Example 1 Mixed Expression to Rational Expression
Example 2 Complex Fraction Involving Numbers
Example 3 Complex Fraction Involving Monomials
Example 4 Complex Fraction Involving Polynomials
Lesson 8 Contents

122. Distributive Property
Simplify
The LCD is
Add the numerators.
Distributive Property
Answer:
Simplify.
Example 8-1a

123. Simplify
Answer:
Example 8-1b

124. Baking Suppose Katelyn bought 2 pounds of chocolate chip cookie dough
Baking Suppose Katelyn bought 2 pounds of chocolate chip cookie dough. If the average cookie requires ounces of dough, how many cookies would she be able to make?
To find the total number of cookies, divide the amount of cookie dough by the amount of dough needed for each cookie.
Example 8-2a

125. Convert pounds to ounces and divide by common units.
Simplify.
Express each term as an improper fraction.
Example 8-2b

126. Answer: Katelyn can make 21 cookies.
Simplify.
Answer: Katelyn can make 21 cookies.
Example 8-2c

127. Baking James bought pounds of cookie dough, and he prefers to make large cookies. If each cookie requires ounces of dough, how many cookies can he make? 
Answer: 27 cookies
Example 8-2d

128. Rewrite as a division sentence.
Simplify
Rewrite as a division sentence.
Rewrite as multiplication by the reciprocal.
Example 8-3a

129. Divide by common factors a, b, and c2.1
Simplify.
Answer:
Example 8-3b

130. Simplify
Answer:
Example 8-3c

131. The LCD of the fractions in the numerator is
Simplify
The numerator contains a mixed expression. Rewrite it as a rational expression first.
The LCD of the fractions in the numerator is
Simplify the numerator.
Example 8-4a

132. Rewrite as a division sentence.
Factor.
Rewrite as a division sentence.
Multiply by the reciprocal of
Simplify.
Answer:
Example 8-4b

133. Simplify
Answer:
Example 8-4c

134. End of Lesson 8

135. Example 1 Use Cross Products Example 2 Use the LCD
Example 3 Multiple Solutions
Example 4 Work Problem
Example 5 Rate Problem
Example 6 No Solution
Example 7 Extraneous Solution
Lesson 9 Contents

136. Distributive Property
Solve
Original equation
Cross multiply.
Distributive Property
Add –2x and 48 to each side.
Answer:
Divide each side by 6.
Example 9-1a

137. Solve
Answer: –3
Example 9-1b

138. Solve
Original equation
The LCD is
Distributive Property
Example 9-2a

139. Subtract 1 from each side.
Simplify.
Add.
Subtract 1 from each side.
Divide each side by 6.
Answer:
Example 9-2b

140. Solve
Answer: 8
Example 9-2c

141. Solve
Original equation
The LCD is
Distributive Property
Example 9-3a

142. Simplify.
Set equal to 0.
Factor. or
Example 9-3b

143. Check. Check solutions by substituting each value in
Check Check solutions by substituting each value in the original equation.
Example 9-3c

144. Check. Check solutions by substituting each value in
Check Check solutions by substituting each value in the original equation.
Answer: The number 1 is an excluded value for x. Thus, the solution is 3.
Example 9-3d

145. Solve
Answer: 4, –1
Example 9-3e

146. TV Installation On Saturdays, Lee helps her father install satellite TV systems. The jobs normally take Lee’s father about hours. But when Lee helps, the jobs only take them hours. If Lee were installing a satellite system herself, how long would the job take?
Example 9-4a

147. Explore. Since it takes Lee’s father
Explore Since it takes Lee’s father hours to install one job, he can finish of the job in one hour. The amount of work Lee can do in one hour can be represented by To determine how long it takes Lee to do the job, use the formula Lee’s work + her father’s work = 1 job.
Example 9-4b

148. Plan. The time that both of them worked was hours
Plan The time that both of them worked was hours. Each rate multiplied by this time results in the amount of work done by each person.
Solve Lee’s her father’s total work plus work equals work. 1
Example 9-4c

149. Distributive Property
Multiply.
The LCD is 10t.
Distributive Property
Simplify.
Example 9-4d

150. Answer: The job would take Lee or hours by herself.
Add –6t to each side.
Divide each side by 4.
Answer: The job would take Lee or hours by herself.
Examine This seems reasonable because the combined efforts of the two took longer than half of her father’s usual time.
Example 9-4e

151. Driveways Shawna earns extra money by shoveling driveways
Driveways Shawna earns extra money by shoveling driveways. If she works alone, she can finish a large driveway in hours. If Vince helps her, they can get done in hours. If Vince were shoveling the driveway himself, how long would the job take him?
Answer: hours
Example 9-4f

152. Transportation The schedule for the Washington, D. C
Transportation The schedule for the Washington, D.C., Metrorail is shown to the right. Suppose two Red Line trains leave their stations at opposite ends of the line at exactly 2:00 P.M. One train travels between the two stations in 48 minutes and the other train takes 54 minutes. At what time do the two trains pass each other?
Example 9-5a

153. Determine the rates of both trains. The total distance is 19.4 miles.
Next, since both trains left at the same time, the time both have traveled when they pass will be the same. And since they started at opposite ends of the route, the sum of their distances is equal to the total route, miles.
Example 9-5b

154. t min d = r  t t r Train 1 Train 2 The sum of the distances is 19.4.
The LCD is 432.
Example 9-5c

155. Distributive Property
Simplify.
Add.
Divide each side by
Answer: The trains passed each other at about 25 minutes after they left their stations, at 2:25 P.M.
Example 9-5d

156. Transportation Two cyclists are riding on a 5-mile circular bike trail
Transportation Two cyclists are riding on a 5-mile circular bike trail. They both leave the bike trail entrance at 3:00 P.M. traveling in opposite directions. It usually takes the first cyclist one hour to complete the trail and it takes the second cyclist 50 minutes. At what time will they pass each other?
Answer: 3:27 P.M.
Example 9-5e

157. Distributive Property
Solve
Original equation
The LCD is x – 1.
Distributive Property 1
Example 9-6a

158. Subtract 2 from each side.
Simplify.
Subtract 2 from each side.
Answer: Since 1 is an excluded value for x, the number 1 is an extraneous solution. Thus, the equation has no solution.
Example 9-6b

159. Solve
Answer: no solutions
Example 9-6c

160. Distributive Property
Solve
Original equation
The LCD is x – 2. 1
Distributive Property
Example 9-7a

161. Subtract 4 from each side.
Simplify.
Subtract 4 from each side.
Factor. or
Zero Product Property
Answer: The number 2 is an extraneous solution, since 2 is an excluded value for x. Thus, –2 is the solution of the equation.
Example 9-7b

162. Solve
Answer: –3
Example 9-7c

163. End of Lesson 9

164. Explore online information about the information introduced in this chapter.
Click on the Connect button to launch your browser and go to the Algebra 1 Web site. At this site, you will find extra examples for each lesson in the Student Edition of your textbook. When you finish exploring, exit the browser program to return to this presentation. If you experience difficulty connecting to the Web site, manually launch your Web browser and go to
Algebra1.com

165. Click the mouse button or press the Space Bar to display the answers.
Transparency 1

166. Transparency 1a

167. Click the mouse button or press the Space Bar to display the answers.
Transparency 2

168. Transparency 2a

169. Click the mouse button or press the Space Bar to display the answers.
Transparency 3

170. Transparency 3a

171. Click the mouse button or press the Space Bar to display the answers.
Transparency 4

172. Transparency 4a

173. Click the mouse button or press the Space Bar to display the answers.
Transparency 5

174. Transparency 5a

175. Click the mouse button or press the Space Bar to display the answers.
Transparency 6

176. Transparency 6a

177. Click the mouse button or press the Space Bar to display the answers.
Transparency 7

178. Transparency 7a

179. Click the mouse button or press the Space Bar to display the answers.
Transparency 8

180. Transparency 8a

181. Click the mouse button or press the Space Bar to display the answers.
Transparency 9

182. Transparency 9a

183. To navigate within this Interactive Chalkboard product:
Click the Forward button to go to the next slide.
Click the Previous button to return to the previous slide.
Click the Section Back button to return to the beginning of the lesson you are working on. If you accessed a feature, this button will return you to the slide from where you accessed the feature.
Click the Main Menu button to return to the presentation main menu.
Click the Help button to access this screen.
Click the Exit button or press the Escape key [Esc] to end the current slide show.
Click the Extra Examples button to access additional examples on the Internet.
Click the 5-Minute Check button to access the specific 5-Minute Check transparency that corresponds to each lesson.
Help

184. End of Custom Shows WARNING! Do Not Remove
This slide is intentionally blank and is set to auto-advance to end custom shows and return to the main presentation.
End of Custom Show

185. End of Slide Show