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KNOCKHARDY PUBLISHING

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1 KNOCKHARDY PUBLISHING
AN INTRODUCTION TO ELECTRODE POTENTIALS KNOCKHARDY PUBLISHING

2 KNOCKHARDY PUBLISHING
ELECTRODE POTENTIALS INTRODUCTION This Powerpoint show is one of several produced to help students understand selected topics at AS and A2 level Chemistry. It is based on the requirements of the AQA and OCR specifications but is suitable for other examination boards. Individual students may use the material at home for revision purposes or it may be used for classroom teaching if an interactive white board is available. Accompanying notes on this, and the full range of AS and A2 topics, are available from the KNOCKHARDY SCIENCE WEBSITE at... Navigation is achieved by... either clicking on the grey arrows at the foot of each page or using the left and right arrow keys on the keyboard

3 ELECTRODE POTENTIALS CONTENTS Types of half cells Cell potential
The standard hydrogen electrode Measuring electrode potentials The electrochemical series Combining half cells Cell diagrams Uses of E° values

4 Before you start it would be helpful to…
ELECTRODE POTENTIALS Before you start it would be helpful to… Recall the definitions of oxidation and reduction Be able to balance simple ionic equations Have a knowledge of simple circuitry

5 TYPES OF HALF CELL METALS IN CONTACT WITH SOLUTIONS OF THEIR IONS
These are systems involving oxidation or reduction METALS IN CONTACT WITH SOLUTIONS OF THEIR IONS Reaction Cu2+(aq) e¯ Cu(s) Electrode copper Solution Cu2+(aq) (1M) - 1M copper sulphate solution Potential V Reaction Zn2+(aq) e¯ Zn(s) Electrode zinc Solution Zn2+(aq) (1M) - 1M zinc sulphate solution Potential V

6 TYPES OF HALF CELL GASES IN CONTACT WITH SOLUTIONS OF THEIR IONS
These are systems involving oxidation or reduction GASES IN CONTACT WITH SOLUTIONS OF THEIR IONS Reaction 2H+(aq) e¯ H2(g) Electrode platinum Solution H+(aq) (1M) M HCl or 0.5M H2SO4 Gas hydrogen ( 1 atm pressure ) Potential 0.00V Reaction Cl2(aq) e¯ 2Cl¯(g) Solution Cl¯(aq) (1M) M sodium chloride Gas chorine ( 1 atm pressure ) Potential V

7 TYPES OF HALF CELL SOLUTIONS OF IONS IN TWO DIFFERENT OXIDATION STATES
These are systems involving oxidation or reduction SOLUTIONS OF IONS IN TWO DIFFERENT OXIDATION STATES Reaction Fe3+(aq) e¯ Fe2+(aq) Electrode platinum Solution Fe3+(aq) (1M) and Fe2+(aq) (1M) Potential V SOLUTIONS OF OXIDISING AGENTS IN ACID SOLUTION Reaction MnO4¯ + 8H+(aq) + 5e¯ Mn2+(aq) + 4H2O(l) Solution MnO4¯(aq) (1M) and Mn2+(aq) (1M) and H+(aq) Potential V

8 CELL POTENTIAL Each electrode / electrolyte combination has its own
half-reaction which sets up a potential difference The value is affected by ... TEMPERATURE PRESSURE OF ANY GASES SOLUTION CONCENTRATION Measurement it is impossible to measure the potential of a single electrode… BUT you can measure the potential difference between two electrodes it is measured relative to a reference cell under standard conditions The ultimate reference is the STANDARD HYDROGEN ELECTRODE. However, as it is difficult to set up, secondary standards are used.

9 THE STANDARD HYDROGEN ELECTRODE
The ultimate reference is the STANDARD HYDROGEN ELECTRODE. However as it is difficult to set up secondary standards are used. HYDROGEN GAS AT 1 ATMOSPHERE PRESSURE 298K (25°C) SOLUTION OF 1M H+(aq) e.g. 1M HCl or 0.5M H2SO4 PLATINUM ELECTRODE The standard hydrogen electrode is assigned an E° value of 0.00V.

10 MEASUREMENT OF E° VALUES
SALT BRIDGE HYDROGEN (1 ATM) PLATINUM ELECTRODE HYDROCHLORIC ACID (1M) ZINC ZINC SULPHATE (1M) In the diagram the standard hydrogen electrode is shown coupled up to a zinc half cell. The voltmeter reading gives the standard electrode potential of the zinc cell. conditions temperature 298K solution conc. 1 Molar (1 mol dm-3) with respect to ions gases 1 atmosphere pressure salt bridge filled with saturated potassium chloride solution it enables the circuit to be completed

11 THE ELECTROCHEMICAL SERIES
E° / V F2(g) + 2e¯ 2F¯(aq) MnO4¯(aq) + 8H+(aq) + 5e¯ Mn2+(aq) + 4H2O(l) Cl2(g) + 2e¯ 2Cl¯(aq) Cr2O72-(aq) + I4H+(aq) + 6e¯ 2Cr3+(aq) + 7H2O(l) Br2(l) + 2e¯ 2Br¯(aq) Ag+(aq) + e¯ Ag(s) Fe3+(aq) + e¯ Fe2+(aq) O2(g) + 2H+(aq) + 2e¯ H2O2(aq) I2(s) + 2e¯ 2I¯(aq) Cu+(aq) + e¯ Cu(s) Cu2+(aq) + 2e¯ Cu(s) Cu2+(aq) + e¯ Cu+(aq) 2H+(aq) + 2e¯ H2(g) Sn2+(aq) + 2e¯ Sn(s) Fe2+(aq) + 2e¯ Fe(s) Zn2+ (aq) + 2e¯ Zn(s) Layout If species are arranged in order of their standard electrode potentials you get a series that shows how good each substance is at gaining electrons. All equations are written as reduction processes i.e. gaining electrons A species with a higher E° value oxidise (reverses) one with a lower value REACTION MORE LIKELY TO WORK SPECIES ON LEFT ARE MORE POWERFUL OXIDATION AGENTS

12 THE ELECTROCHEMICAL SERIES
E° / V F2(g) + 2e¯ 2F¯(aq) MnO4¯(aq) + 8H+(aq) + 5e¯ Mn2+(aq) + 4H2O(l) Cl2(g) + 2e¯ 2Cl¯(aq) Cr2O72-(aq) + I4H+(aq) + 6e¯ 2Cr3+(aq) + 7H2O(l) Br2(l) + 2e¯ 2Br¯(aq) Ag+(aq) + e¯ Ag(s) Fe3+(aq) + e¯ Fe2+(aq) O2(g) + 2H+(aq) + 2e¯ H2O2(aq) I2(s) + 2e¯ 2I¯(aq) Cu+(aq) + e¯ Cu(s) Cu2+(aq) + 2e¯ Cu(s) Cu2+(aq) + e¯ Cu+(aq) 2H+(aq) + 2e¯ H2(g) Sn2+(aq) + 2e¯ Sn(s) Fe2+(aq) + 2e¯ Fe(s) Zn2+ (aq) + 2e¯ Zn(s) Application Chlorine is a more powerful oxidising agent - it has a higher E° Chlorine will get its electrons by reversing the iodine equation Cl2(g) + 2e¯ ——> 2Cl¯(aq) and I¯(aq) ——> I2(s) + 2e¯ Overall equation is Cl2(g) I¯(aq) ——> I2(s) Cl¯(aq) AN EQUATION WITH A HIGHER E° VALUE WILL REVERSE AN EQUATION WITH A LOWER VALUE

13 SECONDARY STANDARDS Why? The standard hydrogen electrode (SHE) is difficult to set up it is easier to choose a more convenient secondary standard the secondary standard has been calibrated against the SHE Calomel • the calomel electrode contains Hg2Cl2 • it has a standard electrode potential of +0.27V • is used as the LH electrode to determine the potential of an unknown • to get the value of the other cell ADD 0.27V to the measured cell potential

14 ELECTROCHEMICAL CELLS
CELLS • electrochemical cells contain two electrodes • each electrode / electrolyte combination has its own half-reaction • the electrons produced by one half reaction are available for the other • oxidation occurs at the anode • reduction occurs at the cathode. ANODE Zn(s) ——> Zn2+(aq) + 2e¯ OXIDATION CATHODE Cu2+(aq) + 2e¯ ——> Cu(s) REDUCTION The resulting cell has a potential difference (voltage) called the cell potential which depends on the difference between the two potentials It is affected by ... • current • temperature • pressure of any gases • solution concentrations

15 A TYPICAL COMBINATION OF HALF CELLS
1.10V ZINC SULPHATE (1M) COPPER SULPHATE (1M) E° = V E° = V zinc is more reactive - it dissolves to give ions Zn(s) ——> Zn2+(aq) + 2e¯ the electrons produced go round the external circuit to the copper electrode electrons are picked up by copper ions Cu2+(aq) + 2e¯ ——> Cu(s) As a result, copper is deposited overall reaction Zn(s) + Cu2+(aq) ——> Zn2+(aq) + Cu(s)

16 Zn Zn2+ Cu2+ Cu CELL DIAGRAMS
These give a diagrammatic representation of what is happening in a cell. • Place the cell with the more positive E° value on the RHS of the diagram. Cu2+(aq) + 2e¯ Cu(s) E° = V put on the RHS Zn2+(aq) + 2e¯ Zn(s) E° = V put on the LHS Zn Zn Cu2+ Cu

17 Zn Zn2+ Cu2+ Cu CELL DIAGRAMS
These give a diagrammatic representation of what is happening in a cell. • Place the cell with the more positive E° value on the RHS of the diagram. Cu2+(aq) + 2e¯ Cu(s) E° = V put on the RHS Zn2+(aq) + 2e¯ Zn(s) E° = V put on the LHS ZINC IS IN CONTACT THE SOLUTIONS A SOLUTION OF WITH A SOLUTION ARE JOINED VIA A COPPER IONS IN OF ZINC IONS SALT BRIDGE TO CONTACT WITH COPPER Zn Zn Cu2+ Cu

18 + _ Zn Zn2+ Cu2+ Cu CELL DIAGRAMS
These give a diagrammatic representation of what is happening in a cell. • Place the cell with the more positive E° value on the RHS of the diagram. Cu2+(aq) + 2e¯ Cu(s) E° = V put on the RHS Zn2+(aq) + 2e¯ Zn(s) E° = V put on the LHS • Draw as shown… the cell reaction goes from left to right • the zinc metal dissolves Zn(s) ——> Zn2+(aq) + 2e¯ OXIDATION • copper is deposited Cu2+(aq) + 2e¯ ——> Cu(s) REDUCTION • oxidation takes place at the anode • reduction at the cathode _ Zn Zn Cu2+ Cu +

19 + _ Zn Zn2+ Cu2+ Cu V CELL DIAGRAMS
These give a diagrammatic representation of what is happening in a cell. • Place the cell with the more positive E° value on the RHS of the diagram. Cu2+(aq) + 2e¯ Cu(s) E° = V put on the RHS Zn2+(aq) + 2e¯ Zn(s) E° = V put on the LHS • Draw as shown… the electrons go round the external circuit from left to right • electrons are released when zinc turns into zinc ions • the electrons produced go round the external circuit to the copper • electrons are picked up by copper ions and copper is deposited _ Zn Zn Cu2+ Cu + V

20 + _ Zn Zn2+ Cu2+ Cu V CELL DIAGRAMS
These give a diagrammatic representation of what is happening in a cell. • Place the cell with the more positive E° value on the RHS of the diagram. Cu2+(aq) + 2e¯ Cu(s) E° = V put on the RHS Zn2+(aq) + 2e¯ Zn(s) E° = V put on the LHS • Draw as shown… the cell voltage is E°(RHS) - E°(LHS) - it must be positive cell voltage = V - (-0.76V) = V _ Zn Zn Cu2+ Cu + V

21 USE OF Eo VALUES - WILL IT WORK?
E° values Can be used to predict the feasibility of redox and cell reactions In theory ANY REDOX REACTION WITH A POSITIVE E° VALUE WILL WORK In practice, it proceeds if the E° value of the reaction is greater than V An equation with a more positive E° value reverse a less positive one

22 USE OF Eo VALUES - WILL IT WORK?
An equation with a more positive E° value reverse a less positive one What happens if an Sn(s) / Sn2+(aq) and a Cu(s) / Cu2+(aq) cell are connected? Write out the equations Cu2+(aq) + 2e¯ Cu(s) ; E° = V Sn2+(aq) + 2e¯ Sn(s) ; E° = V the half reaction with the more positive E° value is more likely to work it gets the electrons by reversing the half reaction with the lower E° value therefore Cu2+(aq) ——> Cu(s) and Sn(s) ——> Sn2+(aq) the overall reaction is Cu2+(aq) Sn(s) ——> Sn2+(aq) + Cu(s) the cell voltage is the difference in E° values... (+0.34) - (-0.14) = V

23 USE OF Eo VALUES - WILL IT WORK?
An equation with a more positive E° value reverse a less positive one Will this reaction be spontaneous? Sn(s) + Cu2+(aq) ——> Sn2+(aq) + Cu(s) Write out the appropriate equations Cu2+(aq) + 2e¯ Cu(s) ; E° = V as reductions with their E° values Sn2+(aq) + 2e¯ Sn(s) ; E° = V The reaction which takes place will involve the more positive one reversing the other i.e. Cu2+(aq) ——> Cu(s) and Sn(s) ——> Sn2+(aq) The cell voltage will be the difference in E° values and will be positive (+0.34) - (- 0.14) = V If this is the equation you want then it will be spontaneous If it is the opposite equation (going the other way) it will not be spontaneous

24 USE OF Eo VALUES - WILL IT WORK?
An equation with a more positive E° value reverse a less positive one Will this reaction be spontaneous? Sn(s) + Cu2+(aq) ——> Sn2+(aq) + Cu(s) Split equation into two half equations Cu2+(aq) e¯ ——> Cu(s) Sn(s) ——> Sn2+(aq) e¯ Find the electrode potentials Cu2+(aq) + 2e¯ Cu(s) ; E° = V and the usual equations Sn2+(aq) + 2e¯ Sn(s) ; E° = V Reverse one equation and its sign Sn(s) ——> Sn2+(aq) e¯ ; E° = V Combine the two half equations Sn(s) + Cu2+(aq) ——> Sn2+(aq) + Cu(s) Add the two numerical values (+0.34V) + (+ 0.14V) = V If the value is positive the reaction will be spontaneous

25 What should you be able to do?
REVISION CHECK What should you be able to do? Recall the different types of half cells Recall the structure of the standard hydrogen electrode Recall the methods used to calculate standard electrode electrode potentials Write balanced full and half equations representing electrochemical processes Know that a reaction can be spontaneous if it has a positive E value Calculate if a reaction is feasible by finding its E value CAN YOU DO ALL OF THESE? YES NO

26 You need to go over the relevant topic(s) again
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27 Try some past paper questions
WELL DONE! Try some past paper questions

28 © 2004 JONATHAN HOPTON & KNOCKHARDY PUBLISHING
AN INTRODUCTION TO ELECTRODE POTENTIALS THE END © JONATHAN HOPTON & KNOCKHARDY PUBLISHING


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