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Unit Testing CS 4311 Hans Van Vliet, Software Engineering, Principles and Practice, 3rd edition, John Wiley & Sons, 2008. Chapter 13.

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Presentation on theme: "Unit Testing CS 4311 Hans Van Vliet, Software Engineering, Principles and Practice, 3rd edition, John Wiley & Sons, 2008. Chapter 13."— Presentation transcript:

1 Unit Testing CS 4311 Hans Van Vliet, Software Engineering, Principles and Practice, 3rd edition, John Wiley & Sons, Chapter 13.

2 Hierarchy of Testing Testing Ad Hoc Program Testing System Testing
Acceptance Testing Unit Testing Integration Testing Function Benchmark Properties Black Box Black Box Black Box Black Box Black Box Black Box Top Down Pilot Performance Equivalence Equivalence Equivalence Equivalence Equivalence Equivalence Bottom Up Boundary Boundary Boundary Boundary Boundary Reliability Alpha Big Bang Decision Table Decision Table Availability Beta Sandwich State Transition State Transition State Transition State Transition State Transition Security Use Case Use Case Use Case Use Case Usability Documentation Domain Analysis Domain Analysis Domain Analysis White Box White Box Portability Control Flow Data Flow Capacity

3 Outline Basic concepts Black box testing White box testing

4 Basic Concepts What is unit testing?
Test focusing on the smallest units of code, such as Functions, procedures, subroutines, subprograms Methods, classes Component tested in isolation from the rest of the system and in a controlled environment: Uses appropriately chosen input data Uses component-level design description as guide Often the target of testing frameworks such as JUnit

5 Basics Why unit testing? What to test? When and who?
Foundation for other testing like integration and system testing What to test? Data transformations across the unit are tested Data structures are tested to ensure data integrity When and who? Frequently done (at least partially) during code development by code developers

6 Unit Test Procedures Driver Module to Be Tested Results Test cases
Stub Stub

7 Two Different Techniques
Black box Based on specification Inner structure of test object is not considered White box Based on source code Inner structure of test object is the basis of test case selection Often complementary Effectiveness of black box is similar to white box, but the mistakes found are different (Hetzel 1976, Myers 1978) Use in combinations

8 Outline Basic concepts Black box testing White box testing
Equivalence classes White box testing

9 What Is Black Box Testing?
Unit (code, module) seen as a black box No access to the internal or logical structure Determine if given input produces expected output Input Output

10 Black Box Testing Test set is derived from specifications or requirements Goal is to cover the input space Lots of approaches to describing input space: Equivalence classes Boundary value analysis Decision tables State transitions Use cases . . .

11 Advantage and Disadvantage
(Dis)Advantages It does not require access to the internal logic of a component However, in most real-world applications, impossible to test all possible inputs Need to define an efficient strategy to limit number of test cases

12 General Process Analyze specifications or requirements
Select valid and invalid inputs (i.e., positive and negative tests) Determine expected outputs Construct tests Run tests Compare actual outputs to expected outputs

13 Outline Basic concepts Black box testing White box testing
Equivalence classes Boundary values White box testing

14 Motivation Assume you test a sign function, int sign(int x), whose result is defined as: 1 if x > 0 0 if x = 0 -1 otherwise (i.e., x < 0) One way to reduce the number of test cases is: to partition the input into three subsets { x | x > 0}, { x | x = 0}, { x | x < 0} to pick one from each subset, e.g., 10, 0, and -10.

15 Basic Strategy of Equivalence Classes
Partition the input into equivalence classes This is the tricky part. It’s an equivalence class if: Every test using one element of the class tests the same thing that any other element of the class tests If an error is found with one element, it should be found with any element If an error is not found with some element, it is not found by any element Test a subset from each class

16 Exercise Consider a factorial function, fact(n):
if n < 0 or n >= 200, error if 0  n  20, exact value if 20 < n < 200, approximate value within 0.1%. Q: What equivalence classes can you see?

17 Simple Example Suppose you are building an airline reservation system.
A traveler can be a child, an adult, or a senior. The price depends on the type of traveler. The seat reservation does not depend on the type of traveler. Q: How many test cases can you identify for the reservation component and the billing component?

18 Heuristics for Finding Equivalence Classes
Identify restrictions for inputs and outputs in the specification.

19 Heuristics for Finding Equivalence Classes
Identify restrictions for inputs and outputs in the specification. If there is a continuous numerical domain, create one valid and two or three invalid classes (above, below, and NaN).

20 Heuristics for Finding Equivalence Classes
Identify restrictions for inputs and outputs in the specification. If there is a continuous numerical domain, create one valid and two or three invalid classes (above, below, and NaN). If a number of values is required, create one valid and one or more invalid classes.

21 Heuristics for Finding Equivalence Classes
Identify restrictions for inputs and outputs in the specification. If there is a continuous numerical domain, create one valid and two or three invalid classes (above, below, and NaN). If a number of values is required, create one valid and one or more invalid classes. If a set of values is specified where each may be treated differently, create a class for each element of the set and one more for elements outside the set.

22 Heuristics for Finding Equivalence Classes
Identify restrictions for inputs and outputs in the specification. If there is a continuous numerical domain, create one valid and two or three invalid classes (above, below, and NaN). If a number of values is required, create one valid and one or more invalid classes. If a set of values is specified where each may be treated differently, create a class for each element of the set and one more for elements outside the set. If there is a condition, create two classes, one satisfying and one not satisfying the condition.

23 Exercise Define test cases for a program that reserves a golf tee time. The standard green fee is $65 on weekdays (Monday-Friday) and $80 on weekend (Saturday and Sunday). However, an El Paso resident pays a reduced green fee of $45 and $60 on weekdays and weekend, respectively. A senior (of age 60+) pays only $40 and $50 on weekdays and weekend, respectively. A junior (of age <17) pays only $20 and $30 on weekdays and weekend, respectively. Q: How many equivalence classes? Define them. Q: Define one test case per equivalence class.

24 Outline Basic concepts Black box testing White box testing
Equivalence classes Boundary values Decision tables White box testing

25 Boundary Values Observations Test the boundaries
Programs that fail at interior elements of an equivalence class usually fail at the boundaries too. Programmers often make errors on boundary conditions (e.g., branch/loop condition x <= 10 instead of x < 10). Test the boundaries if it should work for 1-99, test 0, 1, 99, 100. if it works for A-Z, A, Z, [, a, and z The hard part is identifying boundaries.

26 Hints If a domain is a restricted set, check the boundaries. e.g., D=[1,10], test 0, 1, 10, 11 It may be possible to test the boundaries of outputs, also. For ordered sets, check the first and last elements. For complex data structures, the empty list, full lists, the zero array, and the null pointer should be tested. Extremely large data sets should be tested. Check for off-by-one errors.

27 More Hints Some boundaries are not obvious and may depend on the implementation (use gray box testing if needed) Numeric limits (e.g., test 255 and 256 for 8-bit values) Implementation limits (e.g., max array size)

28 Example Consider a simple voltage stabilizer with an input range of volts hertz.

29 Example Consider a simple voltage stabilizer with an input range of volts hertz. Voltage boundaries 189 volts (below the lowest boundary) 190 volts (lowest boundary) 240 volts (highest boundary) 241 volts (above the highest boundary) Cycles (hertz) boundaries 49 hertz (below) 50 hertz (lowest) 60 hertz (highest) 61 hertz (above)

30 One extremes with others fixed.
Example Consider a simple voltage stabilizer with an input range of volts hertz. Voltage boundaries 189 volts (below the lowest boundary) 190 volts (lowest boundary) 240 volts (highest boundary) 241 volts (above the highest boundary) Cycles (hertz) boundaries 49 hertz (below) 50 hertz (lowest) 60 hertz (highest) 61 hertz (above) How to combine? Exhaustive, Pairwise (later), One extremes with others fixed.

31 Exercise Determine the boundary values for US Postal Service ZIP codes (5 digits such as or 5 digits hyphen 4 digits such as ). Determine the boundary values for a 15-character last name entry. Hints: Two kinds of boundaries---size boundary and value boundary.

32 Outline Basic concepts Black box testing White box testing
Equivalence classes Boundary values Decision tables Pairwise testing State transitions Use cases White box testing

33 Decision Tables Construct a table (to help organize the testing)
Identify each rule or condition in the system that depends on some input For each input to one of these rules, list the combinations of inputs and the expected results

34 Example Theater ticket prices are discounted for senior citizens and students. Test Case C1 Student? C2 Senior? Result Discount? 1 T 2 F 3 4

35 Exercise Construct a decision table for a program that reserves a golf tee time. The standard green fee is $65 on weekdays (Monday-Friday) and $80 on weekend (Saturday and Sunday). However, an El Paso resident pays a reduced green fee of $45 and $60 on weekdays and weekend, respectively. A senior (of age 60+) pays only $40 and $50 on weekdays and weekend, respectively. A junior (of age <17) pays only $20 and $30 on weekdays and weekend, respectively.

36 Pairwise Testing: Motivation
Consider a website that must: operate correctly with different browsers: IE 5, IE 6, and IE 7; Mozilla 1.1; Opera 7; FireFox 2, 3, and 4, and Chrome. work using RealPlayer, MediaPlayer, or no plug-in. run under Windows ME, NT, 2000, XP, and Vista, 7.0, and 8.0 accept pages from IIS, Apache and WebLogic running on Windows NT, 2000, and Linux servers. How many different configurations are there?

37 Motivation Consider a website that must:
operate correctly with different browsers: IE 5, IE 6, and IE 7; Mozilla 1.1; Opera 7; FireFox 2, 3, and 4, and Chrome. work using RealPlayer, MediaPlayer, or no plug-in. run under Windows ME, NT, 2000, XP, and Vista, 7.0, and 8.0 accept pages from IIS, Apache and WebLogic running on Windows NT, 2000, and Linux servers. How many different configurations are there? A: 9 browsers x 3 plug-ins x 7 OS’s x 3 web servers x 3 server OS’s = 1701 combinations

38 Motivation Many such examples (i.e., finite sets of discrete values).
A bank is ready to test a data processing system Customer types: Gold, Platinum, Business, Non profits Account types: Checking, Savings, Mortgages, Consumer loans, Commercial loans States (with different rules): CA, NV, UT, ID, AZ, NM How many different configurations are there?

39 Approaches? When given a large number of combinations:
Give up and don’t test Test all combinations: miss targets, delay product launch, and go out of business Choose one or two cases Choose a few that the programmers already ran Choose the tests that are easy to create List all combinations and choose first few List all combinations and randomly choose some “Magically” choose a small subset with high probability of revealing defects

40 Pairwise Testing Combinatorial testing technique in which every pair of input parameters of software is tested. Reasonable cost-benefit compromise Much faster than exhaustive testing More effective than less exhaustive methods that fail to exercise all possible pairs of input parameters Why? Majority of software failures are caused by a single input parameter or a combination of two input parameters. Each pair of input parameter values should be captured at least by one test case. However, finding the least number of test cases is an NP-complete problem.

41 Example Consider software that takes three input parameters, say x, y, and z. If each parameter can have three different values, then there will be 27 different pairs: (x1, y1), (x1, y2), …, (y3, z3). A test case (x1, y3, z2), for example, captures three of these 27 pairs: (x1, y3), (x1, z2), and (y3, z3). By selecting test cases judiciously, all pairs of input parameters can be exercised with a minimum number of test cases; e.g., a set of 9 test cases can capture all 27 pairs of three parameters, each with three different values.

42 State Transitions Use state transitions (e.g., UML state machine diagrams) to derive test inputs Cover a state transition diagram, e.g., Visit each state at least once Trigger each event at least once Exercise each transition at least once Exercise each path at least once* * Might not be possible.

43 Example and Exercise Customer makes a reservation and has a limited time to pay. May cancel at any time. printed Paid paid Ticketed ordered/ start timer Reserved delivered canceled canceled/ refund canceled/ refund timer expired Cancelled Used Unpaid Groups: How many tests to visit each state, trigger each event, exercise each transition, and exercise each path?

44 Use Cases Use the use cases to specify test cases
Use case specifies both normal, alternate, and exceptional operations However, use cases may not have sufficient details, esp. for unit testing

45 Outline Basic concepts Black box testing White box testing
Control flow graph (CFG) Statement coverage

46 White Box Testing Test set is derived from structure of (source) code
Also known as: Glass box testing Structural testing Often use a graph called a control flow graph (CFG) To represent code structure To cover it (CFG), e.g., all statements Input Output

47 Control Flow Graphs Programs are made of three kinds of statements:
Sequence (i.e., series of statements) Condition (i.e., if statement) Iteration (i.e., while, for, repeat statements)

48 Control Flow Graphs Programs are made of three kinds of statements:
Sequence (i.e., series of statements) Condition (i.e., if statement) Iteration (i.e., while, for, repeat statements) CFG: visual representation of flow of control Node represents a sequence of statements with single entry and single exit Edge represents transfer of control from one node to another

49 Control Flow Graph (CFG)
Sequence If-then-else If-then Iterative

50 Control Flow Graph (CFG)
Join Join Sequence If-then-else If-then Iterative When drawing CFG, ensure that there is one exit: include the join node if needed

51 Example 1. read (result); 2. read (x,k) 3. while result < 0 {
5 6 7 9 8 2 1 4 1. read (result); 2. read (x,k) 3. while result < 0 { 4. ptr  false 5. if x > k then ptr  true 7. x  x + 1 8. result  result + 1 } 9. print result

52 Example 1. read (result); 2. read (x,k) 3. while result < 0 {
5 6 7 9 8 2 1 4 1,2 1. read (result); 2. read (x,k) 3. while result < 0 { 4. ptr  false 5. if x > k then ptr  true 7. x  x + 1 8. result  result + 1 } 9. print result 3 9 4,5 6 Join 7,8

53 Exercise: Draw CFGs Example 1 if (a < b) then while (a < n)
a  a + 1; 4. else while (b < n) b  b + 1; Example 2 1. read (a, b); 2. if (a  0 && b  0) then { c  a + b; if c > 10 then c  max; else c  min; } 7. else print ‘Done’; Example 3 1. read (a, b); 2. if (a  0 || b  0) then { c  a + b; while( c < 100) c  a + b; } 6. c  a * b;

54 Outline Basic concepts Black box testing White box testing
Control flow graph (CFG) Statement coverage Branch coverage Condition coverage Path coverage

55 Coverage Coverage-based testing Control-flow coverage
Adequacy of testing in terms of the coverage of the product to be tested, e.g., the percentage of statements executed or the percentage of functional requirements tested. Control-flow coverage Statement Branch Condition Path Data-flow coverage Def-use

56 Statement Coverage Every statement gets executed at least once
Every node in the CFG gets visited at least once, also known as all-nodes coverage

57 Example Q: Number of paths needed for statement coverage? 1 6 1 6 2 7
3 8 3 8 4 9 4 9 5 5

58 Branch Coverage Every decision is made true and false.
Every edge in a CFG of the program gets traversed at least once. Also known as Decision coverage All edges coverage Basis path coverage Branch is finer than statement. C1 is finer than C2 if T1  C1  (T2  C2  T2  T1) true false

59 Example Q: Number of paths needed for branch coverage? 1 6 1 6 2 7 2 7
3 8 3 8 4 9 4 9 5 5

60 Condition Coverage Make each Boolean sub-expression (called a condition) of a decision evaluated both to true and false Example: if (x > 0 || y > 0) { … } else { … } C1: x > 0, x  0 C2: y > 0, y  0 Q: How many tests?

61 Many Variances of Condition Coverage
Condition coverage is not finer than branch coverage. There are pathological cases where you can achieve condition and not branch. E.g., if (x > 0 || y > 0) { … } (x = 10, y = 0), (x = 0, y = 10): condition but not branch Under most circumstances, achieving condition achieves branch Many variances, e.g., Multiple condition Condition/decision Modified condition/decision (MC/DC)

62 CFG for Condition Coverage
One way to determine the number of paths is to break the compound conditional into atomic conditionals Suppose you were writing the CFG for the assembly language implementation of the control construct if (A AND B) then C endif (short circuit eval) (no short circuit eval) LD A LD A ; in general, lots of BZ :endif LAND B ; code for A and B LD B BZ :endif BZ :endif JSR C JSR C :endif nop :endif nop

63 AND Condition 1 2A 2B 4 3 Join 1. read (a, b);
2. if (a == 0 && b == 0) then { c  a + b; } 4. else c  a * b; paths: 1, 2A,2B,3, J 1, 2A, 2B, 4, J 1, 2A, 4, J 2A true false 2B 4 true false 3 Join

64 OR Condition 1 2A 3 2B 4 5 Join 1. read (a,b);
2. if (a == 0 || b == 0) then { c  a + b; while( c < 100) c  a + b;} Paths: 1, 2A, 3, 4, 5, 4 … J 1, 2A, 3, 4, J 1, 2A, 2B, 3, 4, 5, 4, … J 1, 2A, 2B, J 2A true false 3 2B true false 4 5 Join

65 Outline Basic concepts Black box testing White box testing
Control flow graph (CFG) Statement coverage Branch coverage Condition coverage Path coverage Def-use coverage

66 Path Coverage Every distinct path through code is executed at least once. All-paths coverage similar to exhaustive testing A path is a sequence of: Statements Branches Edges

67 Example 1,2,3 4,5 6 Test Paths: 1, 2, 3, 4, 5, J1, 7, 8, J2 Join1
1. read (x) 2. read (z) 3. if x  0 then { y  x * z; x  z; } 6. else print ‘Invalid’; 7. if z > 1 then 8. print z; 9. else print ‘Invalid’; Test Paths: 1, 2, 3, 4, 5, J1, 7, 8, J2 1, 2, 3, 4, 5, J1, 7, 9, J2 1, 2, 3, 6, J1, 7, 8, J2 1, 2, 3, 6, J1, 7, 9, J2 1,2,3 4,5 Join1 6 7 8 Join2 9 P353 Pfleeger 2nd ed 67

68 Linearly Independent Paths
It is not feasible to calculate the total number of paths. It is feasible to calculate the number of linearly independent paths: A complete path which, disregarding back tracking (such as loops), has an unique set of decisions in a program. Any path through the program that introduces at least one new edge that is not included in any other linearly independent paths. The number of linearly independent paths is the number of end-to-end paths required to touch every path segment at least once.

69 McCabe’s Cyclomatic Complexity
Software metric for the logical complexity of a program Defines the number of independent paths in the basis set of a program (basis set: maximal linearly independent set of paths). Provides the upper bound for the number of tests that must be conducted to ensure that all statements have been executed at least once. For edges (E) and nodes (N), cyclomatic complexity number V is: V = E – N + 2

70 Example: Complexity of CFG
3,4 3,4 1 1 5 5 6 2 Join Join 3 N = 1 E = 0 V = E - N + 2 = = 1 N = 3 E = 2 V = E - N + 2 = 2 – 3 + 2 = 1 N = 4 E = 4 V = E - N + 2 = = 2 N = 3 E = 3 V = E - N + 2 = = 2

71 Example 1 2,3 6 4,5 8 7 9 10 11 V = 11 – 9 + 2 = 4 Independent paths:
1-11 …-11 …-11

72 Exercise: Cyclomatic Complexity
3 4,5 6 Join 9 7,8 1,2 1,2 Join 3,4 5 6 7 1, 2 3 Join 4 5 6 1 2 3 Join 5 6

73 Linearly Independent Path Coverage
Cyclomatic-number criterion: construct a test set such that all linearly independent paths are covered. 1. read (x) 2. read (z) 3. if x  0 then { y  x * z; x  z; } 6. else print ‘Invalid’; 7. if z > 1 then 8. print z; 9. else print ‘Invalid’; Cyclomatic complexity: 3 (= 9 – 8 + 2) Test Paths: 1, 2, 3, 4, 5, J1, 7, 8, J2 1, 2, 3, 4, 5, J1, 7, 9, J2 1, 2, 3, 6, J1, 7, 8, J2, 1,2,3 4,5 Join1 6 7 8 Join2 9 P353 Pfleeger 2nd ed 73

74 Outline Basic concepts Black box testing White box testing
Control flow graph (CFG) Statement coverage Branch coverage Condition coverage Path coverage Def-use coverage

75 Data Flow Coverage Consider how variables are treated along the various paths, a.k.a. data flow analysis, e.g., definitions and uses. Many variations All-defs-uses All-defs All-uses All-C-uses/Some-P-uses All-P-uses/Some-C-uses All-P-uses * P-uses are predicate uses, e.g., in conditions; all others are C-uses.

76 Def-Use Coverage Def-use coverage: every path from every definition of every variable to every use of that definition is exercised in some test. 1. read (x); 2. read (z); 3. if x  0 then { y  x * z; x  z; } 6. else print ‘Invalid’; 7. if y > 1 then 8. print y; 9. else print ‘Invalid’; Test Path: 1, 2, 3, 4, 5, 7, 8, J D: x, z U: x 1,2,3 U: x, z D: y, x 4,5 6 U: none Join 7 U: y 8 U: y 9 U: none Join

77 Strength of Coverage Statement
Arrows point from weaker to stronger coverage. Stronger coverage requires more test cases. Branch Def-Use Condition Path

78 Limitation of Paths What they don’t tell you: Timing errors
Unanticipated error conditions User interface inconsistency (or anything else) Configuration errors Capacity errors


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