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Mario Lintz Mario.Lintz@ucdenver.edu 303-946-5838 Organic Chemistry Mario Lintz Mario.Lintz@ucdenver.edu 303-946-5838 1.

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Presentation on theme: "Mario Lintz Mario.Lintz@ucdenver.edu 303-946-5838 Organic Chemistry Mario Lintz Mario.Lintz@ucdenver.edu 303-946-5838 1."— Presentation transcript:

1 Mario Lintz Mario.Lintz@ucdenver.edu 303-946-5838
Organic Chemistry Mario Lintz 1

2 Organic Chemistry I Functional Groups Molecular Structure Hydrocarbons
Substitution and Elimination Oxygen Containing Compounds Amines 2

3 Functional Groups List #1- Critical for the MCAT
Alkane Alkene Alkyne Alcohol Ether Amine Aldehyde Ketone Carboxylic Acid Ester Amide 3

4 Functional Groups List #2- Memorize as well
Alkyl Halogen Gem-dihalide Vic dihalide Hydroxyl Alkoxy Hemiacetal Hemiaketal Mesyl group Tosyl group Carbonyl Acetal Acyl Anhydride Aryl Benzyl Hydrazine Hydrazone Vinyl Vinylic Allyl Nitrile Epoxide Enamine Imine Nitro Nitroso 4

5 5

6 Bonds Types: Ionic: complete transfer of electrons
Covalent: shared electrons Coordinate covalent bonds- One atom provides both electrons in a shared pair. Polar covalent: unequal sharing of electrons Hydrogen Bonds: bonds between polar molecules containing H and O, N, or F 6

7 Bonds In the pi bond of an alkene, the electron pair have:
33% p character and are at a lower energy level than the electron pair in the o bond. 33% p character and are at a higher energy level than the electron pair in the o bond. 100% p character and are at a lower energy level than the electron pair in the o bond. 100% p character and are at a higher energy level than the electron pair in the o bond. 7

8 Covalent Bonds Sigma s Pi P 8

9 Covalent Bonds Sigma s Pi P Between s orbitals
Small, strong, lots of rotation Pi P 9

10 Covalent Bonds Sigma s Pi P Between s orbitals
Small, strong, lots of rotation Pi P Between p orbitals Discreet structure, weaker than sigma, no rotation 10

11 Covalent Bonds Sigma s Pi P Between s orbitals
Small, strong, lots of rotation Pi P Between p orbitals Discreet structure, weaker than sigma, no rotation Always add to sigma bonds creating a stronger bond 11

12 When albuterol I dissolved in water, which of the following hydrogen-bonded structures does NOT contribute to its water solubility? 12

13 Dipole Moments (Solely responsible for Intermolecular Attractions)
Charge distribution of bond is unequal Molecule with dipole moment = polar Molecule without dipole moment = nonpolar Possible to have nonpolar molecules with polar bonds Induced Dipoles Spontaneous formation of dipole moment in nonpolar molecule Occurs via: polar molecule, ion, or electric field Instantaneous Dipole Due to random e- movement Hydrogen Bonds Strongest dipole-dipole interaction Responsible for high BP of water London Dispersion Forces Between 2 instantaneous dipoles Responsible for phase change of nonpolar molecules 13

14 Lewis Dot Structures Rules for writing Exceptions Formal Charge
Find total # valence e- 1 e- pair = 1 bond Arrange remaining e- to satisfy duet and octet rules Exceptions Atoms containing more than an octet must come from the 3rd period, (vacant d orbital required for hybridization) Not very popular on the MCAT Formal Charge # valence e- (isolated atom) - # valence e- (lewis structure) Sum of formal charge for each atom is the total charge on the molecule (actual charge distribution depends on electronegativity) 14

15 Structural Formulas Dash Formula Condensed Formula Bond-line Formula
Fischer projection Newman projection Dash-line-wedge Ball and stick All Images courtesy of Exam Krackers 15

16 Hybridization 16

17 Hybrid Bonds -ane -ene -yne -yl Suffix C bonds Hybridization Percent
S:P Bond Angle Bond Length Bond Strength -ane -ene -yne -yl 17

18 Hybrid Bonds Percent S:P -ane C-C sp3 25:75 109.5 154 346 -ene C=C sp2
Suffix C bonds Hybridization Percent S:P Bond Angleo Bond Length (pm) Bond Strength (kJ/mol) -ane C-C sp3 25:75 109.5 154 346 -ene C=C sp2 33:66 120 134 612 -yne sp 50:50 180 835 -yl Side chain 18

19 Hybrid Bonding in Oxygen and Nitrogen
Lone pair occupies more space than N-H Causes compression of the bond angle. Bond angles are as opposed to 109.5 Oxygen- 2 sets of lone pair electrons Causes greater compression than in Nitrogen. H2O bond angles are vs 19

20 For the molecule 1,4 pentadiene, what type of hybridization is present in carbons # 1 and # 3 respectively? A) sp2, sp2 B) sp2, sp3 C) sp3, sp3 D) sp3, sp2 20

21 VSEPR valance shell electron pair repulsion Prediction of shape
Minimize electron repulsion 1. Draw the Lewis dot structure for the molecule or ion 2. Place electron pairs as far apart as possible, then large atoms, then small atoms 3. Name the molecular structure based on the position of the atoms (ignore electron pairs) 21

22 Trigonal bipyramidal, dsp3
VSEPR 1. Draw the Lewis dot structure for the molecule or ion 2. Place electron pairs as far apart as possible, then large atoms, then small atoms 3. Name the molecular structure based on the position of the atoms (ignore electron pairs) molecule Lewis structure Shape BeCl2 Linear, sp SF4 Seesaw SO3 Trigonal planar, sp2 ICl3 T shaped NO2- Bent CH4 Tetrahedral, sp3 NH3 Trigonal Pyramidal PCl5 Trigonal bipyramidal, dsp3 SF6 Octahedral, d2sp3 IF5 Square Pyramidal ICl4- Square Planar 22

23 Delocalized e- and Resonance passage 25
Resonance forms differ only in the placement of pi bond and nonbonding e- Does not suggest that the bonds alternate between positions Neither represent the actual molecule, rather the real e assignment is the intermediate of the resonant structures. The real structure is called a resonance hybrid (cannot be seen on paper) 23

24 Organic Acids and Bases
Organic Acids- Presence of positively charged H+ Two kinds present on a OH such as methyl alcohol present on a C next to a C=O such as acetone Organic Bases- Presence of lone pair e to bond to H Nitrogen containing molecules are most common Oxygen containing molecules act as bases in presence of strong acids 24

25 Stereochemistry Isomers: same elements, same proportions. Different spatial arrangements => different properties. Structural (constitutional): Different connectivity. Isobutane vs n-butane Both C4H10 Conformational (rotational): Different spatial arrangement of same molecule Chair vs. boat Gauche vs Eclispsed vs Antistaggered vs Fully Eclipsed 25

26 Stereochemistry-isomers
Stereoisomers: different 3D arrangement Enantiomers: mirror images, non-superimposable. Same physical properties (MP, BP, density, solubility, etc.) except rotation of light and reactions with other chiral compounds May function differently; e.g. thalidomide, sugars, AA Have chiral centers 26

27 Stereochemistry-isomers
Stereoisomers: different 3D arrangement Diastereomers: not mirror images (cis/trans) Different physical properties (usually), Can be separated Chiral diastereomers have opposite configurations at one or more chiral centers, but have the same configuration at others. 27

28 Stereochemistry-isomers
What kind of isomers are the two compounds below? A. Configurational diastereomers B. Enantiomers C. Constitutional isomers D. Cis -trans diastereomers 28

29 Stereochemistry-polarization of light
Excess of one enantiomer causes rotation of plane-polarized light. Right, clockwise, dextrarotary (d), or + Left, counterclockwise, levarotary (l), or – Racemic: 50:50 mixture of 2 enantiomers, no net rotation of light RELATIVE Configuration: configuration of one molecule relative to another. Two molecules have the same relative configuration about a carbon if they differ by only one substituent and the other substituents are oriented identically about the carbon. Specific rotation [a]: normalization for path length (l) and sample density (d). ocm3/g [a] = a / (l*d) 29

30 Stereochemistry-Chiral molecules passage 27
Achiral=plane or center of symmetry ABSOLUTE Configuration: physical orientation of atoms around a chiral center R and S: 1. Assign priority, 1 highest, 4 lowest H < C < O < F higher atomic #, higher priority If attachments are the same, look at the b atoms (ethyl beats methyl) 2. Orient 4 away from the observer 3. Draw a circular arrow from 1 to 2 to 3 R = clockwise S = counterclockwise This has nothing to do with the rotation of light! E and Z: Different than cis and trans Z= same side of high priority groups E=opposite side of high priority groups 30

31 IUPAC Naming Conventions
IUPAC Rules for Alkane Nomenclature 1.   Find and name the longest continuous carbon chain.  2.   Identify and name groups attached to this chain. 3.   Number the chain consecutively, starting at the end nearest a substituent group. 4.   Designate the location of each substituent group by an appropriate number and name. 5.   Assemble the name, listing groups in alphabetical order. The prefixes di, tri, tetra etc., used to designate several groups of the same kind, are not considered when alphabetizing. 31

32 Hydrocarbons # of C Root Name 1 meth 6 hex 2 eth 7 hept 3 prop 8 oct 4
but 9 non 5 pent 10 dec 32

33 Hydrocarbons Saturated: CnH(2n+2)\
Unsaturated: CnH[2(n-u+1)] ; u is the # of sites of unsaturation Primary, secondary, tertiary, and quaternary carbons Know and be able to recognize the following structures n-propyl Iso-propyl n-butyl sec-butyl iso-butyl tert-butyl 33

34 Alkanes Physical Properties:
Straight chains: MP and BP increase with length (increased van Der Waals interactions) C1-4: gas C5-17: liquid C18+: solid Branched chains: BP decreases (less surface area, fewer vDW) When compared to the straight chain analog, the straight chain will have a higher MP than the branched molecule. BUT, amongst branched molecules, the greater the branching, the higher the MP. 34

35 Alkanes-Important Reactions Very Unreactive
Combustion: Alkane + Oxygen + High energy input (fire) Products: H2O, CO2, Heat Halogenation Initiation with UV light Homolytic cleavage of diatomic halogen Yields a free radical Propagation (chain reaction mechanisms) Halogen radical removes H from alkyl Yields an alkyl radical Termination Radical bonds to wall of container or another radical Reactivity of halogens: F > Cl > Br >>> I Selectivity of halogens (How selective is the halogen in choosing a position on an alkane): I > Br > Cl > F more electronegative (Cl) means less selective (Br) Stability of free radicals: more highly substituted = more stable aryl>>>alkene> 3o > 2o > 1o >methyl 35

36 Halogenation In the halogenation of an alkane, which of the following halogens will give the greatest percent yield of a tertiary alkyl halide when reacted with 2-methylpentane in the presence of UV light. F2 Cl2 Br2 2-methylpentane will not yield a tertiary product 36

37 Cycloalkanes General formula: (CH2)n or CnH2n
As MW increases BP increases though MP fluctuates irregularly because different shapes of cycloalkanes effects the efficiency in which molecules pack together in crystals. Ring strain in cyclic compounds: Bicyclic Molecules: 37

38 Cycloalkanes Naming Find parent
Count C’s in ring vs longest chain. If # in ring is equal to or greater than chain, then name as a cycloalkane. Number the substituents and write the name Start at point of attachment and number so that subsequent substituents have the lowest # assignment If two or more different alkyl groups are present, number them by alphabetic priority If halogens are present, treat them like alkyl groups Cis vs Trans Think of a ring as having a top and bottom If two substituents both on top: cis It two substituents and 1 top, 1 bottom: trans 38

39 Cycloalkanes Ring Strain Cyclohexane
Zero for cyclohexane (All C-C-C bond angles: 111.5°) Increases as rings become smaller or larger (up to cyclononane) Cyclohexane Exist as chair and boat conformations Chair conformation preferred because it is at the lowest energy. Hydrogens occupy axial and equatorial positions. Axia (6)l- perpendicular to the ring Equatorial (6)- roughly in the plane of the ring Neither energetically favored When the ring reverses its conformation, substituents reverse their conformation Substituents favor equatorial positions because crowding occurs most often in the axial position. 39

40 Cyclohexanes In a sample of cis-1,2-dimethylcyclohexane at room temperature, the methyl groups will: Both be equatorial whenever the molecule is in the chair conformation. Both be axial whenever the molecule is in the chair conformation. Alternate between both equatorial and both axial whenever the molecule is in the chair conformation Both alternate between equatorial and axial but will never exist both axial or both equatorial at the same time 40

41 Substitutions Substitution: one functional group replaces another
Electrophile: wants electrons, has partial + charge Nucleophile: donates electrons, has partial – charge 41

42 Substitution SN1: substitution, nucleophilic, unimolecular
Rate depends only on the substrate (i.e. leaving group) R=k[reactant] Occurs when Nu has bulky side groups, stable carbocation (3o), weak Nu (good leaving group) Carbocation rearrangement Two step reaction 1. spontaneous formation of carbocation (SLOW) 2. Nucleophile attacks carbocation (chiral reactants yield racemic product mixtures) 42

43 Substitution SN2: substitution, nucleophilic, bimolecular
Rate depends on the substrate and the nucleophile R=k[Nu][E] Inversion of configuration Occurs with poor leaving groups (1o or 2o) One step reaction 1. Nu attacks the C with a partial + charge 43

44 Which of the following carbocations is the most stable?
CH3CH2CH2CH2 B. CH3CH2CH2CHCH3 C. (CH3)3C D. CH3 44

45 Benzene Undergoes substitution not addition Flat molecule
Stabilized by resonance Electron donating groups activate the ring and are ortho-para directors Electron withdrawing groups deactivate the ring and are meta directors Halogens are electron withdrawing, however, are ortho-para directors 45

46 Benzene Substituent Effects
46

47 Oxygen Containing Compounds
Alcohols Aldehydes and Ketones Carboxylic Acids Acid Derivatives Acid Chlorides Anhydrides Amides Keto Acids and Esters 47

48 Alcohols One of the most common reactions of alcohols is nucleophilic substitution. Which of the following are TRUE in regards to SN2 reactions: Inversion of configuration occurs Racemic mixture of products results Reaction rate = k [S][nucleophile] I only II only I and III only I, II, and III 48

49 Alcohols Physical Properties: Polar High MP and BP (H bonding)
More substituted = more basic (CH3)3COH: pKa = 18.00 CH3CH2OH: pKa = 16.00 CH3OH: pKa = 15.54 Electron withdrawing substituents stabilize alkoxide ion and lower pKa. Tert-butyl alcohol: pKa = 18.00 Nonafluoro-tert-butyl alcohol: pKa = 5.4 IR absorption of OH at ~3400 cm- General principles H bonding Acidity: weak relative to other O containing compounds (CH groups are e- donating = destabilize deprotonated species) Branching: lowers BP and MP 49

50 Alcohols Naming Select longest C chain containing the hydroxyl group and derive the parent name by replacing –e ending of the corresponding alkane with –ol. Number the chain beginning at the end nearest the –OH group. Number the substituents according to their position on the chain, and write the name listing the substituents in alphabetical order. 50

51 Alcohols-Oxidation & Reduction
51 Reduction

52 Alcohols-Oxidation & Reduction
Common oxidizing and reducing agents Generally for the MCAT Oxidizing agents have lots of oxygens Reducing agents have lots of hydrogens Oxidizing Agents Reducing Agents K2Cr2O7 LiAlH4 KMnO4 NaBH4 H2CrO4 H2 + Pressure O2 Br2 52

53 Reduction Synthesis of Alcohols
Reduction of aldehydes, ketones, esters, and acetates to alcohols. Accomplished using strong reducing agents such as NaBH4 and LiAlH4 Electron donating groups increase the negative charge on the carbon and make it less susceptible to nucleophilic attack. Reactivity: Aldehydes>Ketones>Esters>Acetates Only LiAlH4 is strong enough to reduce esters and acetates 53

54 Alcohols: Pinacol rearrangement
Starting with Vicinal Diol Generate ketones and aldehydes Formation of most stable carbocation Can get ring expansion or contraction 54

55 Alcohols-Protection Alcohol behaves as the nucleophile. (As is often the case) OH easily transfer H to a basic reagent, a problem in some reactions. Conversion of the OH to a removable functional group without an acidic proton protects the alcohol 55

56 56

57 Alcohols to Alkylhalides via a strong acid catalyst
R-OH + HCl  RCl + H20 Alcohol is protonated by strong acid, (it takes a strong acid to protonate an alcohol). -OH is converted to the much better leaving group, H2O Occurs readily with tertiary alcohols via treatment with HCl or HBr. Primary and secondary alcohols are more resistant to acid and are best converted via treatment with SOCl2 or PBr3 57

58 Alcohols to Alkylhalides reactions with SOCl2 and PBr3
Halogenation of alcohols via SN1 or SN2 OH is the Nu, attacking the halogenating agent It is not OH that leaves, but a much better leaving group -OSOCl or –OPBr2, which is readily expelled by backside nucleophilic substitution. Does not require strong acids (HCl, HBr) 58

59 Alcohols-preparation of mesylates and tosylates
OH is a poor leaving group, unless protonated, but most Nu are strong bases and remove such a proton Conversion to mesylates or tosylates allow for reactions with strong Nu Preparation SN1: no change of stereogenic center. Reaction SN2: inversion of configuration allow control of stereochemistry and 59

60 Alcohols: Esterification
Fischer Esterification Reaction: Alcohol + Carboxylic Acid  Ester + Water Acid Catalyzed- protonates –OH to H2O (excellent leaving group) Alcohol performs nucleophilic attack on carbonyl carbon These bonds are broken 60

61 Alcohols: Inorganic Esters passage 30
Esters with another atom in place of the carbon 1. Sulfate esters: alcohol + sulfuric acid 2. Nitrate esters: alcohol + HNO3 (e.g. nitroglycerine) 3. Phosphate esters: DNA 61

62 Upon heating 2,3-Dimethyl-2,3-butanediol with aqueous acid, which of the following products would be obtained in the greatest amount? 3,3-Dimethyl-2-butanone 2,2-Dimethyl-3-butanone 2,3-Dimethyl-3-butanone 2,3-Dimethyl-2-butanone 62

63 Heterogeneous catalyst Homogeneous catalyst Alcohol protection
In the reaction above, what is the purpose of using the 1,2-ethanediol in the first step? Heterogeneous catalyst Homogeneous catalyst Alcohol protection Oxidizing agent 63

64 In the reaction above, if the reagents in the first step were replaced with LiAlH4, what product would result? a) c) b) d) O OH OH OH OH OH OH HO 64

65 Carbonyls Carbon double bonded to Oxygen
Planar stereochemistry Partial positive charge on Carbon (susceptibility to nucleophilic attack) Aldehydes & Ketones (nucleophilic addition) Carboxylic Acids (nucleophilic substitution) Amides 65

66 Aldehydes and Ketones Physical properties:
Carbonyl group is polar Higher BP and MP than alkanes because of dipole-dipole interactions More water soluble than alkanes Trigonal planar geometry, chemistry yields racemic mixtures IR absorption of C=O at ~1600 General principles: Effects of substituents on reactivity of C=O: e- withdrawing increase the carbocation nature and make the C=O more reactive Steric hindrance: ketones are less reactive than aldehydes Acidity of alpha hydrogen: carbanions a, b unsaturated carbonyls-resonance structures 66

67 Aldehydes and Ketones Naming
Naming Aldehydes Replace terminal –e of corresponding alkane with –al. Parent chain must contain the –CHO group The –CHO carbon is C1 When –CHO is attached to a ring, the suffix carbaldehyde is used. Naming Ketones Replace terminal –e of corresponding alkane with –one. Parent chain is longest chain containing ketone Numbering begins at the end nearest the carbonyl C. 67

68 Aldehydes and Ketones- Acetal and Ketal Formation nucleophilic addition at C=O bond
68

69 Aldehydes and Ketones- Imine Formation nucleophilic addition at C=O bond
Imine R2C=NR Primary amines (RNH2) + aldehyde or ketone  R2C=NR Acid Catalyzed protonation of –OH  H2O 69

70 Aldehydes and Ketones- Enamine Formation nucleophilic addition at C=O bond
Enamine (ene + amine) R2N-CR=CR2 Secondary amine (R2N) + aldehyde or ketone  R2N-CR=CR2 Acid catalyzed protonation of –OH  H2O 70

71 Aldehydes and Ketones-reactions at adjacent positions
Haloform: trihalomethane Halogens add to ketones at the alpha position in the presence of a base or acid. Used in qualitative analysis to indicate the presence of a methyl ketone. The product, iodoform, is yellow and has a characteristic odor. 71

72 Aldehydes and Ketones-reactions at adjacent positions
Aldol (aldehyde + alcohol) condensation: Occurs at the alpha carbon Base catalyzed condensation Alkoxide ion formation (stronger than –OH, extracts H from H2O to complete aldol formation) Can use mixtures of different aldehydes and ketones 72

73 Aldehydes and Ketones-Oxidation (Aldehydes  Carboxylic acids)
Aldehydes are easy to oxidize because of the adjacent hydrogen. In other words, they are good reducing agents. Potassium dichromate (VI): orange to green Tollens’ reagent (silver mirror test): grey ppt. Prevents reactions at C=C and other acid sensitive funtional groups in acidic conditions. Fehlings or benedicts solution (copper solution): blue to red Ketones, lacking such an oxygen, are resistant to oxidation. 73

74 Aldehydes and Ketones Keto-enol Tautomerism:
Keto tautomer is preferred (alcohols are more acidic than aldehydes and ketones). 74

75 Aldehydes and Ketones Internal H bonding: 1,3-dicarbonlys
Enol tautomer is preferred (stabilized by resonance and internal H-bonding) 75

76 Guanine, the base portion of guanosine, exists as an equilibrium mixture of the keto and enol forms. Which of the following structures represents the enol form of guanine? 76

77 Aldehydes and Ketones Organometallic reagents:
Nucleophilic addition of a carbanion to an aldehyde or ketone to yield an alcohol 77

78 Acetoacetic Ester Synthesis Alkyl Halide + Acetoacetic Ester  Methyl Ketone
Use acetoacetic ester (ethyl acetoacetate) to generate substituted methyl ketones Base catalyzed extraction of α H 78

79 Aldehydes and Ketones Wolff-Kishner reduction:
Nucleophilic addition of hydrazine (H2N-NH2) Replace =O with 2 H atoms + H2O 79

80 In which of the following reactions would
the formation of an imine occur? Methylamine + propanol Methylamine + propanal Dimethylamine+ propanal Trimethylamine + propanal 80

81 In which of the following reactions would
the formation of an enamine occur? Methylamine + propanol Methylamine + propanal Dimethylamine+ propanal Trimethylamine + propanal 81

82 It contains an aldehyde It contains an alcohol
In an organic chemistry class a group of students are trying to determine the identity of an unknown compound. In the haloform reaction the reaction mixture turned yellow indicating a positive result. Which of the following is true of the unknown compound? It contains an aldehyde It contains an alcohol It contains a methyl ketone It contains a carboxylic acid 82

83 Oxygen Containing Compounds-Carboxylic Acids
Physical Properties: Acidic Trigonal planar geometry Higher BP and MP than alcohols Polarity, dimer formation in hydrogen bonding increases size and VDW interactions Solubility: small (n<5) CA are soluble, larger are less soluble because long hydrocarbon tails break up H bonding IR absorption of C=O at ~1600, OH at ~3400 General Principles: Acidity Increases with EWG (stabilize carboxylate) Acidity decreases with EDG (destabilize carboxylate) Relative reactivity Steric effects Electronic effects Strain (e.g. b-lactams: 3C, 1N ring; inhibits bacterial cell wall formation) 83

84 Carboxylic Acids Naming
Carboxylic acids derived from open chain alkanes are systematically named by replacing the terminal –e of the corresponding alkane name with –oic acid. Compounds that have a –CO2H group bonded to a ring are named using the suffix –carboxylic acid. The –CO2H group is attached to C #1 and is not itself numbered in the system. 84

85 Carboxylic Acids-important reactions
Carboxyl group reactions: Nucleophilic attack: Carboxyl groups and their derivatives undergo nucleophilic substitution. Aldehydes and Ketones undergo addition because they lack a good leaving group. Must contain a good leaving group or a substituent that can be converted to a good leaving group. 85

86 Carboxylic Acids-important reactions
Reduction: Form a primary alcohol LiAlH4 is the reducing agent Unlike oxidation, cannot isolate the aldehyde LiAlH4 CH3(CH2)6COOH CH3(CH2)6CH2OH 86

87 Carboxylic Acids-important reactions
Carboxyl group reactions: Decarboxylation: 87

88 Carboxylic Acids-important reactions
Fischer Esterification Reaction: Alcohol + Carboxylic Acid  Ester + Water Acid Catalyzed- protonates –OH to H2O (excellent leaving group) Alcohol performs nucleophilic attack on carbonyl carbon H+ These bonds are broken 88

89 Carboxylic Acids- reactions at two positions
Substitution reactions: keto reactions shown, consider enol reactions To make -> SOCl2    or PCl3 Heat, -H2O R'OH, heat, H+ - R2NH heat HO- 89

90 Carboxylic Acids- reactions at two positions passage 26
Halogenation: enol tautomer undergoes halogenation 90

91 Acid Derivatives- Acid Chlorides, Anhydrides, Amides, Esters
Physical Properties: Acid chlorides: acyl chlorides React violently with water Polar Dipole attractions (no H bonds) Higher BP and MP than alkanes, lower than alcohols Anhydrides Large, polar molecules Higher BP than alkanes, lower than alcohols 91

92 Acid Derivatives Physical Properties: Amides: Esters:
Highest BP and MP Soluble in water (H bonds) Esters: Poor to fair H bond acceptors Sparingly soluble in water Weakly basic H on alpha C weakly acidic 92

93 Acid Derivatives Naming
Acid Halides (RCOX) Identify the acyl group and then the halide Replace –ic acd with –yl, or –carboxylic acid with –carbonyl Acid Anhydrides (RCO2COR’) Symmetrical anhydrides or unsubstituted monocarboxylic acids and cyclic anhydrides of dicarboxylic acids are named by replacing the word acid with anhydride. 2 acetic acid  acetic anhydride Anhydrides derived from substituted monocarboxylic acids are named by adding the prefix –bis to the acid name. 2 chloroacetic acid  bis(chloroacetic) anhydride Unsymmetrical anhydrides- those produced from two different carboxylic acids- are named by citing the two acids alphabetically. Acetic acid + benzoic acid  acetic benzoic anhydride Amides (RCONH2) Amides with an unsubstituted –NH2 group are named by replacing the –oic acid or ic acid ending with amide, or by replacing the –carboxylic acid ending with carboxamide. Acetic acid  acetamide If the nitrogen atom is further substituted, the compound is named by first identifying the substituent groups and then the parent amide. The substituents are preceded by the letter N to identify them as being directly attached to nitrogen. Propanoic acid + methyl amine  N-Methylpropanamide Esters (RCO2R) Identify the alkyl group attached to oxygen and then the carboxylic acid. Replace the –ic acid ending with -ate 93

94 Acid Derivatives- Relative Reactivity and Reactions of Derivatives
A more reactive acid derivative can be converted to a less reactive one, but not vice versa Only esters and amides commonly found in nature. Acid halides and anhydrides react rapidly with water and do not exist in living organisms Hydrolysis- +water  carboxylic acid Alcoholysis- +alcohol  ester Aminolysis- +ammonia or amine  amide Reduction- + H-  aldehyde or alcohol Grignard- + Organometallic  ketone or alcohol 94

95 Acid Derivatives-important reactions
Preparation: replace OH Nucleophilic Substitution: 95

96 Acid Derivatives Hoffman Degredation
Hoffman degradation (rearrangement) of amides; migration of an aryl group 1° Amides + Strong basic Br or Cl soln  1° Amines + CO2 96

97 Acid Derivatives Transesterification
Transesterification: exchange alkoxyl group with ester of another alcohol Alcohol + Ester  Different Alcohol + Different Ester 97

98 Acid Derivatives- Saponification
Saponification- ester hydrolysis in basic solutions 98

99 Acid Derivatives- Hydrolysis of Amides passage 33
Acid or base catalyzed 99

100 Acid Derivatives Strain (e.g., β-lactams)
Lactams- cyclic amides Although amides are most stable acid derivative, β-lactams are highly reactive due to ring strain. Subject to nuclephilic attack. Found in several types of antibiotics Inhibits bacterial cell wall formation. 100

101 Keto-Acids and Esters Keto acids contain a ketone and a carboxyl group (alpha and beta) Amino acids degraded to alpha keto acids and then go into the TCA Esters have distinctive odors and are used as artificial flavors and fragrances Beta-keto esters have an acidic alpha hydrogen Consider keto-enol tautomerism Naming Esters Esters are named by first determining the alkyl group attached to the oxygen and then the carboxylic acid from which the ester is derived. EX: Methyl Propanoate is derived from propanoic acid and a methyl group 101

102 Keto Acids and Esters- important reactions
Decarboxylation Acetoacetic ester synthesis: see aldehydes and ketones 102

103 Amines Important functions in amino acids, nucleotides, neurotransmitters 1o, 2o, 3o, 4o based on how many carbons bonded to Can be chiral, rarely have 4 side groups 103

104 Amines Important functions in amino acids, nucleotides, neurotransmitters 1o, 2o, 3o, 4o based on how many carbons bonded to Can be chiral, rarely have 4 side groups Physical properties: Polar Similar reactivity to alcohols Can H bond, but weaker H bond than alcohols MP and BP higher than alkanes, lower than alcohols IR absorption: 104

105 Amines Important functions in amino acids, nucleotides, neurotransmitters 1o, 2o, 3o, 4o based on how many carbons bonded to Can be chiral, rarely have 4 side groups Physical properties: Polar Similar reactivity to alcohols Can H bond, but weaker H bond than alcohols MP and BP higher than alkanes, lower than alcohols IR absorption: General principles: Lewis bases when they have a lone electron pair NR3 > NR2 > NR > NH3 (least basic) Stabilize adjacent carbocations and carbanions Effect of substituents on basicity of aromatic amines: Electron withdrawing are less basic Electron donating are more basic 105

106 Amines-major reactions
Amines are basic and fairly nucleophilic Amide formation: proteins 106

107 Amines-major reactions
Reactions with nitrous acid (HONO): Distinguishes primary, secondary, and tertiary Primary: burst of colorless, odorless N2 gas Secondary: yellow oil, nitrosamine-powerful carcinogen Tertiary: colorless solution, amine forms an ion, e.g. (CH3)3NH+ 107

108 Amines- Alkylation Reaction with 1° alkyl halide
 Alkylation: SN2 with amine as the nucleophile and alkyl halides as the electrophile Reaction with 1° alkyl halide Alkylation of 1° and 2° are difficult to control and often lead to mixtures of products Alkylation of 3° amines yield quaternary ammonium salts 108

109 Amines- Hoffman Elimination
Elimination of amine as a quaternary ammonium salt to yield an alkene. Does not follow Zaitsev’s rule. Less highly substituted alkene predominates 109

110 For Next Time… Last Slide (Hooray!!!!)
Functional Group Quiz Spectra Separations and Purifications Biological Molecules Carbohydrates Amino acids and proteins Lipids Phophorous containing compounds 110


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